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| Mirrors > Home > ILE Home > Th. List > 3sstr3i | Unicode version | ||
| Description: Substitution of equality in both sides of a subclass relationship. (Contributed by NM, 13-Jan-1996.) (Proof shortened by Eric Schmidt, 26-Jan-2007.) |
| Ref | Expression |
|---|---|
| 3sstr3.1 |
|
| 3sstr3.2 |
|
| 3sstr3.3 |
|
| Ref | Expression |
|---|---|
| 3sstr3i |
|
| Step | Hyp | Ref | Expression |
|---|---|---|---|
| 1 | 3sstr3.1 |
. 2
| |
| 2 | 3sstr3.2 |
. . 3
| |
| 3 | 3sstr3.3 |
. . 3
| |
| 4 | 2, 3 | sseq12i 3232 |
. 2
|
| 5 | 1, 4 | mpbi 145 |
1
|
| Colors of variables: wff set class |
| Syntax hints: |
| This theorem was proved from axioms: ax-mp 5 ax-1 6 ax-2 7 ax-ia1 106 ax-ia2 107 ax-ia3 108 ax-5 1473 ax-7 1474 ax-gen 1475 ax-ie1 1519 ax-ie2 1520 ax-8 1530 ax-11 1532 ax-4 1536 ax-17 1552 ax-i9 1556 ax-ial 1560 ax-i5r 1561 ax-ext 2191 |
| This theorem depends on definitions: df-bi 117 df-nf 1487 df-sb 1789 df-clab 2196 df-cleq 2202 df-clel 2205 df-in 3183 df-ss 3190 |
| This theorem is referenced by: (None) |
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