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Theorem cbv3v2 2281
Description: Version of cbv3 2429 with two disjoint variable conditions, which does not require ax-11 2197 nor ax-13 2404. (Contributed by BJ, 24-Jun-2019.) (Proof shortened by Wolf Lammen, 30-Aug-2021.)
Hypotheses
Ref Expression
cbv3v2.nf Ⅎ𝑥𝜓
cbv3v2.1 (𝑥 = 𝑦 → (𝜑 → 𝜓))
Assertion
Ref Expression
cbv3v2 (∀𝑥𝜑 → ∀𝑦𝜓)
Distinct variable groups:   𝑥,𝑦   𝜑,𝑦
Allowed substitution hints:   𝜑(𝑥)   𝜓(𝑥, 𝑦)

Proof of Theorem cbv3v2
StepHypRef Expression
1 cbv3v2.nf . . 3 Ⅎ𝑥𝜓
2 cbv3v2.1 . . 3 (𝑥 = 𝑦 → (𝜑 → 𝜓))
31, 2spimfv 2279 . 2 (∀𝑥𝜑 → 𝜓)
43alrimiv 1962 1 (∀𝑥𝜑 → ∀𝑦𝜓)
Colors of variables:    wff setvar class
This proof depends on syntax axioms:   → wi 4  ∀wal 1568  Ⅎwnf 1816
This proof depends on axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1828  ax-4 1842  ax-5 1945  ax-6 2002  ax-7 2043  ax-12 2216
This proof depends on definitions:  df-bi 210  df-ex 1813  df-nf 1817
This theorem is used by:  bj-cbv3hv2  37922
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