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| Mirrors > Home > QLE Home > Th. List > u1lem9ab | GIF version | ||
| Description: Lemma used in study of orthoarguesian law. (Contributed by NM, 27-Dec-1998.) |
| Ref | Expression |
|---|---|
| u1lem9ab | (a⊥ →1 b)⊥ ≤ (a →1 b) |
| Step | Hyp | Ref | Expression |
|---|---|---|---|
| 1 | u1lem9a 777 | . 2 (a⊥ →1 b)⊥ ≤ a⊥ | |
| 2 | u1lem9b 778 | . 2 a⊥ ≤ (a →1 b) | |
| 3 | 1, 2 | letr 137 | 1 (a⊥ →1 b)⊥ ≤ (a →1 b) |
| Colors of variables: term |
| Syntax hints: ≤ wle 2 ⊥ wn 4 →1 wi1 12 |
| This theorem was proved from axioms: ax-a1 30 ax-a2 31 ax-a3 32 ax-a5 34 ax-r1 35 ax-r2 36 ax-r4 37 ax-r5 38 |
| This theorem depends on definitions: df-a 40 df-i1 44 df-le1 130 df-le2 131 |
| This theorem is referenced by: 3vcom 813 oa3-u1 991 oa3-u2 992 |
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