Theorem hbal 1465

Description: If x is not free in ph, it is not free in A. y ph. (Contributed by NM, 5-Aug-1993.)

Hypothesis

Ref	Expression
hbal.1	|- ( ph -> A. x ph )

Assertion

Ref	Expression
hbal	|- ( A. y ph -> A. x A. y ph )

Proof of Theorem hbal

Step	Hyp	Ref	Expression
1		hbal.1	. . 3 |- ( ph -> A. x ph )
2	1	alimi 1443	. 2 |- ( A. y ph -> A. y A. x ph )
3		ax-7 1436	. 2 |- ( A. y A. x ph -> A. x A. y ph )
4	2, 3	syl 14	1 |- ( A. y ph -> A. x A. y ph )

Syntax hints:   -> wi 4   A.wal 1341

This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-5 1435  ax-7 1436  ax-gen 1437

This theorem is referenced by:  hba2  1539  aaanh  1574  hbex  1624  pm11.53  1883  euf  2019  hbral  2495