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| Mirrors > Home > ILE Home > Th. List > hbs1f | GIF version | ||
| Description: If 𝑥 is not free in 𝜑, it is not free in [𝑦 / 𝑥]𝜑. (Contributed by NM, 5-Aug-1993.) (Proof shortened by Andrew Salmon, 25-May-2011.) |
| Ref | Expression |
|---|---|
| hbs1f.1 | ⊢ (𝜑 → ∀𝑥𝜑) |
| Ref | Expression |
|---|---|
| hbs1f | ⊢ ([𝑦 / 𝑥]𝜑 → ∀𝑥[𝑦 / 𝑥]𝜑) |
| Step | Hyp | Ref | Expression |
|---|---|---|---|
| 1 | hbs1f.1 | . . 3 ⊢ (𝜑 → ∀𝑥𝜑) | |
| 2 | 1 | sbh 1799 | . 2 ⊢ ([𝑦 / 𝑥]𝜑 ↔ 𝜑) |
| 3 | 2, 1 | hbxfrbi 1495 | 1 ⊢ ([𝑦 / 𝑥]𝜑 → ∀𝑥[𝑦 / 𝑥]𝜑) |
| Colors of variables: wff set class |
| Syntax hints: → wi 4 ∀wal 1371 [wsb 1785 |
| This theorem was proved from axioms: ax-mp 5 ax-1 6 ax-2 7 ax-ia1 106 ax-ia2 107 ax-ia3 108 ax-5 1470 ax-gen 1472 ax-ie1 1516 ax-ie2 1517 ax-4 1533 ax-i9 1553 ax-ial 1557 |
| This theorem depends on definitions: df-bi 117 df-sb 1786 |
| This theorem is referenced by: (None) |
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