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Theorem cbv3v2 2277
Description: Version of cbv3 2426 with two disjoint variable conditions, which does not require ax-11 2193 nor ax-13 2401. (Contributed by BJ, 24-Jun-2019.) (Proof shortened by Wolf Lammen, 30-Aug-2021.)
Hypotheses
Ref Expression
cbv3v2.nf Ⅎ𝑥𝜓
cbv3v2.1 (𝑥 = 𝑦 → (𝜑 → 𝜓))
Assertion
Ref Expression
cbv3v2 (∀𝑥𝜑 → ∀𝑦𝜓)
Distinct variable groups:   𝑥,𝑦   𝜑,𝑦
Allowed substitution hints:   𝜑(𝑥)   𝜓(𝑥, 𝑦)

Proof of Theorem cbv3v2
StepHypRef Expression
1 cbv3v2.nf . . 3 Ⅎ𝑥𝜓
2 cbv3v2.1 . . 3 (𝑥 = 𝑦 → (𝜑 → 𝜓))
31, 2spimfv 2275 . 2 (∀𝑥𝜑 → 𝜓)
43alrimiv 1959 1 (∀𝑥𝜑 → ∀𝑦𝜓)
Colors of variables:    wff setvar class
This proof depends on syntax axioms:   → wi 4  ∀wal 1567  Ⅎwnf 1815
This proof depends on axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1827  ax-4 1841  ax-5 1942  ax-6 1999  ax-7 2040  ax-12 2212
This proof depends on definitions:  df-bi 210  df-ex 1812  df-nf 1816
This theorem is used by:  bj-cbv3hv2  37800
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