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Mirrors > Home > NFE Home > Th. List > axext4 | GIF version |
Description: A bidirectional version of Extensionality. Although this theorem "looks" like it is just a definition of equality, it requires the Axiom of Extensionality for its proof under our axiomatization. See the comments for ax-ext 2334 and df-cleq 2346. (Contributed by NM, 14-Nov-2008.) |
Ref | Expression |
---|---|
axext4 | ⊢ (x = y ↔ ∀z(z ∈ x ↔ z ∈ y)) |
Step | Hyp | Ref | Expression |
---|---|---|---|
1 | elequ2 1715 | . . 3 ⊢ (x = y → (z ∈ x ↔ z ∈ y)) | |
2 | 1 | alrimiv 1631 | . 2 ⊢ (x = y → ∀z(z ∈ x ↔ z ∈ y)) |
3 | axext3 2336 | . 2 ⊢ (∀z(z ∈ x ↔ z ∈ y) → x = y) | |
4 | 2, 3 | impbii 180 | 1 ⊢ (x = y ↔ ∀z(z ∈ x ↔ z ∈ y)) |
Colors of variables: wff setvar class |
Syntax hints: ↔ wb 176 ∀wal 1540 = wceq 1642 ∈ wcel 1710 |
This theorem was proved from axioms: ax-mp 5 ax-1 6 ax-2 7 ax-3 8 ax-gen 1546 ax-5 1557 ax-17 1616 ax-9 1654 ax-8 1675 ax-14 1714 ax-6 1729 ax-7 1734 ax-11 1746 ax-12 1925 ax-ext 2334 |
This theorem depends on definitions: df-bi 177 df-an 360 df-tru 1319 df-ex 1542 df-nf 1545 |
This theorem is referenced by: (None) |
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