Theorem 3anbi2i 1186

Description: Inference adding two conjuncts to each side of a biconditional. (Contributed by NM, 8-Sep-2006.)

Hypothesis

Ref	Expression
3anbi1i.1	|- ( ph <-> ps )

Assertion

Ref	Expression
3anbi2i	|- ( ( ch /\ ph /\ th ) <-> ( ch /\ ps /\ th ) )

Proof of Theorem 3anbi2i

Step	Hyp	Ref	Expression
1		biid 170	. 2 |- ( ch <-> ch )
2		3anbi1i.1	. 2 |- ( ph <-> ps )
3		biid 170	. 2 |- ( th <-> th )
4	1, 2, 3	3anbi123i 1183	1 |- ( ( ch /\ ph /\ th ) <-> ( ch /\ ps /\ th ) )

Syntax hints:   <-> wb 104   /\ w3a 973

This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-ia1 105  ax-ia2 106  ax-ia3 107

This theorem depends on definitions:  df-bi 116  df-3an 975

This theorem is referenced by:  seq3f1olemp  10458  seq3f1oleml  10459  fsum3  11350