Theorem eqeq12OLD 2758

Description: Obsolete version of eqeq12 2756 as of 23-Oct-2024. (Contributed by NM, 3-Aug-1994.) (New usage is discouraged.) (Proof modification is discouraged.)

Assertion

Ref	Expression
eqeq12OLD	⊢ ((𝐴 = 𝐵 ∧ 𝐶 = 𝐷) → (𝐴 = 𝐶 ↔ 𝐵 = 𝐷))

Proof of Theorem eqeq12OLD

Step	Hyp	Ref	Expression
1		eqeq1 2743	. 2 ⊢ (𝐴 = 𝐵 → (𝐴 = 𝐶 ↔ 𝐵 = 𝐶))
2		eqeq2 2751	. 2 ⊢ (𝐶 = 𝐷 → (𝐵 = 𝐶 ↔ 𝐵 = 𝐷))
3	1, 2	sylan9bb 509	1 ⊢ ((𝐴 = 𝐵 ∧ 𝐶 = 𝐷) → (𝐴 = 𝐶 ↔ 𝐵 = 𝐷))

Syntax hints:   → wi 4   ↔ wb 205   ∧ wa 395   = wceq 1541

This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1801  ax-4 1815  ax-5 1916  ax-6 1974  ax-7 2014  ax-9 2119  ax-ext 2710

This theorem depends on definitions:  df-bi 206  df-an 396  df-ex 1786  df-cleq 2731

This theorem is referenced by:  eqeq12dOLD  2759