Theorem anandis 592

Description: Inference that undistributes conjunction in the antecedent. (Contributed by NM, 7-Jun-2004.)

Hypothesis

Ref	Expression
anandis.1	⊢ (((𝜑 ∧ 𝜓) ∧ (𝜑 ∧ 𝜒)) → 𝜏)

Assertion

Ref	Expression
anandis	⊢ ((𝜑 ∧ (𝜓 ∧ 𝜒)) → 𝜏)

Proof of Theorem anandis

Step	Hyp	Ref	Expression
1		anandis.1	. . 3 ⊢ (((𝜑 ∧ 𝜓) ∧ (𝜑 ∧ 𝜒)) → 𝜏)
2	1	an4s 588	. 2 ⊢ (((𝜑 ∧ 𝜑) ∧ (𝜓 ∧ 𝜒)) → 𝜏)
3	2	anabsan 575	1 ⊢ ((𝜑 ∧ (𝜓 ∧ 𝜒)) → 𝜏)

Syntax hints:   → wi 4   ∧ wa 104

This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-ia1 106  ax-ia2 107  ax-ia3 108

This theorem depends on definitions:  df-bi 117

This theorem is referenced by:  3impdi  1304  dff13  5815  f1oiso  5873  ltapig  7405  ltmpig  7406  faclbnd  10833  tgcl  14300