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Theorem pm2.24nel 3074
Description: A contradiction concerning membership implies anything. (Contributed by Alexander van der Vekens, 25-Jan-2018.)
Assertion
Ref Expression
pm2.24nel (𝐴𝐵 → (𝐴𝐵𝜑))

Proof of Theorem pm2.24nel
StepHypRef Expression
1 df-nel 3062 . 2 (𝐴𝐵 ↔ ¬ 𝐴𝐵)
2 pm2.24 125 . 2 (𝐴𝐵 → (¬ 𝐴𝐵𝜑))
31, 2biimtrid 245 1 (𝐴𝐵 → (𝐴𝐵𝜑))
Colors of variables:    wff setvar class
This proof depends on syntax axioms:  ¬ wn 3  wi 4  wcel 2145  wnel 3061
This proof depends on axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8
This proof depends on definitions:  df-bi 210  df-nel 3062
This theorem is used by:  xnn0lenn0nn0  13297  ge2nprmge4  16792  afv2orxorb  48116  ppivalnnnprm  48531  isubgr3stgrlem6  48887
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