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Theorem List for Metamath Proof Explorer - 36701-36800   *Has distinct variable group(s)
TypeLabelDescription
Statement
 
Theoremttcss 36701 A transitive closure contains the transitive closures of all its subclasses. (Contributed by Matthew House, 6-Apr-2026.)
(𝐴 ⊆ TC+ 𝐵 → TC+ 𝐴 ⊆ TC+ 𝐵)
 
Theoremttcss2 36702 The subclass relationship is inherited by transitive closures. (Contributed by Matthew House, 6-Apr-2026.)
(𝐴𝐵 → TC+ 𝐴 ⊆ TC+ 𝐵)
 
Theoremttcel 36703 A transitive closure contains the transitive closures of all its elements. (Contributed by Matthew House, 6-Apr-2026.)
(𝐴 ∈ TC+ 𝐵 → TC+ 𝐴 ⊆ TC+ 𝐵)
 
Theoremttcel2 36704 Elements turn into subclasses upon taking transitive closures. (Contributed by Matthew House, 6-Apr-2026.)
(𝐴𝐵 → TC+ 𝐴 ⊆ TC+ 𝐵)
 
Theoremttctrid 36705 The transitive closure of a transitive class is the class itself. (Contributed by Matthew House, 6-Apr-2026.)
(Tr 𝐴 → TC+ 𝐴 = 𝐴)
 
Theoremttcidm 36706 The transitive closure operation is idempotent. (Contributed by Matthew House, 6-Apr-2026.)
TC+ TC+ 𝐴 = TC+ 𝐴
 
Theoremssttctr 36707 Transitivity of 𝐴 ⊆ TC+ 𝐵 relationship. (Contributed by Matthew House, 6-Apr-2026.)
((𝐴 ⊆ TC+ 𝐵𝐵 ⊆ TC+ 𝐶) → 𝐴 ⊆ TC+ 𝐶)
 
Theoremelttctr 36708 Transitivity of 𝐴 ∈ TC+ 𝐵 relationship. (Contributed by Matthew House, 6-Apr-2026.)
((𝐴 ∈ TC+ 𝐵𝐵 ∈ TC+ 𝐶) → 𝐴 ∈ TC+ 𝐶)
 
Theoremdfttc2g 36709 A shorter expression for the transitive closure of a set. (Contributed by Matthew House, 6-Apr-2026.)
(𝐴𝑉 → TC+ 𝐴 = (rec((𝑥 ∈ V ↦ 𝑥), 𝐴) “ ω))
 
Theoremttc0 36710 The transitive closure of the empty set is the empty set. (Contributed by Matthew House, 6-Apr-2026.)
TC+ ∅ = ∅
 
Theoremttc00 36711 A class has an empty transitive closure iff it is the empty set. (Contributed by Matthew House, 6-Apr-2026.)
(𝐴 = ∅ ↔ TC+ 𝐴 = ∅)
 
Theoremcsbttc 36712 Distribute proper substitution through a transitive closure. (Contributed by Matthew House, 6-Apr-2026.)
𝐴 / 𝑥TC+ 𝐵 = TC+ 𝐴 / 𝑥𝐵
 
Theoremttcuniun 36713 Relationship between TC+ 𝐴 and TC+ 𝐴: we can decompose TC+ 𝐴 into the elements of TC+ 𝐴 plus the elements of 𝐴 itself. (Contributed by Matthew House, 6-Apr-2026.)
TC+ 𝐴 = (TC+ 𝐴𝐴)
 
Theoremttciunun 36714* Relationship between TC+ 𝐴 and 𝑥𝐴TC+ 𝑥: we can decompose TC+ 𝐴 into the elements of 𝑥𝐴TC+ 𝑥 plus the elements of 𝐴 itself. (Contributed by Matthew House, 6-Apr-2026.)
TC+ 𝐴 = ( 𝑥𝐴 TC+ 𝑥𝐴)
 
Theoremttcun 36715 Distribute union of two classes through a transitive closure. (Contributed by Matthew House, 6-Apr-2026.)
TC+ (𝐴𝐵) = (TC+ 𝐴 ∪ TC+ 𝐵)
 
Theoremttcuni 36716 Distribute union of a class through a transitive closure. (Contributed by Matthew House, 6-Apr-2026.)
TC+ 𝐴 = TC+ 𝐴
 
Theoremttciun 36717 Distribute indexed union through a transitive closure. (Contributed by Matthew House, 6-Apr-2026.)
TC+ 𝑥𝐴 𝐵 = 𝑥𝐴 TC+ 𝐵
 
Theoremttcpwss 36718 The transitive closure of a power class is contained in the power class of the transitive closure. (Contributed by Matthew House, 6-Apr-2026.)
TC+ 𝒫 𝐴 ⊆ 𝒫 TC+ 𝐴
 
Theoremttcsnssg 36719 The transitive closure is contained in the singleton transitive closure. (Contributed by Matthew House, 6-Apr-2026.)
(𝐴𝑉 → TC+ 𝐴 ⊆ TC+ {𝐴})
 
Theoremttcsnidg 36720 The singleton transitive closure contains its argument 𝐴 as an element. (Contributed by Matthew House, 6-Apr-2026.)
(𝐴𝑉𝐴 ∈ TC+ {𝐴})
 
Theoremttcsnmin 36721 The singleton transitive closure is the minimal transitive class containing 𝐴 as an element. (Contributed by Matthew House, 6-Apr-2026.)
((𝐴𝐵 ∧ Tr 𝐵) → TC+ {𝐴} ⊆ 𝐵)
 
Theoremttcsng 36722 Relationship between TC+ {𝐴} and TC+ 𝐴: the former contains the additional element 𝐴. (Contributed by Matthew House, 6-Apr-2026.)
(𝐴𝑉 → TC+ {𝐴} = (TC+ 𝐴 ∪ {𝐴}))
 
Theoremttcsnexg 36723 If the transitive closure of a class is a set, then its singleton transitive closure is a set. (Contributed by Matthew House, 6-Apr-2026.)
(TC+ 𝐴𝑉 → TC+ {𝐴} ∈ V)
 
Theoremttcsnexbig 36724 The transitive closure of a set is a set iff its singleton transitive closure is a set. (Contributed by Matthew House, 6-Apr-2026.)
(𝐴𝑉 → (TC+ 𝐴 ∈ V ↔ TC+ {𝐴} ∈ V))
 
Theoremttcsntrsucg 36725 The singleton transitive closure of a transitive set is its successor. (Contributed by Matthew House, 6-Apr-2026.)
((𝐴𝑉 ∧ Tr 𝐴) → TC+ {𝐴} = suc 𝐴)
 
Theoremdfttc3gw 36726 If the transitive closure of 𝐴 is a set, then its value is (TC‘𝐴). If we assume Transitive Containment, then we can weaken the hypothesis to 𝐴𝑉, see dfttc3g 36737. (Contributed by Matthew House, 6-Apr-2026.)
(TC+ 𝐴𝑉 → TC+ 𝐴 = (TC‘𝐴))
 
Theoremttcwf 36727 A set is well-founded iff its transitive closure is well-founded. As a corollary, the transitive closure of any well-founded set is a set. (Contributed by Matthew House, 6-Apr-2026.)
(𝐴 (𝑅1 “ On) ↔ TC+ 𝐴 (𝑅1 “ On))
 
Theoremttcwf2 36728 If a transitive closure class is a set, then it is well-founded, assuming Regularity. (Contributed by Matthew House, 6-Apr-2026.)
(TC+ 𝐴 ∈ V ↔ TC+ 𝐴 (𝑅1 “ On))
 
Theoremttcwf3 36729 The sets whose transitive closures are sets are precisely the well-founded sets, assuming Regularity. (Contributed by Matthew House, 6-Apr-2026.)
(TC+ 𝐴 ∈ V ↔ 𝐴 (𝑅1 “ On))
 
Theoremttc0elw 36730 If a transitive closure is a set, then it contains as an element iff it is nonempty, assuming Regularity. If we also assume Transitive Containment, then we can remove the TC+ 𝐴𝑉 hypothesis, see ttc0el 36738. (Contributed by Matthew House, 6-Apr-2026.)
(TC+ 𝐴𝑉 → (𝐴 ≠ ∅ ↔ ∅ ∈ TC+ 𝐴))
 
Theoremdfttc4lem1 36731* Lemma for dfttc4 36733. (Contributed by Matthew House, 6-Apr-2026.)
𝐵 = {𝑥 ∣ ∃𝑦((𝐴𝑦) ≠ ∅ ∧ ∀𝑧𝑦 ((𝑧𝑦) = ∅ → 𝑧 = 𝑥))}    &   𝐶 ∈ V    &   𝐷 ∈ V       (((𝐴𝐶) ≠ ∅ ∧ ∀𝑧𝐶 ((𝑧𝐶) = ∅ → 𝑧 = 𝐷)) → 𝐷𝐵)
 
Theoremdfttc4lem2 36732* Lemma for dfttc4 36733. (Contributed by Matthew House, 6-Apr-2026.)
𝐵 = {𝑥 ∣ ∃𝑦((𝐴𝑦) ≠ ∅ ∧ ∀𝑧𝑦 ((𝑧𝑦) = ∅ → 𝑧 = 𝑥))}       (𝐴𝐵 ∧ Tr 𝐵)
 
Theoremdfttc4 36733* An alternative expression for the transitive closure of a class, assuming Regularity. A set 𝑥 is contained in the transitive closure of 𝐴 iff we can construct an -chain from 𝑥 to an element of 𝐴. This weak definition is primarily useful for proving elttcirr 36734. (Contributed by Matthew House, 6-Apr-2026.)
TC+ 𝐴 = {𝑥 ∣ ∃𝑦((𝐴𝑦) ≠ ∅ ∧ ∀𝑧𝑦 ((𝑧𝑦) = ∅ → 𝑧 = 𝑥))}
 
Theoremelttcirr 36734 Irreflexivity of 𝐴 ∈ TC+ 𝐵 relationship. This is a consequence of Regularity, but it does not require Transitive Containment. We use the alternative expression dfttc4 36733 to construct a set in which 𝐴 is both -minimal and not -minimal. (Contributed by Matthew House, 6-Apr-2026.)
¬ 𝐴 ∈ TC+ 𝐴
 
Theoremttcexg 36735 The transitive closure of a set is a set, assuming Transitive Containment. (Contributed by Matthew House, 6-Apr-2026.)
(𝐴𝑉 → TC+ 𝐴 ∈ V)
 
Theoremttcexbi 36736 A class is a set iff its transitive closure is a set, assuming Transitive Containment. (Contributed by Matthew House, 6-Apr-2026.)
(𝐴 ∈ V ↔ TC+ 𝐴 ∈ V)
 
Theoremdfttc3g 36737 The transitive closure of a set 𝐴 is (TC‘𝐴), assuming Transitive Containment. (Contributed by Matthew House, 6-Apr-2026.)
(𝐴𝑉 → TC+ 𝐴 = (TC‘𝐴))
 
Theoremttc0el 36738 A transitive closure contains as an element iff it is nonempty, assuming Regularity and Transitive Containment. (Contributed by Matthew House, 6-Apr-2026.)
(𝐴 ≠ ∅ ↔ ∅ ∈ TC+ 𝐴)
 
21.17.4  Stronger axioms of regularity

This section contains some experiments related to the Axiom of Regularity ax-reg 9498. As written, ax-reg 9498 cannot guarantee that all sets are well-founded unless we further assume ax-inf 9548 / ax-inf2 9551; in particular, ax-reg 9498 alone is insufficient to assert that every set has a transitive closure (tz9.1 9639), even though this is true among the hereditarily finite sets.

The underlying cause of this issue is that ax-reg 9498 requires a witness set to detect non-well-foundedness, but if all sets are hereditarily finite, then there may be no such witness set for an infinite descending -chain. The question is, how can we strengthen ax-reg 9498 so that we get a true "Axiom of Foundation" even in the absence of ax-inf 9548 / ax-inf2 9551 (e.g., so that we can prove unir1 9726 (𝑅1 “ On) = V)?

There are a few possible solutions. First, we can directly strengthen ax-reg 9498 into ax-regs 35291, which asserts that every class {𝑥𝜑} has an -minimal element. Second, we can keep ax-reg 9498 and add ax-tco 36675, which asserts that every set is a member of a transitive set. Third, we can replace ax-reg 9498 with a set-induction axiom mh-setind 36739. Fourth, we can take unir1 9726 as an axiom and derive everything from that. This list is far from exhaustive.

In this section, we prove that these four listed principles are equivalent. We see that ax-regs 35291 implies the other three principles: ax-reg 9498 + ax-tco 36675 via axreg 35292 + tz9.1regs 35299, mh-setind 36739 via setindregs 35295, and unir1 9726 via unir1regs 35300. So we just have to show that ax-regs 35291 is implied by each of the other three.

Some questions: When expanded to primitives, what is the shortest single axiom equivalent to these, over ZF minus ax-reg 9498 and ax-inf 9548 / ax-inf2 9551? One candidate is mh-setind 36739, with 19 primitives. What is the shortest single axiom not using any wff variables? The conjunction of ax-reg 9498 + ax-tco 36675, expanded and slightly simplified, comes out to 46 primitives. Can we do better?

 
Theoremmh-setind 36739* Principle of set induction setind 9657, written with primitive symbols. (Contributed by Matthew House, 4-Mar-2026.)
(∀𝑦(∀𝑥(𝑥𝑦𝜑) → ∀𝑥(𝑥 = 𝑦𝜑)) → 𝜑)
 
Theoremmh-setindnd 36740 A version of mh-setind 36739 with no distinct variable conditions. (Contributed by Matthew House, 5-Mar-2026.) (New usage is discouraged.)
(∀𝑦(∀𝑥(𝑥𝑦𝜑) → ∀𝑥(𝑥 = 𝑦 → ∀𝑦𝜑)) → 𝜑)
 
Theoremregsfromregtco 36741* Derivation of ax-regs 35291 from ax-reg 9498 + ax-tco 36675. (Contributed by Matthew House, 4-Mar-2026.)
(∃𝑦 𝑦𝑤 → ∃𝑦(𝑦𝑤 ∧ ∀𝑧(𝑧𝑦 → ¬ 𝑧𝑤)))    &   𝑢(𝑣𝑢 ∧ ∀𝑡(𝑡𝑢 → ∀𝑠(𝑠𝑡𝑠𝑢)))       (∃𝑥𝜑 → ∃𝑦(∀𝑥(𝑥 = 𝑦𝜑) ∧ ∀𝑧(𝑧𝑦 → ¬ ∀𝑥(𝑥 = 𝑧𝜑))))
 
Theoremregsfromsetind 36742* Derivation of ax-regs 35291 from mh-setind 36739. (Contributed by Matthew House, 4-Mar-2026.)
(∀𝑦(∀𝑥(𝑥𝑦 → ¬ 𝜑) → ∀𝑥(𝑥 = 𝑦 → ¬ 𝜑)) → ¬ 𝜑)       (∃𝑥𝜑 → ∃𝑦(∀𝑥(𝑥 = 𝑦𝜑) ∧ ∀𝑧(𝑧𝑦 → ¬ ∀𝑥(𝑥 = 𝑧𝜑))))
 
Theoremregsfromunir1 36743* Derivation of ax-regs 35291 from unir1 9726. (Contributed by Matthew House, 4-Mar-2026.)
(𝑅1 “ On) = V       (∃𝑥𝜑 → ∃𝑦(∀𝑥(𝑥 = 𝑦𝜑) ∧ ∀𝑧(𝑧𝑦 → ¬ ∀𝑥(𝑥 = 𝑧𝜑))))
 
21.18  Mathbox for Asger C. Ipsen
 
21.18.1  Continuous nowhere differentiable functions
 
Theoremdnival 36744* Value of the "distance to nearest integer" function. (Contributed by Asger C. Ipsen, 4-Apr-2021.)
𝑇 = (𝑥 ∈ ℝ ↦ (abs‘((⌊‘(𝑥 + (1 / 2))) − 𝑥)))       (𝐴 ∈ ℝ → (𝑇𝐴) = (abs‘((⌊‘(𝐴 + (1 / 2))) − 𝐴)))
 
Theoremdnicld1 36745 Closure theorem for the "distance to nearest integer" function. (Contributed by Asger C. Ipsen, 4-Apr-2021.)
(𝜑𝐴 ∈ ℝ)       (𝜑 → (abs‘((⌊‘(𝐴 + (1 / 2))) − 𝐴)) ∈ ℝ)
 
Theoremdnicld2 36746* Closure theorem for the "distance to nearest integer" function. (Contributed by Asger C. Ipsen, 4-Apr-2021.)
𝑇 = (𝑥 ∈ ℝ ↦ (abs‘((⌊‘(𝑥 + (1 / 2))) − 𝑥)))    &   (𝜑𝐴 ∈ ℝ)       (𝜑 → (𝑇𝐴) ∈ ℝ)
 
Theoremdnif 36747 The "distance to nearest integer" function is a function. (Contributed by Asger C. Ipsen, 4-Apr-2021.)
𝑇 = (𝑥 ∈ ℝ ↦ (abs‘((⌊‘(𝑥 + (1 / 2))) − 𝑥)))       𝑇:ℝ⟶ℝ
 
Theoremdnizeq0 36748* The distance to nearest integer is zero for integers. (Contributed by Asger C. Ipsen, 15-Jun-2021.)
𝑇 = (𝑥 ∈ ℝ ↦ (abs‘((⌊‘(𝑥 + (1 / 2))) − 𝑥)))    &   (𝜑𝐴 ∈ ℤ)       (𝜑 → (𝑇𝐴) = 0)
 
Theoremdnizphlfeqhlf 36749* The distance to nearest integer is a half for half-integers. (Contributed by Asger C. Ipsen, 15-Jun-2021.)
𝑇 = (𝑥 ∈ ℝ ↦ (abs‘((⌊‘(𝑥 + (1 / 2))) − 𝑥)))    &   (𝜑𝐴 ∈ ℤ)       (𝜑 → (𝑇‘(𝐴 + (1 / 2))) = (1 / 2))
 
Theoremrddif2 36750 Variant of rddif 15292. (Contributed by Asger C. Ipsen, 4-Apr-2021.)
(𝐴 ∈ ℝ → 0 ≤ ((1 / 2) − (abs‘((⌊‘(𝐴 + (1 / 2))) − 𝐴))))
 
Theoremdnibndlem1 36751* Lemma for dnibnd 36764. (Contributed by Asger C. Ipsen, 4-Apr-2021.)
𝑇 = (𝑥 ∈ ℝ ↦ (abs‘((⌊‘(𝑥 + (1 / 2))) − 𝑥)))    &   (𝜑𝐴 ∈ ℝ)    &   (𝜑𝐵 ∈ ℝ)       (𝜑 → ((abs‘((𝑇𝐵) − (𝑇𝐴))) ≤ 𝑆 ↔ (abs‘((abs‘((⌊‘(𝐵 + (1 / 2))) − 𝐵)) − (abs‘((⌊‘(𝐴 + (1 / 2))) − 𝐴)))) ≤ 𝑆))
 
Theoremdnibndlem2 36752* Lemma for dnibnd 36764. (Contributed by Asger C. Ipsen, 4-Apr-2021.)
𝑇 = (𝑥 ∈ ℝ ↦ (abs‘((⌊‘(𝑥 + (1 / 2))) − 𝑥)))    &   (𝜑𝐴 ∈ ℝ)    &   (𝜑𝐵 ∈ ℝ)    &   (𝜑 → (⌊‘(𝐵 + (1 / 2))) = (⌊‘(𝐴 + (1 / 2))))       (𝜑 → (abs‘((𝑇𝐵) − (𝑇𝐴))) ≤ (abs‘(𝐵𝐴)))
 
Theoremdnibndlem3 36753 Lemma for dnibnd 36764. (Contributed by Asger C. Ipsen, 4-Apr-2021.)
𝑇 = (𝑥 ∈ ℝ ↦ (abs‘((⌊‘(𝑥 + (1 / 2))) − 𝑥)))    &   (𝜑𝐴 ∈ ℝ)    &   (𝜑𝐵 ∈ ℝ)    &   (𝜑 → (⌊‘(𝐵 + (1 / 2))) = ((⌊‘(𝐴 + (1 / 2))) + 1))       (𝜑 → (abs‘(𝐵𝐴)) = (abs‘((𝐵 − ((⌊‘(𝐵 + (1 / 2))) − (1 / 2))) + (((⌊‘(𝐴 + (1 / 2))) + (1 / 2)) − 𝐴))))
 
Theoremdnibndlem4 36754 Lemma for dnibnd 36764. (Contributed by Asger C. Ipsen, 4-Apr-2021.)
(𝐵 ∈ ℝ → 0 ≤ (𝐵 − ((⌊‘(𝐵 + (1 / 2))) − (1 / 2))))
 
Theoremdnibndlem5 36755 Lemma for dnibnd 36764. (Contributed by Asger C. Ipsen, 4-Apr-2021.)
(𝐴 ∈ ℝ → 0 < (((⌊‘(𝐴 + (1 / 2))) + (1 / 2)) − 𝐴))
 
Theoremdnibndlem6 36756 Lemma for dnibnd 36764. (Contributed by Asger C. Ipsen, 4-Apr-2021.)
(𝜑𝐴 ∈ ℝ)    &   (𝜑𝐵 ∈ ℝ)       (𝜑 → (abs‘((abs‘((⌊‘(𝐵 + (1 / 2))) − 𝐵)) − (abs‘((⌊‘(𝐴 + (1 / 2))) − 𝐴)))) ≤ (((1 / 2) − (abs‘((⌊‘(𝐵 + (1 / 2))) − 𝐵))) + ((1 / 2) − (abs‘((⌊‘(𝐴 + (1 / 2))) − 𝐴)))))
 
Theoremdnibndlem7 36757 Lemma for dnibnd 36764. (Contributed by Asger C. Ipsen, 4-Apr-2021.)
(𝜑𝐵 ∈ ℝ)       (𝜑 → ((1 / 2) − (abs‘((⌊‘(𝐵 + (1 / 2))) − 𝐵))) ≤ (𝐵 − ((⌊‘(𝐵 + (1 / 2))) − (1 / 2))))
 
Theoremdnibndlem8 36758 Lemma for dnibnd 36764. (Contributed by Asger C. Ipsen, 4-Apr-2021.)
(𝜑𝐴 ∈ ℝ)       (𝜑 → ((1 / 2) − (abs‘((⌊‘(𝐴 + (1 / 2))) − 𝐴))) ≤ (((⌊‘(𝐴 + (1 / 2))) + (1 / 2)) − 𝐴))
 
Theoremdnibndlem9 36759* Lemma for dnibnd 36764. (Contributed by Asger C. Ipsen, 4-Apr-2021.)
𝑇 = (𝑥 ∈ ℝ ↦ (abs‘((⌊‘(𝑥 + (1 / 2))) − 𝑥)))    &   (𝜑𝐴 ∈ ℝ)    &   (𝜑𝐵 ∈ ℝ)    &   (𝜑 → (⌊‘(𝐵 + (1 / 2))) = ((⌊‘(𝐴 + (1 / 2))) + 1))       (𝜑 → (abs‘((𝑇𝐵) − (𝑇𝐴))) ≤ (abs‘(𝐵𝐴)))
 
Theoremdnibndlem10 36760 Lemma for dnibnd 36764. (Contributed by Asger C. Ipsen, 4-Apr-2021.)
(𝜑𝐴 ∈ ℝ)    &   (𝜑𝐵 ∈ ℝ)    &   (𝜑 → ((⌊‘(𝐴 + (1 / 2))) + 2) ≤ (⌊‘(𝐵 + (1 / 2))))       (𝜑 → 1 ≤ (𝐵𝐴))
 
Theoremdnibndlem11 36761 Lemma for dnibnd 36764. (Contributed by Asger C. Ipsen, 4-Apr-2021.)
(𝜑𝐴 ∈ ℝ)    &   (𝜑𝐵 ∈ ℝ)       (𝜑 → (abs‘((abs‘((⌊‘(𝐵 + (1 / 2))) − 𝐵)) − (abs‘((⌊‘(𝐴 + (1 / 2))) − 𝐴)))) ≤ (1 / 2))
 
Theoremdnibndlem12 36762* Lemma for dnibnd 36764. (Contributed by Asger C. Ipsen, 4-Apr-2021.)
𝑇 = (𝑥 ∈ ℝ ↦ (abs‘((⌊‘(𝑥 + (1 / 2))) − 𝑥)))    &   (𝜑𝐴 ∈ ℝ)    &   (𝜑𝐵 ∈ ℝ)    &   (𝜑 → ((⌊‘(𝐴 + (1 / 2))) + 2) ≤ (⌊‘(𝐵 + (1 / 2))))       (𝜑 → (abs‘((𝑇𝐵) − (𝑇𝐴))) ≤ (abs‘(𝐵𝐴)))
 
Theoremdnibndlem13 36763* Lemma for dnibnd 36764. (Contributed by Asger C. Ipsen, 4-Apr-2021.)
𝑇 = (𝑥 ∈ ℝ ↦ (abs‘((⌊‘(𝑥 + (1 / 2))) − 𝑥)))    &   (𝜑𝐴 ∈ ℝ)    &   (𝜑𝐵 ∈ ℝ)    &   (𝜑 → (⌊‘(𝐴 + (1 / 2))) ≤ (⌊‘(𝐵 + (1 / 2))))       (𝜑 → (abs‘((𝑇𝐵) − (𝑇𝐴))) ≤ (abs‘(𝐵𝐴)))
 
Theoremdnibnd 36764* The "distance to nearest integer" function is 1-Lipschitz continuous, i.e., is a short map. (Contributed by Asger C. Ipsen, 4-Apr-2021.)
𝑇 = (𝑥 ∈ ℝ ↦ (abs‘((⌊‘(𝑥 + (1 / 2))) − 𝑥)))    &   (𝜑𝐴 ∈ ℝ)    &   (𝜑𝐵 ∈ ℝ)       (𝜑 → (abs‘((𝑇𝐵) − (𝑇𝐴))) ≤ (abs‘(𝐵𝐴)))
 
Theoremdnicn 36765 The "distance to nearest integer" function is continuous. (Contributed by Asger C. Ipsen, 4-Apr-2021.)
𝑇 = (𝑥 ∈ ℝ ↦ (abs‘((⌊‘(𝑥 + (1 / 2))) − 𝑥)))       𝑇 ∈ (ℝ–cn→ℝ)
 
Theoremknoppcnlem1 36766* Lemma for knoppcn 36777. (Contributed by Asger C. Ipsen, 4-Apr-2021.)
𝐹 = (𝑦 ∈ ℝ ↦ (𝑛 ∈ ℕ0 ↦ ((𝐶𝑛) · (𝑇‘(((2 · 𝑁)↑𝑛) · 𝑦)))))    &   (𝜑𝐴 ∈ ℝ)    &   (𝜑𝑀 ∈ ℕ0)       (𝜑 → ((𝐹𝐴)‘𝑀) = ((𝐶𝑀) · (𝑇‘(((2 · 𝑁)↑𝑀) · 𝐴))))
 
Theoremknoppcnlem2 36767* Lemma for knoppcn 36777. (Contributed by Asger C. Ipsen, 4-Apr-2021.) (Revised by Asger C. Ipsen, 5-Jul-2021.)
𝑇 = (𝑥 ∈ ℝ ↦ (abs‘((⌊‘(𝑥 + (1 / 2))) − 𝑥)))    &   (𝜑𝑁 ∈ ℕ)    &   (𝜑𝐶 ∈ ℝ)    &   (𝜑𝐴 ∈ ℝ)    &   (𝜑𝑀 ∈ ℕ0)       (𝜑 → ((𝐶𝑀) · (𝑇‘(((2 · 𝑁)↑𝑀) · 𝐴))) ∈ ℝ)
 
Theoremknoppcnlem3 36768* Lemma for knoppcn 36777. (Contributed by Asger C. Ipsen, 4-Apr-2021.) (Revised by Asger C. Ipsen, 5-Jul-2021.)
𝑇 = (𝑥 ∈ ℝ ↦ (abs‘((⌊‘(𝑥 + (1 / 2))) − 𝑥)))    &   𝐹 = (𝑦 ∈ ℝ ↦ (𝑛 ∈ ℕ0 ↦ ((𝐶𝑛) · (𝑇‘(((2 · 𝑁)↑𝑛) · 𝑦)))))    &   (𝜑𝑁 ∈ ℕ)    &   (𝜑𝐶 ∈ ℝ)    &   (𝜑𝐴 ∈ ℝ)    &   (𝜑𝑀 ∈ ℕ0)       (𝜑 → ((𝐹𝐴)‘𝑀) ∈ ℝ)
 
Theoremknoppcnlem4 36769* Lemma for knoppcn 36777. (Contributed by Asger C. Ipsen, 4-Apr-2021.) (Revised by Asger C. Ipsen, 5-Jul-2021.)
𝑇 = (𝑥 ∈ ℝ ↦ (abs‘((⌊‘(𝑥 + (1 / 2))) − 𝑥)))    &   𝐹 = (𝑦 ∈ ℝ ↦ (𝑛 ∈ ℕ0 ↦ ((𝐶𝑛) · (𝑇‘(((2 · 𝑁)↑𝑛) · 𝑦)))))    &   (𝜑𝑁 ∈ ℕ)    &   (𝜑𝐶 ∈ ℝ)    &   (𝜑𝐴 ∈ ℝ)    &   (𝜑𝑀 ∈ ℕ0)       (𝜑 → (abs‘((𝐹𝐴)‘𝑀)) ≤ ((𝑚 ∈ ℕ0 ↦ ((abs‘𝐶)↑𝑚))‘𝑀))
 
Theoremknoppcnlem5 36770* Lemma for knoppcn 36777. (Contributed by Asger C. Ipsen, 4-Apr-2021.) (Revised by Asger C. Ipsen, 5-Jul-2021.)
𝑇 = (𝑥 ∈ ℝ ↦ (abs‘((⌊‘(𝑥 + (1 / 2))) − 𝑥)))    &   𝐹 = (𝑦 ∈ ℝ ↦ (𝑛 ∈ ℕ0 ↦ ((𝐶𝑛) · (𝑇‘(((2 · 𝑁)↑𝑛) · 𝑦)))))    &   (𝜑𝑁 ∈ ℕ)    &   (𝜑𝐶 ∈ ℝ)       (𝜑 → (𝑚 ∈ ℕ0 ↦ (𝑧 ∈ ℝ ↦ ((𝐹𝑧)‘𝑚))):ℕ0⟶(ℂ ↑m ℝ))
 
Theoremknoppcnlem6 36771* Lemma for knoppcn 36777. (Contributed by Asger C. Ipsen, 4-Apr-2021.) (Revised by Asger C. Ipsen, 5-Jul-2021.)
𝑇 = (𝑥 ∈ ℝ ↦ (abs‘((⌊‘(𝑥 + (1 / 2))) − 𝑥)))    &   𝐹 = (𝑦 ∈ ℝ ↦ (𝑛 ∈ ℕ0 ↦ ((𝐶𝑛) · (𝑇‘(((2 · 𝑁)↑𝑛) · 𝑦)))))    &   (𝜑𝑁 ∈ ℕ)    &   (𝜑𝐶 ∈ ℝ)    &   (𝜑 → (abs‘𝐶) < 1)       (𝜑 → seq0( ∘f + , (𝑚 ∈ ℕ0 ↦ (𝑧 ∈ ℝ ↦ ((𝐹𝑧)‘𝑚)))) ∈ dom (⇝𝑢‘ℝ))
 
Theoremknoppcnlem7 36772* Lemma for knoppcn 36777. (Contributed by Asger C. Ipsen, 4-Apr-2021.) (Revised by Asger C. Ipsen, 5-Jul-2021.)
𝑇 = (𝑥 ∈ ℝ ↦ (abs‘((⌊‘(𝑥 + (1 / 2))) − 𝑥)))    &   𝐹 = (𝑦 ∈ ℝ ↦ (𝑛 ∈ ℕ0 ↦ ((𝐶𝑛) · (𝑇‘(((2 · 𝑁)↑𝑛) · 𝑦)))))    &   (𝜑𝑁 ∈ ℕ)    &   (𝜑𝐶 ∈ ℝ)    &   (𝜑𝑀 ∈ ℕ0)       (𝜑 → (seq0( ∘f + , (𝑚 ∈ ℕ0 ↦ (𝑧 ∈ ℝ ↦ ((𝐹𝑧)‘𝑚))))‘𝑀) = (𝑤 ∈ ℝ ↦ (seq0( + , (𝐹𝑤))‘𝑀)))
 
Theoremknoppcnlem8 36773* Lemma for knoppcn 36777. (Contributed by Asger C. Ipsen, 4-Apr-2021.) (Revised by Asger C. Ipsen, 5-Jul-2021.)
𝑇 = (𝑥 ∈ ℝ ↦ (abs‘((⌊‘(𝑥 + (1 / 2))) − 𝑥)))    &   𝐹 = (𝑦 ∈ ℝ ↦ (𝑛 ∈ ℕ0 ↦ ((𝐶𝑛) · (𝑇‘(((2 · 𝑁)↑𝑛) · 𝑦)))))    &   (𝜑𝑁 ∈ ℕ)    &   (𝜑𝐶 ∈ ℝ)       (𝜑 → seq0( ∘f + , (𝑚 ∈ ℕ0 ↦ (𝑧 ∈ ℝ ↦ ((𝐹𝑧)‘𝑚)))):ℕ0⟶(ℂ ↑m ℝ))
 
Theoremknoppcnlem9 36774* Lemma for knoppcn 36777. (Contributed by Asger C. Ipsen, 4-Apr-2021.) (Revised by Asger C. Ipsen, 5-Jul-2021.)
𝑇 = (𝑥 ∈ ℝ ↦ (abs‘((⌊‘(𝑥 + (1 / 2))) − 𝑥)))    &   𝐹 = (𝑦 ∈ ℝ ↦ (𝑛 ∈ ℕ0 ↦ ((𝐶𝑛) · (𝑇‘(((2 · 𝑁)↑𝑛) · 𝑦)))))    &   𝑊 = (𝑤 ∈ ℝ ↦ Σ𝑖 ∈ ℕ0 ((𝐹𝑤)‘𝑖))    &   (𝜑𝑁 ∈ ℕ)    &   (𝜑𝐶 ∈ ℝ)    &   (𝜑 → (abs‘𝐶) < 1)       (𝜑 → seq0( ∘f + , (𝑚 ∈ ℕ0 ↦ (𝑧 ∈ ℝ ↦ ((𝐹𝑧)‘𝑚))))(⇝𝑢‘ℝ)𝑊)
 
Theoremknoppcnlem10 36775* Lemma for knoppcn 36777. (Contributed by Asger C. Ipsen, 4-Apr-2021.) (Revised by Asger C. Ipsen, 5-Jul-2021.) Avoid ax-mulf 11107. (Revised by GG, 19-Apr-2025.)
𝑇 = (𝑥 ∈ ℝ ↦ (abs‘((⌊‘(𝑥 + (1 / 2))) − 𝑥)))    &   𝐹 = (𝑦 ∈ ℝ ↦ (𝑛 ∈ ℕ0 ↦ ((𝐶𝑛) · (𝑇‘(((2 · 𝑁)↑𝑛) · 𝑦)))))    &   (𝜑𝑁 ∈ ℕ)    &   (𝜑𝐶 ∈ ℝ)    &   (𝜑𝑀 ∈ ℕ0)       (𝜑 → (𝑧 ∈ ℝ ↦ ((𝐹𝑧)‘𝑀)) ∈ ((topGen‘ran (,)) Cn (TopOpen‘ℂfld)))
 
Theoremknoppcnlem11 36776* Lemma for knoppcn 36777. (Contributed by Asger C. Ipsen, 4-Apr-2021.) (Revised by Asger C. Ipsen, 5-Jul-2021.)
𝑇 = (𝑥 ∈ ℝ ↦ (abs‘((⌊‘(𝑥 + (1 / 2))) − 𝑥)))    &   𝐹 = (𝑦 ∈ ℝ ↦ (𝑛 ∈ ℕ0 ↦ ((𝐶𝑛) · (𝑇‘(((2 · 𝑁)↑𝑛) · 𝑦)))))    &   (𝜑𝑁 ∈ ℕ)    &   (𝜑𝐶 ∈ ℝ)       (𝜑 → seq0( ∘f + , (𝑚 ∈ ℕ0 ↦ (𝑧 ∈ ℝ ↦ ((𝐹𝑧)‘𝑚)))):ℕ0⟶(ℝ–cn→ℂ))
 
Theoremknoppcn 36777* The continuous nowhere differentiable function 𝑊 ( Knopp, K. (1918). Math. Z. 2, 1-26 ) is, in fact, continuous. (Contributed by Asger C. Ipsen, 4-Apr-2021.) (Revised by Asger C. Ipsen, 5-Jul-2021.)
𝑇 = (𝑥 ∈ ℝ ↦ (abs‘((⌊‘(𝑥 + (1 / 2))) − 𝑥)))    &   𝐹 = (𝑦 ∈ ℝ ↦ (𝑛 ∈ ℕ0 ↦ ((𝐶𝑛) · (𝑇‘(((2 · 𝑁)↑𝑛) · 𝑦)))))    &   𝑊 = (𝑤 ∈ ℝ ↦ Σ𝑖 ∈ ℕ0 ((𝐹𝑤)‘𝑖))    &   (𝜑𝑁 ∈ ℕ)    &   (𝜑𝐶 ∈ ℝ)    &   (𝜑 → (abs‘𝐶) < 1)       (𝜑𝑊 ∈ (ℝ–cn→ℂ))
 
Theoremknoppcld 36778* Closure theorem for Knopp's function. (Contributed by Asger C. Ipsen, 26-Jul-2021.)
𝑇 = (𝑥 ∈ ℝ ↦ (abs‘((⌊‘(𝑥 + (1 / 2))) − 𝑥)))    &   𝐹 = (𝑦 ∈ ℝ ↦ (𝑛 ∈ ℕ0 ↦ ((𝐶𝑛) · (𝑇‘(((2 · 𝑁)↑𝑛) · 𝑦)))))    &   𝑊 = (𝑤 ∈ ℝ ↦ Σ𝑖 ∈ ℕ0 ((𝐹𝑤)‘𝑖))    &   (𝜑𝐴 ∈ ℝ)    &   (𝜑𝑁 ∈ ℕ)    &   (𝜑𝐶 ∈ ℝ)    &   (𝜑 → (abs‘𝐶) < 1)       (𝜑 → (𝑊𝐴) ∈ ℂ)
 
Theoremunblimceq0lem 36779* Lemma for unblimceq0 36780. (Contributed by Asger C. Ipsen, 12-May-2021.)
(𝜑𝑆 ⊆ ℂ)    &   (𝜑𝐹:𝑆⟶ℂ)    &   (𝜑𝐴 ∈ ℂ)    &   (𝜑 → ∀𝑏 ∈ ℝ+𝑑 ∈ ℝ+𝑥𝑆 ((abs‘(𝑥𝐴)) < 𝑑𝑏 ≤ (abs‘(𝐹𝑥))))       (𝜑 → ∀𝑐 ∈ ℝ+𝑑 ∈ ℝ+𝑦𝑆 (𝑦𝐴 ∧ (abs‘(𝑦𝐴)) < 𝑑𝑐 ≤ (abs‘(𝐹𝑦))))
 
Theoremunblimceq0 36780* If 𝐹 is unbounded near 𝐴 it has no limit at 𝐴. (Contributed by Asger C. Ipsen, 12-May-2021.)
(𝜑𝑆 ⊆ ℂ)    &   (𝜑𝐹:𝑆⟶ℂ)    &   (𝜑𝐴 ∈ ℂ)    &   (𝜑 → ∀𝑏 ∈ ℝ+𝑑 ∈ ℝ+𝑥𝑆 ((abs‘(𝑥𝐴)) < 𝑑𝑏 ≤ (abs‘(𝐹𝑥))))       (𝜑 → (𝐹 lim 𝐴) = ∅)
 
Theoremunbdqndv1 36781* If the difference quotient (((𝐹𝑧) − (𝐹𝐴)) / (𝑧𝐴)) is unbounded near 𝐴 then 𝐹 is not differentiable at 𝐴. (Contributed by Asger C. Ipsen, 12-May-2021.)
𝐺 = (𝑧 ∈ (𝑋 ∖ {𝐴}) ↦ (((𝐹𝑧) − (𝐹𝐴)) / (𝑧𝐴)))    &   (𝜑𝑆 ⊆ ℂ)    &   (𝜑𝑋𝑆)    &   (𝜑𝐹:𝑋⟶ℂ)    &   (𝜑 → ∀𝑏 ∈ ℝ+𝑑 ∈ ℝ+𝑥 ∈ (𝑋 ∖ {𝐴})((abs‘(𝑥𝐴)) < 𝑑𝑏 ≤ (abs‘(𝐺𝑥))))       (𝜑 → ¬ 𝐴 ∈ dom (𝑆 D 𝐹))
 
Theoremunbdqndv2lem1 36782 Lemma for unbdqndv2 36784. (Contributed by Asger C. Ipsen, 12-May-2021.)
(𝜑𝐴 ∈ ℂ)    &   (𝜑𝐵 ∈ ℂ)    &   (𝜑𝐶 ∈ ℂ)    &   (𝜑𝐷 ∈ ℂ)    &   (𝜑𝐸 ∈ ℝ+)    &   (𝜑𝐷 ≠ 0)    &   (𝜑 → (2 · 𝐸) ≤ (abs‘((𝐴𝐵) / 𝐷)))       (𝜑 → ((𝐸 · (abs‘𝐷)) ≤ (abs‘(𝐴𝐶)) ∨ (𝐸 · (abs‘𝐷)) ≤ (abs‘(𝐵𝐶))))
 
Theoremunbdqndv2lem2 36783* Lemma for unbdqndv2 36784. (Contributed by Asger C. Ipsen, 12-May-2021.)
𝐺 = (𝑧 ∈ (𝑋 ∖ {𝐴}) ↦ (((𝐹𝑧) − (𝐹𝐴)) / (𝑧𝐴)))    &   𝑊 = if((𝐵 · (𝑉𝑈)) ≤ (abs‘((𝐹𝑈) − (𝐹𝐴))), 𝑈, 𝑉)    &   (𝜑𝑋 ⊆ ℝ)    &   (𝜑𝐹:𝑋⟶ℂ)    &   (𝜑𝐴𝑋)    &   (𝜑𝐵 ∈ ℝ+)    &   (𝜑𝐷 ∈ ℝ+)    &   (𝜑𝑈𝑋)    &   (𝜑𝑉𝑋)    &   (𝜑𝑈𝑉)    &   (𝜑𝑈𝐴)    &   (𝜑𝐴𝑉)    &   (𝜑 → (𝑉𝑈) < 𝐷)    &   (𝜑 → (2 · 𝐵) ≤ ((abs‘((𝐹𝑉) − (𝐹𝑈))) / (𝑉𝑈)))       (𝜑 → (𝑊 ∈ (𝑋 ∖ {𝐴}) ∧ ((abs‘(𝑊𝐴)) < 𝐷𝐵 ≤ (abs‘(𝐺𝑊)))))
 
Theoremunbdqndv2 36784* Variant of unbdqndv1 36781 with the hypothesis that (((𝐹𝑦) − (𝐹𝑥)) / (𝑦𝑥)) is unbounded where 𝑥𝐴 and 𝐴𝑦. (Contributed by Asger C. Ipsen, 12-May-2021.)
(𝜑𝑋 ⊆ ℝ)    &   (𝜑𝐹:𝑋⟶ℂ)    &   (𝜑 → ∀𝑏 ∈ ℝ+𝑑 ∈ ℝ+𝑥𝑋𝑦𝑋 ((𝑥𝐴𝐴𝑦) ∧ ((𝑦𝑥) < 𝑑𝑥𝑦) ∧ 𝑏 ≤ ((abs‘((𝐹𝑦) − (𝐹𝑥))) / (𝑦𝑥))))       (𝜑 → ¬ 𝐴 ∈ dom (ℝ D 𝐹))
 
Theoremknoppndvlem1 36785 Lemma for knoppndv 36807. (Contributed by Asger C. Ipsen, 15-Jun-2021.) (Revised by Asger C. Ipsen, 5-Jul-2021.)
(𝜑𝑁 ∈ ℕ)    &   (𝜑𝐽 ∈ ℤ)    &   (𝜑𝑀 ∈ ℤ)       (𝜑 → ((((2 · 𝑁)↑-𝐽) / 2) · 𝑀) ∈ ℝ)
 
Theoremknoppndvlem2 36786 Lemma for knoppndv 36807. (Contributed by Asger C. Ipsen, 15-Jun-2021.) (Revised by Asger C. Ipsen, 5-Jul-2021.)
(𝜑𝑁 ∈ ℕ)    &   (𝜑𝐼 ∈ ℤ)    &   (𝜑𝐽 ∈ ℤ)    &   (𝜑𝑀 ∈ ℤ)    &   (𝜑𝐽 < 𝐼)       (𝜑 → (((2 · 𝑁)↑𝐼) · ((((2 · 𝑁)↑-𝐽) / 2) · 𝑀)) ∈ ℤ)
 
Theoremknoppndvlem3 36787 Lemma for knoppndv 36807. (Contributed by Asger C. Ipsen, 15-Jun-2021.)
(𝜑𝐶 ∈ (-1(,)1))       (𝜑 → (𝐶 ∈ ℝ ∧ (abs‘𝐶) < 1))
 
Theoremknoppndvlem4 36788* Lemma for knoppndv 36807. (Contributed by Asger C. Ipsen, 15-Jun-2021.) (Revised by Asger C. Ipsen, 5-Jul-2021.)
𝑇 = (𝑥 ∈ ℝ ↦ (abs‘((⌊‘(𝑥 + (1 / 2))) − 𝑥)))    &   𝐹 = (𝑦 ∈ ℝ ↦ (𝑛 ∈ ℕ0 ↦ ((𝐶𝑛) · (𝑇‘(((2 · 𝑁)↑𝑛) · 𝑦)))))    &   𝑊 = (𝑤 ∈ ℝ ↦ Σ𝑖 ∈ ℕ0 ((𝐹𝑤)‘𝑖))    &   (𝜑𝐴 ∈ ℝ)    &   (𝜑𝐶 ∈ (-1(,)1))    &   (𝜑𝑁 ∈ ℕ)       (𝜑 → seq0( + , (𝐹𝐴)) ⇝ (𝑊𝐴))
 
Theoremknoppndvlem5 36789* Lemma for knoppndv 36807. (Contributed by Asger C. Ipsen, 15-Jun-2021.) (Revised by Asger C. Ipsen, 5-Jul-2021.)
𝑇 = (𝑥 ∈ ℝ ↦ (abs‘((⌊‘(𝑥 + (1 / 2))) − 𝑥)))    &   𝐹 = (𝑦 ∈ ℝ ↦ (𝑛 ∈ ℕ0 ↦ ((𝐶𝑛) · (𝑇‘(((2 · 𝑁)↑𝑛) · 𝑦)))))    &   (𝜑𝐴 ∈ ℝ)    &   (𝜑𝐶 ∈ ℝ)    &   (𝜑𝑁 ∈ ℕ)       (𝜑 → Σ𝑖 ∈ (0...𝐽)((𝐹𝐴)‘𝑖) ∈ ℝ)
 
Theoremknoppndvlem6 36790* Lemma for knoppndv 36807. (Contributed by Asger C. Ipsen, 15-Jun-2021.) (Revised by Asger C. Ipsen, 5-Jul-2021.)
𝑇 = (𝑥 ∈ ℝ ↦ (abs‘((⌊‘(𝑥 + (1 / 2))) − 𝑥)))    &   𝐹 = (𝑦 ∈ ℝ ↦ (𝑛 ∈ ℕ0 ↦ ((𝐶𝑛) · (𝑇‘(((2 · 𝑁)↑𝑛) · 𝑦)))))    &   𝑊 = (𝑤 ∈ ℝ ↦ Σ𝑖 ∈ ℕ0 ((𝐹𝑤)‘𝑖))    &   𝐴 = ((((2 · 𝑁)↑-𝐽) / 2) · 𝑀)    &   (𝜑𝐶 ∈ (-1(,)1))    &   (𝜑𝐽 ∈ ℕ0)    &   (𝜑𝑀 ∈ ℤ)    &   (𝜑𝑁 ∈ ℕ)       (𝜑 → (𝑊𝐴) = Σ𝑖 ∈ (0...𝐽)((𝐹𝐴)‘𝑖))
 
Theoremknoppndvlem7 36791* Lemma for knoppndv 36807. (Contributed by Asger C. Ipsen, 15-Jun-2021.) (Revised by Asger C. Ipsen, 5-Jul-2021.)
𝑇 = (𝑥 ∈ ℝ ↦ (abs‘((⌊‘(𝑥 + (1 / 2))) − 𝑥)))    &   𝐹 = (𝑦 ∈ ℝ ↦ (𝑛 ∈ ℕ0 ↦ ((𝐶𝑛) · (𝑇‘(((2 · 𝑁)↑𝑛) · 𝑦)))))    &   𝐴 = ((((2 · 𝑁)↑-𝐽) / 2) · 𝑀)    &   (𝜑𝐽 ∈ ℕ0)    &   (𝜑𝑀 ∈ ℤ)    &   (𝜑𝑁 ∈ ℕ)       (𝜑 → ((𝐹𝐴)‘𝐽) = ((𝐶𝐽) · (𝑇‘(𝑀 / 2))))
 
Theoremknoppndvlem8 36792* Lemma for knoppndv 36807. (Contributed by Asger C. Ipsen, 15-Jun-2021.) (Revised by Asger C. Ipsen, 5-Jul-2021.)
𝑇 = (𝑥 ∈ ℝ ↦ (abs‘((⌊‘(𝑥 + (1 / 2))) − 𝑥)))    &   𝐹 = (𝑦 ∈ ℝ ↦ (𝑛 ∈ ℕ0 ↦ ((𝐶𝑛) · (𝑇‘(((2 · 𝑁)↑𝑛) · 𝑦)))))    &   𝐴 = ((((2 · 𝑁)↑-𝐽) / 2) · 𝑀)    &   (𝜑𝐶 ∈ (-1(,)1))    &   (𝜑𝐽 ∈ ℕ0)    &   (𝜑𝑀 ∈ ℤ)    &   (𝜑𝑁 ∈ ℕ)    &   (𝜑 → 2 ∥ 𝑀)       (𝜑 → ((𝐹𝐴)‘𝐽) = 0)
 
Theoremknoppndvlem9 36793* Lemma for knoppndv 36807. (Contributed by Asger C. Ipsen, 15-Jun-2021.) (Revised by Asger C. Ipsen, 5-Jul-2021.)
𝑇 = (𝑥 ∈ ℝ ↦ (abs‘((⌊‘(𝑥 + (1 / 2))) − 𝑥)))    &   𝐹 = (𝑦 ∈ ℝ ↦ (𝑛 ∈ ℕ0 ↦ ((𝐶𝑛) · (𝑇‘(((2 · 𝑁)↑𝑛) · 𝑦)))))    &   𝐴 = ((((2 · 𝑁)↑-𝐽) / 2) · 𝑀)    &   (𝜑𝐶 ∈ (-1(,)1))    &   (𝜑𝐽 ∈ ℕ0)    &   (𝜑𝑀 ∈ ℤ)    &   (𝜑𝑁 ∈ ℕ)    &   (𝜑 → ¬ 2 ∥ 𝑀)       (𝜑 → ((𝐹𝐴)‘𝐽) = ((𝐶𝐽) / 2))
 
Theoremknoppndvlem10 36794* Lemma for knoppndv 36807. (Contributed by Asger C. Ipsen, 15-Jun-2021.) (Revised by Asger C. Ipsen, 5-Jul-2021.)
𝑇 = (𝑥 ∈ ℝ ↦ (abs‘((⌊‘(𝑥 + (1 / 2))) − 𝑥)))    &   𝐹 = (𝑦 ∈ ℝ ↦ (𝑛 ∈ ℕ0 ↦ ((𝐶𝑛) · (𝑇‘(((2 · 𝑁)↑𝑛) · 𝑦)))))    &   𝐴 = ((((2 · 𝑁)↑-𝐽) / 2) · 𝑀)    &   𝐵 = ((((2 · 𝑁)↑-𝐽) / 2) · (𝑀 + 1))    &   (𝜑𝐶 ∈ (-1(,)1))    &   (𝜑𝐽 ∈ ℕ0)    &   (𝜑𝑀 ∈ ℤ)    &   (𝜑𝑁 ∈ ℕ)       (𝜑 → (abs‘(((𝐹𝐵)‘𝐽) − ((𝐹𝐴)‘𝐽))) = (((abs‘𝐶)↑𝐽) / 2))
 
Theoremknoppndvlem11 36795* Lemma for knoppndv 36807. (Contributed by Asger C. Ipsen, 28-Jun-2021.) (Revised by Asger C. Ipsen, 5-Jul-2021.)
𝑇 = (𝑥 ∈ ℝ ↦ (abs‘((⌊‘(𝑥 + (1 / 2))) − 𝑥)))    &   𝐹 = (𝑦 ∈ ℝ ↦ (𝑛 ∈ ℕ0 ↦ ((𝐶𝑛) · (𝑇‘(((2 · 𝑁)↑𝑛) · 𝑦)))))    &   (𝜑𝐴 ∈ ℝ)    &   (𝜑𝐵 ∈ ℝ)    &   (𝜑𝐶 ∈ (-1(,)1))    &   (𝜑𝐽 ∈ ℕ0)    &   (𝜑𝑁 ∈ ℕ)       (𝜑 → (abs‘(Σ𝑖 ∈ (0...(𝐽 − 1))((𝐹𝐵)‘𝑖) − Σ𝑖 ∈ (0...(𝐽 − 1))((𝐹𝐴)‘𝑖))) ≤ ((abs‘(𝐵𝐴)) · Σ𝑖 ∈ (0...(𝐽 − 1))(((2 · 𝑁) · (abs‘𝐶))↑𝑖)))
 
Theoremknoppndvlem12 36796 Lemma for knoppndv 36807. (Contributed by Asger C. Ipsen, 29-Jun-2021.) (Revised by Asger C. Ipsen, 5-Jul-2021.)
(𝜑𝐶 ∈ (-1(,)1))    &   (𝜑𝑁 ∈ ℕ)    &   (𝜑 → 1 < (𝑁 · (abs‘𝐶)))       (𝜑 → (((2 · 𝑁) · (abs‘𝐶)) ≠ 1 ∧ 1 < (((2 · 𝑁) · (abs‘𝐶)) − 1)))
 
Theoremknoppndvlem13 36797 Lemma for knoppndv 36807. (Contributed by Asger C. Ipsen, 1-Jul-2021.) (Revised by Asger C. Ipsen, 5-Jul-2021.)
(𝜑𝐶 ∈ (-1(,)1))    &   (𝜑𝑁 ∈ ℕ)    &   (𝜑 → 1 < (𝑁 · (abs‘𝐶)))       (𝜑𝐶 ≠ 0)
 
Theoremknoppndvlem14 36798* Lemma for knoppndv 36807. (Contributed by Asger C. Ipsen, 1-Jul-2021.) (Revised by Asger C. Ipsen, 7-Jul-2021.)
𝑇 = (𝑥 ∈ ℝ ↦ (abs‘((⌊‘(𝑥 + (1 / 2))) − 𝑥)))    &   𝐹 = (𝑦 ∈ ℝ ↦ (𝑛 ∈ ℕ0 ↦ ((𝐶𝑛) · (𝑇‘(((2 · 𝑁)↑𝑛) · 𝑦)))))    &   𝐴 = ((((2 · 𝑁)↑-𝐽) / 2) · 𝑀)    &   𝐵 = ((((2 · 𝑁)↑-𝐽) / 2) · (𝑀 + 1))    &   (𝜑𝐶 ∈ (-1(,)1))    &   (𝜑𝐽 ∈ ℕ0)    &   (𝜑𝑀 ∈ ℤ)    &   (𝜑𝑁 ∈ ℕ)    &   (𝜑 → 1 < (𝑁 · (abs‘𝐶)))       (𝜑 → (abs‘(Σ𝑖 ∈ (0...(𝐽 − 1))((𝐹𝐵)‘𝑖) − Σ𝑖 ∈ (0...(𝐽 − 1))((𝐹𝐴)‘𝑖))) ≤ ((((abs‘𝐶)↑𝐽) / 2) · (1 / (((2 · 𝑁) · (abs‘𝐶)) − 1))))
 
Theoremknoppndvlem15 36799* Lemma for knoppndv 36807. (Contributed by Asger C. Ipsen, 6-Jul-2021.)
𝑇 = (𝑥 ∈ ℝ ↦ (abs‘((⌊‘(𝑥 + (1 / 2))) − 𝑥)))    &   𝐹 = (𝑦 ∈ ℝ ↦ (𝑛 ∈ ℕ0 ↦ ((𝐶𝑛) · (𝑇‘(((2 · 𝑁)↑𝑛) · 𝑦)))))    &   𝑊 = (𝑤 ∈ ℝ ↦ Σ𝑖 ∈ ℕ0 ((𝐹𝑤)‘𝑖))    &   𝐴 = ((((2 · 𝑁)↑-𝐽) / 2) · 𝑀)    &   𝐵 = ((((2 · 𝑁)↑-𝐽) / 2) · (𝑀 + 1))    &   (𝜑𝐶 ∈ (-1(,)1))    &   (𝜑𝐽 ∈ ℕ0)    &   (𝜑𝑀 ∈ ℤ)    &   (𝜑𝑁 ∈ ℕ)    &   (𝜑 → 1 < (𝑁 · (abs‘𝐶)))       (𝜑 → ((((abs‘𝐶)↑𝐽) / 2) · (1 − (1 / (((2 · 𝑁) · (abs‘𝐶)) − 1)))) ≤ (abs‘((𝑊𝐵) − (𝑊𝐴))))
 
Theoremknoppndvlem16 36800 Lemma for knoppndv 36807. (Contributed by Asger C. Ipsen, 19-Jul-2021.)
𝐴 = ((((2 · 𝑁)↑-𝐽) / 2) · 𝑀)    &   𝐵 = ((((2 · 𝑁)↑-𝐽) / 2) · (𝑀 + 1))    &   (𝜑𝐽 ∈ ℕ0)    &   (𝜑𝑀 ∈ ℤ)    &   (𝜑𝑁 ∈ ℕ)       (𝜑 → (𝐵𝐴) = (((2 · 𝑁)↑-𝐽) / 2))
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