Theorem exellimddv 38459

Description: Eliminate an antecedent when the antecedent is elementhood, deduction version. See exellim 38458 for the closed form, which requires the use of a universal quantifier. (Contributed by ML, 17-Jul-2020.)

Hypotheses

Ref	Expression
exellimddv.1	⊢ (𝜑 → ∃𝑥 𝑥 ∈ 𝐴)
exellimddv.2	⊢ (𝜑 → (𝑥 ∈ 𝐴 → 𝜓))

Assertion

Ref	Expression
exellimddv	⊢ (𝜑 → 𝜓)

Distinct variable groups:   𝜑,𝑥   𝜓,𝑥

Allowed substitution hint:   𝐴(𝑥)

Proof of Theorem exellimddv

Step	Hyp	Ref	Expression
1		exellimddv.1	. 2 ⊢ (𝜑 → ∃𝑥 𝑥 ∈ 𝐴)
2		exellimddv.2	. . 3 ⊢ (𝜑 → (𝑥 ∈ 𝐴 → 𝜓))
3	2	alrimiv 1962	. 2 ⊢ (𝜑 → ∀𝑥(𝑥 ∈ 𝐴 → 𝜓))
4		exellim 38458	. 2 ⊢ ((∃𝑥 𝑥 ∈ 𝐴 ∧ ∀𝑥(𝑥 ∈ 𝐴 → 𝜓)) → 𝜓)
5	1, 3, 4	syl2anc 596	1 ⊢ (𝜑 → 𝜓)

This proof depends on syntax axioms:   → wi 4  ∀wal 1568  ∃wex 1812   ∈ wcel 2147

This proof depends on axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1828  ax-4 1842  ax-5 1945  ax-6 2002  ax-7 2043  ax-10 2180  ax-12 2216

This proof depends on definitions:  df-bi 210  df-an 402  df-or 862  df-ex 1813  df-nf 1817

This theorem is used by:  topdifinffinlem  38461