Theorem neeqtrrd 2397

Description: Substitution of equal classes into an inequality. (Contributed by NM, 4-Jul-2012.)

Hypotheses

Ref	Expression
neeqtrrd.1	|- ( ph -> A =/= B )
neeqtrrd.2	|- ( ph -> C = B )

Assertion

Ref	Expression
neeqtrrd	|- ( ph -> A =/= C )

Proof of Theorem neeqtrrd

Step	Hyp	Ref	Expression
1		neeqtrrd.1	. 2 |- ( ph -> A =/= B )
2		neeqtrrd.2	. . 3 |- ( ph -> C = B )
3	2	eqcomd 2202	. 2 |- ( ph -> B = C )
4	1, 3	neeqtrd 2395	1 |- ( ph -> A =/= C )

Syntax hints:   -> wi 4   = wceq 1364   =/= wne 2367

This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-ia1 106  ax-ia2 107  ax-ia3 108  ax-in1 615  ax-in2 616  ax-5 1461  ax-gen 1463  ax-4 1524  ax-17 1540  ax-ext 2178

This theorem depends on definitions:  df-bi 117  df-cleq 2189  df-ne 2368

This theorem is referenced by:  frecabcl  6457  expnprm  12498