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| Mirrors > Home > ILE Home > Th. List > nfbidf | Unicode version | ||
| Description: An equality theorem for effectively not free. (Contributed by Mario Carneiro, 4-Oct-2016.) | 
| Ref | Expression | 
|---|---|
| nfbidf.1 | 
 | 
| nfbidf.2 | 
 | 
| Ref | Expression | 
|---|---|
| nfbidf | 
 | 
| Step | Hyp | Ref | Expression | 
|---|---|---|---|
| 1 | nfbidf.1 | 
. . . 4
 | |
| 2 | 1 | nfri 1533 | 
. . 3
 | 
| 3 | nfbidf.2 | 
. . . 4
 | |
| 4 | 2, 3 | albidh 1494 | 
. . . 4
 | 
| 5 | 3, 4 | imbi12d 234 | 
. . 3
 | 
| 6 | 2, 5 | albidh 1494 | 
. 2
 | 
| 7 | df-nf 1475 | 
. 2
 | |
| 8 | df-nf 1475 | 
. 2
 | |
| 9 | 6, 7, 8 | 3bitr4g 223 | 
1
 | 
| Colors of variables: wff set class | 
| Syntax hints:     | 
| This theorem was proved from axioms: ax-mp 5 ax-1 6 ax-2 7 ax-ia1 106 ax-ia2 107 ax-ia3 108 ax-5 1461 ax-gen 1463 ax-4 1524 | 
| This theorem depends on definitions: df-bi 117 df-nf 1475 | 
| This theorem is referenced by: dvelimdf 2035 nfcjust 2327 nfceqdf 2338 nfabdw 2358 | 
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