Theorem imdistanda 452

Description: Distribution of implication with conjunction (deduction version with conjoined antecedent). (Contributed by Jeff Madsen, 19-Jun-2011.)

Hypothesis

Ref	Expression
imdistanda.1	|- ( ( ph /\ ps ) -> ( ch -> th ) )

Assertion

Ref	Expression
imdistanda	|- ( ph -> ( ( ps /\ ch ) -> ( ps /\ th ) ) )

Proof of Theorem imdistanda

Step	Hyp	Ref	Expression
1		imdistanda.1	. . 3 |- ( ( ph /\ ps ) -> ( ch -> th ) )
2	1	ex 115	. 2 |- ( ph -> ( ps -> ( ch -> th ) ) )
3	2	imdistand 451	1 |- ( ph -> ( ( ps /\ ch ) -> ( ps /\ th ) ) )

This proof depends on syntax axioms:   -> wi 4   /\ wa 104

This proof depends on axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-ia1 106  ax-ia2 107  ax-ia3 108

This proof depends on definitions:  df-bi 117

This theorem is used by:  fzind  9763  uzss  9945  exbtwnzlemshrink  10685  rebtwn2zlemshrink  10690  cau3lem  11882  dvdsrvald  14402  dvdsrex  14407  iscnp4  15321  cnntr  15328