Theorem 3netr4g 3035

Description: Substitution of equality into both sides of an inequality. (Contributed by NM, 14-Jun-2012.)

Hypotheses

Ref	Expression
3netr4g.1	⊢ (𝜑 → 𝐴 ≠ 𝐵)
3netr4g.2	⊢ 𝐶 = 𝐴
3netr4g.3	⊢ 𝐷 = 𝐵

Assertion

Ref	Expression
3netr4g	⊢ (𝜑 → 𝐶 ≠ 𝐷)

Proof of Theorem 3netr4g

Step	Hyp	Ref	Expression
1		3netr4g.1	. 2 ⊢ (𝜑 → 𝐴 ≠ 𝐵)
2		3netr4g.2	. . 3 ⊢ 𝐶 = 𝐴
3		3netr4g.3	. . 3 ⊢ 𝐷 = 𝐵
4	2, 3	neeq12i 3022	. 2 ⊢ (𝐶 ≠ 𝐷 ↔ 𝐴 ≠ 𝐵)
5	1, 4	sylibr 237	1 ⊢ (𝜑 → 𝐶 ≠ 𝐷)

This proof depends on syntax axioms:   → wi 4   = wceq 1570   ≠ wne 2956

This proof depends on axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1828  ax-4 1842  ax-5 1943  ax-6 2000  ax-7 2041  ax-9 2155  ax-ext 2733

This proof depends on definitions:  df-bi 210  df-an 402  df-ex 1813  df-cleq 2753  df-ne 2957

This theorem is used by:  aalioulem2  26642  mapdpglem18  42714  line2x  49810