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Theorem u2lem7 773
Description: Lemma for unified implication study. (Contributed by NM, 24-Dec-1997.)
Assertion
Ref Expression
u2lem7 (a →2 (a⊥ →2 b)) = (((a ∩ b⊥ ) ∪ (a⊥ ∩ b⊥ )) ∪ b)

Proof of Theorem u2lem7
StepHypRef Expression
1 df-i2 45 . 2 (a →2 (a⊥ →2 b)) = ((a⊥ →2 b) ∪ (a⊥ ∩ (a⊥ →2 b)⊥ ))
2 df-i2 45 . . . . 5 (a⊥ →2 b) = (b ∪ (a⊥ ⊥ ∩ b⊥ ))
3 ax-a1 30 . . . . . . . 8 a = a⊥ ⊥
43ax-r1 35 . . . . . . 7 a⊥ ⊥ = a
54ran 78 . . . . . 6 (a⊥ ⊥ ∩ b⊥ ) = (a ∩ b⊥ )
65lor 70 . . . . 5 (b ∪ (a⊥ ⊥ ∩ b⊥ )) = (b ∪ (a ∩ b⊥ ))
72, 6ax-r2 36 . . . 4 (a⊥ →2 b) = (b ∪ (a ∩ b⊥ ))
8 ancom 74 . . . . 5 (a⊥ ∩ (a⊥ →2 b)⊥ ) = ((a⊥ →2 b)⊥ ∩ a⊥ )
9 u2lemnaa 641 . . . . 5 ((a⊥ →2 b)⊥ ∩ a⊥ ) = (a⊥ ∩ b⊥ )
108, 9ax-r2 36 . . . 4 (a⊥ ∩ (a⊥ →2 b)⊥ ) = (a⊥ ∩ b⊥ )
117, 102or 72 . . 3 ((a⊥ →2 b) ∪ (a⊥ ∩ (a⊥ →2 b)⊥ )) = ((b ∪ (a ∩ b⊥ )) ∪ (a⊥ ∩ b⊥ ))
12 ax-a3 32 . . . 4 ((b ∪ (a ∩ b⊥ )) ∪ (a⊥ ∩ b⊥ )) = (b ∪ ((a ∩ b⊥ ) ∪ (a⊥ ∩ b⊥ )))
13 ax-a2 31 . . . 4 (b ∪ ((a ∩ b⊥ ) ∪ (a⊥ ∩ b⊥ ))) = (((a ∩ b⊥ ) ∪ (a⊥ ∩ b⊥ )) ∪ b)
1412, 13ax-r2 36 . . 3 ((b ∪ (a ∩ b⊥ )) ∪ (a⊥ ∩ b⊥ )) = (((a ∩ b⊥ ) ∪ (a⊥ ∩ b⊥ )) ∪ b)
1511, 14ax-r2 36 . 2 ((a⊥ →2 b) ∪ (a⊥ ∩ (a⊥ →2 b)⊥ )) = (((a ∩ b⊥ ) ∪ (a⊥ ∩ b⊥ )) ∪ b)
161, 15ax-r2 36 1 (a →2 (a⊥ →2 b)) = (((a ∩ b⊥ ) ∪ (a⊥ ∩ b⊥ )) ∪ b)
Colors of variables:    term
This proof depends on syntax axioms:   = wb 1  ⊥ wn 4   ∪ wo 6   ∩ wa 7   →2 wi2 13
This proof depends on axioms:  ax-a1 30  ax-a2 31  ax-a3 32  ax-a5 34  ax-r1 35  ax-r2 36  ax-r4 37  ax-r5 38
This proof depends on definitions:  df-a 40  df-i2 45  df-le1 130  df-le2 131
This theorem is used by:  u2lem7n  775  u2lem8  782
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