Theorem hbex 1624

Description: If 𝑥 is not free in 𝜑, it is not free in ∃𝑦𝜑. (Contributed by NM, 5-Aug-1993.) (Revised by NM, 2-Feb-2015.)

Hypothesis

Ref	Expression
hbex.1	⊢ (𝜑 → ∀𝑥𝜑)

Assertion

Ref	Expression
hbex	⊢ (∃𝑦𝜑 → ∀𝑥∃𝑦𝜑)

Proof of Theorem hbex

Step	Hyp	Ref	Expression
1		hbe1 1483	. . 3 ⊢ (∃𝑦𝜑 → ∀𝑦∃𝑦𝜑)
2	1	hbal 1465	. 2 ⊢ (∀𝑥∃𝑦𝜑 → ∀𝑦∀𝑥∃𝑦𝜑)
3		hbex.1	. . 3 ⊢ (𝜑 → ∀𝑥𝜑)
4		19.8a 1578	. . 3 ⊢ (𝜑 → ∃𝑦𝜑)
5	3, 4	alrimih 1457	. 2 ⊢ (𝜑 → ∀𝑥∃𝑦𝜑)
6	2, 5	exlimih 1581	1 ⊢ (∃𝑦𝜑 → ∀𝑥∃𝑦𝜑)

Syntax hints:   → wi 4  ∀wal 1341  ∃wex 1480

This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-ia1 105  ax-ia2 106  ax-ia3 107  ax-5 1435  ax-7 1436  ax-gen 1437  ax-ie1 1481  ax-ie2 1482  ax-4 1498

This theorem depends on definitions:  df-bi 116

This theorem is referenced by:  nfex  1625  excomim  1651  19.12  1653  cbvexh  1743  cbvexdh  1914  hbsbv  1929  hbeu1  2024  hbmo  2053  moexexdc  2098