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| Mirrors > Home > ILE Home > Th. List > nfs1f | GIF version | ||
| Description: If 𝑥 is not free in 𝜑, it is not free in [𝑦 / 𝑥]𝜑. (Contributed by Mario Carneiro, 11-Aug-2016.) |
| Ref | Expression |
|---|---|
| nfs1f.1 | ⊢ Ⅎ𝑥𝜑 |
| Ref | Expression |
|---|---|
| nfs1f | ⊢ Ⅎ𝑥[𝑦 / 𝑥]𝜑 |
| Step | Hyp | Ref | Expression |
|---|---|---|---|
| 1 | nfs1f.1 | . . . 4 ⊢ Ⅎ𝑥𝜑 | |
| 2 | 1 | nfri 1543 | . . 3 ⊢ (𝜑 → ∀𝑥𝜑) |
| 3 | 2 | sbh 1800 | . 2 ⊢ ([𝑦 / 𝑥]𝜑 ↔ 𝜑) |
| 4 | 3, 1 | nfxfr 1498 | 1 ⊢ Ⅎ𝑥[𝑦 / 𝑥]𝜑 |
| Colors of variables: wff set class |
| Syntax hints: Ⅎwnf 1484 [wsb 1786 |
| This theorem was proved from axioms: ax-mp 5 ax-1 6 ax-2 7 ax-ia1 106 ax-ia2 107 ax-ia3 108 ax-5 1471 ax-gen 1473 ax-ie1 1517 ax-ie2 1518 ax-4 1534 ax-i9 1554 ax-ial 1558 |
| This theorem depends on definitions: df-bi 117 df-nf 1485 df-sb 1787 |
| This theorem is referenced by: (None) |
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