Theorem neeqtrrd 2366

Description: Substitution of equal classes into an inequality. (Contributed by NM, 4-Jul-2012.)

Hypotheses

Ref	Expression
neeqtrrd.1	|- ( ph -> A =/= B )
neeqtrrd.2	|- ( ph -> C = B )

Assertion

Ref	Expression
neeqtrrd	|- ( ph -> A =/= C )

Proof of Theorem neeqtrrd

Step	Hyp	Ref	Expression
1		neeqtrrd.1	. 2 |- ( ph -> A =/= B )
2		neeqtrrd.2	. . 3 |- ( ph -> C = B )
3	2	eqcomd 2171	. 2 |- ( ph -> B = C )
4	1, 3	neeqtrd 2364	1 |- ( ph -> A =/= C )

Syntax hints:   -> wi 4   = wceq 1343   =/= wne 2336

This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-ia1 105  ax-ia2 106  ax-ia3 107  ax-in1 604  ax-in2 605  ax-5 1435  ax-gen 1437  ax-4 1498  ax-17 1514  ax-ext 2147

This theorem depends on definitions:  df-bi 116  df-cleq 2158  df-ne 2337

This theorem is referenced by:  frecabcl  6367  expnprm  12283