Theorem nulge 4457

Description: If the empty set is a finite cardinal, then it is a maximal element. (Contributed by SF, 19-Jan-2015.)

Assertion

Ref	Expression
nulge	|- (((/) e. Nn /\ A e. V) -> <<A, (/)>> e. <_fin )

Proof of Theorem nulge

Dummy variable x is distinct from all other variables.

Step	Hyp	Ref	Expression
1		addcnul1 4453	. . . . 5 |- (A +o (/)) = (/)
2	1	eqcomi 2357	. . . 4 |- (/) = (A +o (/))
3		addceq2 4385	. . . . . 6 |- (x = (/) -> (A +o x) = (A +o (/)))
4	3	eqeq2d 2364	. . . . 5 |- (x = (/) -> ((/) = (A +o x) <-> (/) = (A +o (/))))
5	4	rspcev 2956	. . . 4 |- (((/) e. Nn /\ (/) = (A +o (/))) -> E.x e. Nn (/) = (A +o x))
6	2, 5	mpan2 652	. . 3 |- ((/) e. Nn -> E.x e. Nn (/) = (A +o x))
7	6	adantr 451	. 2 |- (((/) e. Nn /\ A e. V) -> E.x e. Nn (/) = (A +o x))
8		opklefing 4449	. . 3 |- ((A e. V /\ (/) e. Nn ) -> (<<A, (/)>> e. <_fin <-> E.x e. Nn (/) = (A +o x)))
9	8	ancoms 439	. 2 |- (((/) e. Nn /\ A e. V) -> (<<A, (/)>> e. <_fin <-> E.x e. Nn (/) = (A +o x)))
10	7, 9	mpbird 223	1 |- (((/) e. Nn /\ A e. V) -> <<A, (/)>> e. <_fin )

Syntax hints:   -> wi 4   <-> wb 176   /\ wa 358   = wceq 1642   e. wcel 1710  E.wrex 2616  (/)c0 3551  <<copk 4058   Nn cnnc 4374   +o cplc 4376   <__fin clefin 4433

This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1546  ax-5 1557  ax-17 1616  ax-9 1654  ax-8 1675  ax-6 1729  ax-7 1734  ax-11 1746  ax-12 1925  ax-ext 2334  ax-nin 4079  ax-sn 4088

This theorem depends on definitions:  df-bi 177  df-or 359  df-an 360  df-3an 936  df-nan 1288  df-tru 1319  df-ex 1542  df-nf 1545  df-sb 1649  df-clab 2340  df-cleq 2346  df-clel 2349  df-nfc 2479  df-ne 2519  df-ral 2620  df-rex 2621  df-v 2862  df-nin 3212  df-compl 3213  df-in 3214  df-un 3215  df-dif 3216  df-symdif 3217  df-ss 3260  df-nul 3552  df-pw 3725  df-sn 3742  df-pr 3743  df-opk 4059  df-1c 4137  df-pw1 4138  df-ins2k 4188  df-ins3k 4189  df-imak 4190  df-sik 4193  df-ssetk 4194  df-addc 4379  df-lefin 4441

This theorem is referenced by:  lenltfin  4470