Theorem mpidan 427

Description: A deduction which "stacks" a hypothesis. (Contributed by Stanislas Polu, 9-Mar-2020.) (Proof shortened by Wolf Lammen, 28-Mar-2021.)

Hypotheses

Ref	Expression
mpidan.1	⊢ (𝜑 → 𝜒)
mpidan.2	⊢ (((𝜑 ∧ 𝜓) ∧ 𝜒) → 𝜃)

Assertion

Ref	Expression
mpidan	⊢ ((𝜑 ∧ 𝜓) → 𝜃)

Proof of Theorem mpidan

Step	Hyp	Ref	Expression
1		mpidan.1	. . 3 ⊢ (𝜑 → 𝜒)
2	1	adantr 276	. 2 ⊢ ((𝜑 ∧ 𝜓) → 𝜒)
3		mpidan.2	. 2 ⊢ (((𝜑 ∧ 𝜓) ∧ 𝜒) → 𝜃)
4	2, 3	mpdan 425	1 ⊢ ((𝜑 ∧ 𝜓) → 𝜃)

This proof depends on syntax axioms:   → wi 4   ∧ wa 104

This proof depends on axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-ia1 106  ax-ia2 107  ax-ia3 108

This theorem is used by:  sumrbdc  12165  prodrbdclem2  12359  subsubrng  14606  subsubrg  14637  asclpropd  15124  tx2cn  15462  dvaddxxbr  15893  dvmulxxbr  15894