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| Mirrors > Home > NFE Home > Th. List > equvin | GIF version | ||
| Description: A variable introduction law for equality. Lemma 15 of [Monk2] p. 109. (Contributed by NM, 5-Aug-1993.) | 
| Ref | Expression | 
|---|---|
| equvin | ⊢ (x = y ↔ ∃z(x = z ∧ z = y)) | 
| Step | Hyp | Ref | Expression | 
|---|---|---|---|
| 1 | equvini 1987 | . 2 ⊢ (x = y → ∃z(x = z ∧ z = y)) | |
| 2 | equtr 1682 | . . . 4 ⊢ (x = z → (z = y → x = y)) | |
| 3 | 2 | imp 418 | . . 3 ⊢ ((x = z ∧ z = y) → x = y) | 
| 4 | 3 | exlimiv 1634 | . 2 ⊢ (∃z(x = z ∧ z = y) → x = y) | 
| 5 | 1, 4 | impbii 180 | 1 ⊢ (x = y ↔ ∃z(x = z ∧ z = y)) | 
| Colors of variables: wff setvar class | 
| Syntax hints: ↔ wb 176 ∧ wa 358 ∃wex 1541 | 
| This theorem was proved from axioms: ax-mp 5 ax-1 6 ax-2 7 ax-3 8 ax-gen 1546 ax-5 1557 ax-17 1616 ax-9 1654 ax-8 1675 ax-6 1729 ax-7 1734 ax-11 1746 ax-12 1925 | 
| This theorem depends on definitions: df-bi 177 df-or 359 df-an 360 df-tru 1319 df-ex 1542 df-nf 1545 | 
| This theorem is referenced by: (None) | 
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