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Mirrors > Home > ILE Home > Th. List > equtrr | GIF version |
Description: A transitive law for equality. Lemma L17 in [Megill] p. 446 (p. 14 of the preprint). (Contributed by NM, 23-Aug-1993.) |
Ref | Expression |
---|---|
equtrr | ⊢ (𝑥 = 𝑦 → (𝑧 = 𝑥 → 𝑧 = 𝑦)) |
Step | Hyp | Ref | Expression |
---|---|---|---|
1 | equtr 1666 | . 2 ⊢ (𝑧 = 𝑥 → (𝑥 = 𝑦 → 𝑧 = 𝑦)) | |
2 | 1 | com12 30 | 1 ⊢ (𝑥 = 𝑦 → (𝑧 = 𝑥 → 𝑧 = 𝑦)) |
Colors of variables: wff set class |
Syntax hints: → wi 4 |
This theorem was proved from axioms: ax-1 5 ax-2 6 ax-mp 7 ax-ia1 105 ax-gen 1406 ax-ie2 1451 ax-8 1463 ax-17 1487 ax-i9 1491 |
This theorem depends on definitions: df-bi 116 |
This theorem is referenced by: equtr2 1668 equequ2 1670 |
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