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Theorem cbv3v2 2280
Description: Version of cbv3 2432 with two disjoint variable conditions, which does not require ax-11 2195 nor ax-13 2407. (Contributed by BJ, 24-Jun-2019.) (Proof shortened by Wolf Lammen, 30-Aug-2021.)
Hypotheses
Ref Expression
cbv3v2.nf 𝑥𝜓
cbv3v2.1 (𝑥 = 𝑦 → (𝜑𝜓))
Assertion
Ref Expression
cbv3v2 (∀𝑥𝜑 → ∀𝑦𝜓)
Distinct variable groups:   𝑥,𝑦   𝜑,𝑦
Allowed substitution hints:   𝜑(𝑥)   𝜓(𝑥, 𝑦)

Proof of Theorem cbv3v2
StepHypRef Expression
1 cbv3v2.nf . . 3 𝑥𝜓
2 cbv3v2.1 . . 3 (𝑥 = 𝑦 → (𝜑𝜓))
31, 2spimfv 2278 . 2 (∀𝑥𝜑𝜓)
43alrimiv 1960 1 (∀𝑥𝜑 → ∀𝑦𝜓)
Colors of variables:    wff setvar class
This proof depends on syntax axioms:  wi 4  wal 1568  wnf 1816
This proof depends on axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1828  ax-4 1842  ax-5 1943  ax-6 2000  ax-7 2041  ax-12 2216
This proof depends on definitions:  df-bi 210  df-ex 1813  df-nf 1817
This theorem is used by:  bj-cbv3hv2  37471
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