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Theorem hbex 1636
Description: If 𝑥 is not free in 𝜑, it is not free in 𝑦𝜑. (Contributed by NM, 5-Aug-1993.) (Revised by NM, 2-Feb-2015.)
Hypothesis
Ref Expression
hbex.1 (𝜑 → ∀𝑥𝜑)
Assertion
Ref Expression
hbex (∃𝑦𝜑 → ∀𝑥𝑦𝜑)

Proof of Theorem hbex
StepHypRef Expression
1 hbe1 1495 . . 3 (∃𝑦𝜑 → ∀𝑦𝑦𝜑)
21hbal 1477 . 2 (∀𝑥𝑦𝜑 → ∀𝑦𝑥𝑦𝜑)
3 hbex.1 . . 3 (𝜑 → ∀𝑥𝜑)
4 19.8a 1590 . . 3 (𝜑 → ∃𝑦𝜑)
53, 4alrimih 1469 . 2 (𝜑 → ∀𝑥𝑦𝜑)
62, 5exlimih 1593 1 (∃𝑦𝜑 → ∀𝑥𝑦𝜑)
Colors of variables: wff set class
Syntax hints:  wi 4  wal 1351  wex 1492
This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-ia1 106  ax-ia2 107  ax-ia3 108  ax-5 1447  ax-7 1448  ax-gen 1449  ax-ie1 1493  ax-ie2 1494  ax-4 1510
This theorem depends on definitions:  df-bi 117
This theorem is referenced by:  nfex  1637  excomim  1663  19.12  1665  cbvexh  1755  cbvexdh  1926  hbsbv  1941  hbeu1  2036  hbmo  2065  moexexdc  2110
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