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Theorem sb5fALT 2602
Description: Alternate version of sb5f 2537. (Contributed by NM, 5-Aug-1993.) (Revised by Mario Carneiro, 4-Oct-2016.) (Proof modification is discouraged.) (New usage is discouraged.)
Hypotheses
Ref Expression
dfsb1.p5 (𝜃 ↔ ((𝑥 = 𝑦𝜑) ∧ ∃𝑥(𝑥 = 𝑦𝜑)))
sb6fALT.1 𝑦𝜑
Assertion
Ref Expression
sb5fALT (𝜃 ↔ ∃𝑥(𝑥 = 𝑦𝜑))

Proof of Theorem sb5fALT
StepHypRef Expression
1 dfsb1.p5 . . 3 (𝜃 ↔ ((𝑥 = 𝑦𝜑) ∧ ∃𝑥(𝑥 = 𝑦𝜑)))
2 sb6fALT.1 . . 3 𝑦𝜑
31, 2sb6fALT 2601 . 2 (𝜃 ↔ ∀𝑥(𝑥 = 𝑦𝜑))
42equs45f 2481 . 2 (∃𝑥(𝑥 = 𝑦𝜑) ↔ ∀𝑥(𝑥 = 𝑦𝜑))
53, 4bitr4i 280 1 (𝜃 ↔ ∃𝑥(𝑥 = 𝑦𝜑))
Colors of variables: wff setvar class
Syntax hints:  wi 4  wb 208  wa 398  wal 1534  wex 1779  wnf 1783
This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1795  ax-4 1809  ax-5 1910  ax-6 1969  ax-7 2014  ax-10 2144  ax-12 2176  ax-13 2389
This theorem depends on definitions:  df-bi 209  df-an 399  df-or 844  df-ex 1780  df-nf 1784
This theorem is referenced by:  sb7fALT  2615
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