Theorem imdistand 445

Description: Distribution of implication with conjunction (deduction form). (Contributed by NM, 27-Aug-2004.)

Hypothesis

Ref	Expression
imdistand.1	|- ( ph -> ( ps -> ( ch -> th ) ) )

Assertion

Ref	Expression
imdistand	|- ( ph -> ( ( ps /\ ch ) -> ( ps /\ th ) ) )

Proof of Theorem imdistand

Step	Hyp	Ref	Expression
1		imdistand.1	. 2 |- ( ph -> ( ps -> ( ch -> th ) ) )
2		imdistan 442	. 2 |- ( ( ps -> ( ch -> th ) ) <-> ( ( ps /\ ch ) -> ( ps /\ th ) ) )
3	1, 2	sylib 121	1 |- ( ph -> ( ( ps /\ ch ) -> ( ps /\ th ) ) )

Syntax hints:   -> wi 4   /\ wa 103

This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-ia1 105  ax-ia2 106  ax-ia3 107

This theorem depends on definitions:  df-bi 116

This theorem is referenced by:  imdistanda  446  pm5.32d  447  a2and  553  fconstfvm  5714  lbzbi  9575