Theorem exan 1693

Description: Place a conjunct in the scope of an existential quantifier. (Contributed by NM, 18-Aug-1993.) (Proof shortened by Andrew Salmon, 25-May-2011.)

Hypothesis

Ref	Expression
exan.1	⊢ (∃𝑥𝜑 ∧ 𝜓)

Assertion

Ref	Expression
exan	⊢ ∃𝑥(𝜑 ∧ 𝜓)

Proof of Theorem exan

Step	Hyp	Ref	Expression
1		hbe1 1495	. . . 4 ⊢ (∃𝑥𝜑 → ∀𝑥∃𝑥𝜑)
2	1	19.28h 1562	. . 3 ⊢ (∀𝑥(∃𝑥𝜑 ∧ 𝜓) ↔ (∃𝑥𝜑 ∧ ∀𝑥𝜓))
3		exan.1	. . 3 ⊢ (∃𝑥𝜑 ∧ 𝜓)
4	2, 3	mpgbi 1452	. 2 ⊢ (∃𝑥𝜑 ∧ ∀𝑥𝜓)
5		19.29r 1621	. 2 ⊢ ((∃𝑥𝜑 ∧ ∀𝑥𝜓) → ∃𝑥(𝜑 ∧ 𝜓))
6	4, 5	ax-mp 5	1 ⊢ ∃𝑥(𝜑 ∧ 𝜓)

Syntax hints:   ∧ wa 104  ∀wal 1351  ∃wex 1492

This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-ia1 106  ax-ia2 107  ax-ia3 108  ax-5 1447  ax-gen 1449  ax-ie1 1493  ax-ie2 1494  ax-4 1510  ax-ial 1534

This theorem depends on definitions:  df-bi 117

This theorem is referenced by:  bm1.3ii  4126  bdbm1.3ii  14728