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Theorem hbal 1488
Description: If 𝑥 is not free in 𝜑, it is not free in 𝑦𝜑. (Contributed by NM, 5-Aug-1993.)
Hypothesis
Ref Expression
hbal.1 (𝜑 → ∀𝑥𝜑)
Assertion
Ref Expression
hbal (∀𝑦𝜑 → ∀𝑥𝑦𝜑)

Proof of Theorem hbal
StepHypRef Expression
1 hbal.1 . . 3 (𝜑 → ∀𝑥𝜑)
21alimi 1466 . 2 (∀𝑦𝜑 → ∀𝑦𝑥𝜑)
3 ax-7 1459 . 2 (∀𝑦𝑥𝜑 → ∀𝑥𝑦𝜑)
42, 3syl 14 1 (∀𝑦𝜑 → ∀𝑥𝑦𝜑)
Colors of variables: wff set class
Syntax hints:  wi 4  wal 1362
This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-5 1458  ax-7 1459  ax-gen 1460
This theorem is referenced by:  hba2  1562  aaanh  1597  hbex  1647  pm11.53  1907  euf  2043  hbral  2519
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