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Theorem exan 1671
Description: Place a conjunct in the scope of an existential quantifier. (Contributed by NM, 18-Aug-1993.) (Proof shortened by Andrew Salmon, 25-May-2011.)
Hypothesis
Ref Expression
exan.1 (∃𝑥𝜑𝜓)
Assertion
Ref Expression
exan 𝑥(𝜑𝜓)

Proof of Theorem exan
StepHypRef Expression
1 hbe1 1471 . . . 4 (∃𝑥𝜑 → ∀𝑥𝑥𝜑)
2119.28h 1541 . . 3 (∀𝑥(∃𝑥𝜑𝜓) ↔ (∃𝑥𝜑 ∧ ∀𝑥𝜓))
3 exan.1 . . 3 (∃𝑥𝜑𝜓)
42, 3mpgbi 1428 . 2 (∃𝑥𝜑 ∧ ∀𝑥𝜓)
5 19.29r 1600 . 2 ((∃𝑥𝜑 ∧ ∀𝑥𝜓) → ∃𝑥(𝜑𝜓))
64, 5ax-mp 5 1 𝑥(𝜑𝜓)
Colors of variables: wff set class
Syntax hints:  wa 103  wal 1329  wex 1468
This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-ia1 105  ax-ia2 106  ax-ia3 107  ax-5 1423  ax-gen 1425  ax-ie1 1469  ax-ie2 1470  ax-4 1487  ax-ial 1514
This theorem depends on definitions:  df-bi 116
This theorem is referenced by:  bm1.3ii  4044  bdbm1.3ii  13078
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