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| Mirrors > Home > MPE Home > Th. List > pm2.24nel | Structured version Visualization version GIF version | ||
| Description: A contradiction concerning membership implies anything. (Contributed by Alexander van der Vekens, 25-Jan-2018.) |
| Ref | Expression |
|---|---|
| pm2.24nel | ⊢ (𝐴 ∈ 𝐵 → (𝐴 ∉ 𝐵 → 𝜑)) |
| Step | Hyp | Ref | Expression |
|---|---|---|---|
| 1 | df-nel 3071 | . 2 ⊢ (𝐴 ∉ 𝐵 ↔ ¬ 𝐴 ∈ 𝐵) | |
| 2 | pm2.24 125 | . 2 ⊢ (𝐴 ∈ 𝐵 → (¬ 𝐴 ∈ 𝐵 → 𝜑)) | |
| 3 | 1, 2 | biimtrid 245 | 1 ⊢ (𝐴 ∈ 𝐵 → (𝐴 ∉ 𝐵 → 𝜑)) |
| Colors of variables: wff setvar class |
| Syntax hints: ¬ wn 3 → wi 4 ∈ wcel 2149 ∉ wnel 3070 |
| This theorem was proved from axioms: ax-mp 5 ax-1 6 ax-2 7 ax-3 8 |
| This theorem depends on definitions: df-bi 210 df-nel 3071 |
| This theorem is referenced by: xnn0lenn0nn0 13267 ge2nprmge4 16756 afv2orxorb 47847 ppivalnnnprm 48262 isubgr3stgrlem6 48618 |
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