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Mirrors > Home > QLE Home > Th. List > wddi1 | GIF version |
Description: Prove the weak distributive law in WDOL. This is our first WDOL theorem making use of ax-wom 361, which is justified by wdwom 1106. (Contributed by NM, 4-Mar-2006.) |
Ref | Expression |
---|---|
wddi1 | ((a ∩ (b ∪ c)) ≡ ((a ∩ b) ∪ (a ∩ c))) = 1 |
Step | Hyp | Ref | Expression |
---|---|---|---|
1 | wdcom 1105 | . 2 C (a, b) = 1 | |
2 | wdcom 1105 | . 2 C (a, c) = 1 | |
3 | 1, 2 | wfh1 423 | 1 ((a ∩ (b ∪ c)) ≡ ((a ∩ b) ∪ (a ∩ c))) = 1 |
Colors of variables: term |
Syntax hints: = wb 1 ≡ tb 5 ∪ wo 6 ∩ wa 7 1wt 8 |
This theorem was proved from axioms: ax-a1 30 ax-a2 31 ax-a3 32 ax-a4 33 ax-a5 34 ax-r1 35 ax-r2 36 ax-r4 37 ax-r5 38 ax-wom 361 ax-wdol 1104 |
This theorem depends on definitions: df-b 39 df-a 40 df-t 41 df-f 42 df-i1 44 df-i2 45 df-le 129 df-le1 130 df-le2 131 df-cmtr 134 |
This theorem is referenced by: wddi2 1108 wddi-0 1117 |
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