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Mirrors > Home > MPE Home > Th. List > Mathboxes > empty-surprise2 | Structured version Visualization version GIF version |
Description: "Prove" that
false is true when using a restricted "for all" over the
empty set, to demonstrate that the expression is always true if the
value ranges over the empty set.
Those inexperienced with formal notations of classical logic can be surprised with what restricted "for all" does over an empty set. We proved the general case in empty-surprise 46372. Here we prove an extreme example: we "prove" that false is true. Of course, we actually do no such thing (see notfal 1567); the problem is that restricted "for all" works in ways that might seem counterintuitive to the inexperienced when given an empty set. Solutions to this can include requiring that the set not be empty or by using the allsome quantifier df-alsc 46379. (Contributed by David A. Wheeler, 20-Oct-2018.) |
Ref | Expression |
---|---|
empty-surprise2.1 | ⊢ ¬ ∃𝑥 𝑥 ∈ 𝐴 |
Ref | Expression |
---|---|
empty-surprise2 | ⊢ ∀𝑥 ∈ 𝐴 ⊥ |
Step | Hyp | Ref | Expression |
---|---|---|---|
1 | empty-surprise2.1 | . 2 ⊢ ¬ ∃𝑥 𝑥 ∈ 𝐴 | |
2 | 1 | empty-surprise 46372 | 1 ⊢ ∀𝑥 ∈ 𝐴 ⊥ |
Colors of variables: wff setvar class |
Syntax hints: ¬ wn 3 ⊥wfal 1551 ∃wex 1783 ∈ wcel 2108 ∀wral 3063 |
This theorem was proved from axioms: ax-mp 5 ax-1 6 ax-2 7 ax-3 8 ax-gen 1799 ax-4 1813 ax-5 1914 ax-6 1972 ax-7 2012 ax-12 2173 |
This theorem depends on definitions: df-bi 206 df-an 396 df-or 844 df-ex 1784 df-ral 3068 |
This theorem is referenced by: (None) |
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