Theorem bj-substw 37164

Description: Weak form of the LHS of bj-substax12 37163 proved from the core axiom schemes. Compare ax12w 2166. (Contributed by BJ, 26-May-2024.) (Proof modification is discouraged.)

Hypothesis

Ref	Expression
bj-substw.is	⊢ (𝑥 = 𝑡 → (𝜑 ↔ 𝜓))

Assertion

Ref	Expression
bj-substw	⊢ (∃𝑥(𝑥 = 𝑡 ∧ 𝜑) → ∀𝑥(𝑥 = 𝑡 → 𝜑))

Distinct variable group:   𝜓,𝑥

Allowed substitution hints:   𝜑(𝑥,𝑡)   𝜓(𝑡)

Proof of Theorem bj-substw

Step	Hyp	Ref	Expression
1		bj-substw.is	. . . . 5 ⊢ (𝑥 = 𝑡 → (𝜑 ↔ 𝜓))
2	1	pm5.32i 582	. . . 4 ⊢ ((𝑥 = 𝑡 ∧ 𝜑) ↔ (𝑥 = 𝑡 ∧ 𝜓))
3	2	exbii 1867	. . 3 ⊢ (∃𝑥(𝑥 = 𝑡 ∧ 𝜑) ↔ ∃𝑥(𝑥 = 𝑡 ∧ 𝜓))
4		19.41v 1968	. . 3 ⊢ (∃𝑥(𝑥 = 𝑡 ∧ 𝜓) ↔ (∃𝑥 𝑥 = 𝑡 ∧ 𝜓))
5	3, 4	bitri 277	. 2 ⊢ (∃𝑥(𝑥 = 𝑡 ∧ 𝜑) ↔ (∃𝑥 𝑥 = 𝑡 ∧ 𝜓))
6	1	biimprcd 252	. . 3 ⊢ (𝜓 → (𝑥 = 𝑡 → 𝜑))
7	6	alrimiv 1946	. 2 ⊢ (𝜓 → ∀𝑥(𝑥 = 𝑡 → 𝜑))
8	5, 7	simplbiim 512	1 ⊢ (∃𝑥(𝑥 = 𝑡 ∧ 𝜑) → ∀𝑥(𝑥 = 𝑡 → 𝜑))

Syntax hints:   → wi 4   ↔ wb 208   ∧ wa 399  ∀wal 1557  ∃wex 1798

This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1814  ax-4 1828  ax-5 1929

This theorem depends on definitions:  df-bi 209  df-an 400  df-ex 1799

This theorem is referenced by: (None)