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Theorem 3ccased 36453
Description: Triple disjunction form of ccased 1054. (Contributed by Scott Fenton, 27-Oct-2013.) (Revised by Mario Carneiro, 19-Apr-2014.)
Hypotheses
Ref Expression
3ccased.1 (𝜑 → ((𝜒 ∧ 𝜂) → 𝜓))
3ccased.2 (𝜑 → ((𝜒 ∧ 𝜁) → 𝜓))
3ccased.3 (𝜑 → ((𝜒 ∧ 𝜎) → 𝜓))
3ccased.4 (𝜑 → ((𝜃 ∧ 𝜂) → 𝜓))
3ccased.5 (𝜑 → ((𝜃 ∧ 𝜁) → 𝜓))
3ccased.6 (𝜑 → ((𝜃 ∧ 𝜎) → 𝜓))
3ccased.7 (𝜑 → ((𝜏 ∧ 𝜂) → 𝜓))
3ccased.8 (𝜑 → ((𝜏 ∧ 𝜁) → 𝜓))
3ccased.9 (𝜑 → ((𝜏 ∧ 𝜎) → 𝜓))
Assertion
Ref Expression
3ccased (𝜑 → (((𝜒 ∨ 𝜃 ∨ 𝜏) ∧ (𝜂 ∨ 𝜁 ∨ 𝜎)) → 𝜓))

Proof of Theorem 3ccased
StepHypRef Expression
1 3ccased.1 . . . . 5 (𝜑 → ((𝜒 ∧ 𝜂) → 𝜓))
21com12 33 . . . 4 ((𝜒 ∧ 𝜂) → (𝜑 → 𝜓))
3 3ccased.2 . . . . 5 (𝜑 → ((𝜒 ∧ 𝜁) → 𝜓))
43com12 33 . . . 4 ((𝜒 ∧ 𝜁) → (𝜑 → 𝜓))
5 3ccased.3 . . . . 5 (𝜑 → ((𝜒 ∧ 𝜎) → 𝜓))
65com12 33 . . . 4 ((𝜒 ∧ 𝜎) → (𝜑 → 𝜓))
72, 4, 63jaodan 1458 . . 3 ((𝜒 ∧ (𝜂 ∨ 𝜁 ∨ 𝜎)) → (𝜑 → 𝜓))
8 3ccased.4 . . . . 5 (𝜑 → ((𝜃 ∧ 𝜂) → 𝜓))
98com12 33 . . . 4 ((𝜃 ∧ 𝜂) → (𝜑 → 𝜓))
10 3ccased.5 . . . . 5 (𝜑 → ((𝜃 ∧ 𝜁) → 𝜓))
1110com12 33 . . . 4 ((𝜃 ∧ 𝜁) → (𝜑 → 𝜓))
12 3ccased.6 . . . . 5 (𝜑 → ((𝜃 ∧ 𝜎) → 𝜓))
1312com12 33 . . . 4 ((𝜃 ∧ 𝜎) → (𝜑 → 𝜓))
149, 11, 133jaodan 1458 . . 3 ((𝜃 ∧ (𝜂 ∨ 𝜁 ∨ 𝜎)) → (𝜑 → 𝜓))
15 3ccased.7 . . . . 5 (𝜑 → ((𝜏 ∧ 𝜂) → 𝜓))
1615com12 33 . . . 4 ((𝜏 ∧ 𝜂) → (𝜑 → 𝜓))
17 3ccased.8 . . . . 5 (𝜑 → ((𝜏 ∧ 𝜁) → 𝜓))
1817com12 33 . . . 4 ((𝜏 ∧ 𝜁) → (𝜑 → 𝜓))
19 3ccased.9 . . . . 5 (𝜑 → ((𝜏 ∧ 𝜎) → 𝜓))
2019com12 33 . . . 4 ((𝜏 ∧ 𝜎) → (𝜑 → 𝜓))
2116, 18, 203jaodan 1458 . . 3 ((𝜏 ∧ (𝜂 ∨ 𝜁 ∨ 𝜎)) → (𝜑 → 𝜓))
227, 14, 213jaoian 1457 . 2 (((𝜒 ∨ 𝜃 ∨ 𝜏) ∧ (𝜂 ∨ 𝜁 ∨ 𝜎)) → (𝜑 → 𝜓))
2322com12 33 1 (𝜑 → (((𝜒 ∨ 𝜃 ∨ 𝜏) ∧ (𝜂 ∨ 𝜁 ∨ 𝜎)) → 𝜓))
Colors of variables:    wff setvar class
This proof depends on syntax axioms:   → wi 4   ∧ wa 401   ∨ w3o 1102
This proof depends on axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8
This proof depends on definitions:  df-bi 210  df-an 402  df-or 862  df-3or 1104  df-3an 1105
This theorem is used by: (None)
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