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Theorem bj-ssbid1ALT 34502
Description: Alternate proof of bj-ssbid1 34501, not using sbequ1 2249. (Contributed by BJ, 22-Dec-2020.) (Proof modification is discouraged.) (New usage is discouraged.)
Assertion
Ref Expression
bj-ssbid1ALT (𝜑 → [𝑥 / 𝑥]𝜑)

Proof of Theorem bj-ssbid1ALT
Dummy variable 𝑦 is distinct from all other variables.
StepHypRef Expression
1 ax12v 2180 . . . . 5 (𝑥 = 𝑦 → (𝜑 → ∀𝑥(𝑥 = 𝑦𝜑)))
21equcoms 2032 . . . 4 (𝑦 = 𝑥 → (𝜑 → ∀𝑥(𝑥 = 𝑦𝜑)))
32com12 32 . . 3 (𝜑 → (𝑦 = 𝑥 → ∀𝑥(𝑥 = 𝑦𝜑)))
43alrimiv 1934 . 2 (𝜑 → ∀𝑦(𝑦 = 𝑥 → ∀𝑥(𝑥 = 𝑦𝜑)))
5 df-sb 2075 . 2 ([𝑥 / 𝑥]𝜑 ↔ ∀𝑦(𝑦 = 𝑥 → ∀𝑥(𝑥 = 𝑦𝜑)))
64, 5sylibr 237 1 (𝜑 → [𝑥 / 𝑥]𝜑)
Colors of variables: wff setvar class
Syntax hints:  wi 4  wal 1540  [wsb 2074
This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1802  ax-4 1816  ax-5 1917  ax-6 1975  ax-7 2020  ax-12 2179
This theorem depends on definitions:  df-bi 210  df-an 400  df-ex 1787  df-sb 2075
This theorem is referenced by: (None)
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