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Theorem nic-dfim 1434
Description: Define implication in terms of 'nand'. Analogous to ((φ ⊼ (ψ ⊼ ψ)) ↔ (φ → ψ)). In a pure (standalone) treatment of Nicod's axiom, this theorem would be changed to a definition ($a statement). (Contributed by NM, 11-Dec-2008.) (Proof modification is discouraged.) (New usage is discouraged.)
Assertion
Ref Expression
nic-dfim ⊢ (((φ ⊼ (ψ ⊼ ψ)) ⊼ (φ → ψ)) ⊼ (((φ ⊼ (ψ ⊼ ψ)) ⊼ (φ ⊼ (ψ ⊼ ψ))) ⊼ ((φ → ψ) ⊼ (φ → ψ))))

Proof of Theorem nic-dfim
StepHypRef Expression
1 nanim 1292 . . 3 ⊢ ((φ → ψ) ↔ (φ ⊼ (ψ ⊼ ψ)))
21bicomi 193 . 2 ⊢ ((φ ⊼ (ψ ⊼ ψ)) ↔ (φ → ψ))
3 nanbi 1294 . 2 ⊢ (((φ ⊼ (ψ ⊼ ψ)) ↔ (φ → ψ)) ↔ (((φ ⊼ (ψ ⊼ ψ)) ⊼ (φ → ψ)) ⊼ (((φ ⊼ (ψ ⊼ ψ)) ⊼ (φ ⊼ (ψ ⊼ ψ))) ⊼ ((φ → ψ) ⊼ (φ → ψ)))))
42, 3mpbi 199 1 ⊢ (((φ ⊼ (ψ ⊼ ψ)) ⊼ (φ → ψ)) ⊼ (((φ ⊼ (ψ ⊼ ψ)) ⊼ (φ ⊼ (ψ ⊼ ψ))) ⊼ ((φ → ψ) ⊼ (φ → ψ))))
Colors of variables:    wff setvar class
This proof depends on syntax axioms:   → wi 4   ↔ wb 176   ⊼ wnan 1287
This proof depends on axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8
This proof depends on definitions:  df-bi 177  df-or 359  df-an 360  df-nan 1288
This theorem is used by:  nic-stdmp  1455  nic-luk1  1456  nic-luk2  1457  nic-luk3  1458
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