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Mirrors > Home > QLE Home > Th. List > i3ancom | GIF version |
Description: Commutative law for disjunction with Kalmbach implication. (Contributed by NM, 7-Nov-1997.) |
Ref | Expression |
---|---|
i3ancom | ((a ∩ b) →3 (b ∩ a)) = 1 |
Step | Hyp | Ref | Expression |
---|---|---|---|
1 | i3id 251 | . 2 ((b ∩ a) →3 (b ∩ a)) = 1 | |
2 | ancom 74 | . . . 4 (b ∩ a) = (a ∩ b) | |
3 | 2 | ri3 253 | . . 3 ((b ∩ a) →3 (b ∩ a)) = ((a ∩ b) →3 (b ∩ a)) |
4 | 3 | bi1 118 | . 2 (((b ∩ a) →3 (b ∩ a)) ≡ ((a ∩ b) →3 (b ∩ a))) = 1 |
5 | 1, 4 | wwbmp 205 | 1 ((a ∩ b) →3 (b ∩ a)) = 1 |
Colors of variables: term |
Syntax hints: = wb 1 ∩ wa 7 1wt 8 →3 wi3 14 |
This theorem was proved from axioms: ax-a1 30 ax-a2 31 ax-a4 33 ax-a5 34 ax-r1 35 ax-r2 36 ax-r4 37 ax-r5 38 |
This theorem depends on definitions: df-b 39 df-a 40 df-t 41 df-f 42 df-i3 46 |
This theorem is referenced by: (None) |
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