Theorem ifpxorxorb 41118

Description: Factor conditional logic operator over xor in terms 2 and 3. (Contributed by RP, 21-Apr-2020.)

Assertion

Ref	Expression
ifpxorxorb	⊢ (if-(𝜑, (𝜓 ⊻ 𝜒), (𝜃 ⊻ 𝜏)) ↔ (if-(𝜑, 𝜓, 𝜃) ⊻ if-(𝜑, 𝜒, 𝜏)))

Proof of Theorem ifpxorxorb

Step	Hyp	Ref	Expression
1		df-xor 1507	. . 3 ⊢ ((𝜓 ⊻ 𝜒) ↔ ¬ (𝜓 ↔ 𝜒))
2		df-xor 1507	. . 3 ⊢ ((𝜃 ⊻ 𝜏) ↔ ¬ (𝜃 ↔ 𝜏))
3		ifpbi23 41080	. . 3 ⊢ ((((𝜓 ⊻ 𝜒) ↔ ¬ (𝜓 ↔ 𝜒)) ∧ ((𝜃 ⊻ 𝜏) ↔ ¬ (𝜃 ↔ 𝜏))) → (if-(𝜑, (𝜓 ⊻ 𝜒), (𝜃 ⊻ 𝜏)) ↔ if-(𝜑, ¬ (𝜓 ↔ 𝜒), ¬ (𝜃 ↔ 𝜏))))
4	1, 2, 3	mp2an 689	. 2 ⊢ (if-(𝜑, (𝜓 ⊻ 𝜒), (𝜃 ⊻ 𝜏)) ↔ if-(𝜑, ¬ (𝜓 ↔ 𝜒), ¬ (𝜃 ↔ 𝜏)))
5		ifpbibib 41117	. . . 4 ⊢ (if-(𝜑, (𝜓 ↔ 𝜒), (𝜃 ↔ 𝜏)) ↔ (if-(𝜑, 𝜓, 𝜃) ↔ if-(𝜑, 𝜒, 𝜏)))
6	5	notbii 320	. . 3 ⊢ (¬ if-(𝜑, (𝜓 ↔ 𝜒), (𝜃 ↔ 𝜏)) ↔ ¬ (if-(𝜑, 𝜓, 𝜃) ↔ if-(𝜑, 𝜒, 𝜏)))
7		ifpnotnotb 41086	. . 3 ⊢ (if-(𝜑, ¬ (𝜓 ↔ 𝜒), ¬ (𝜃 ↔ 𝜏)) ↔ ¬ if-(𝜑, (𝜓 ↔ 𝜒), (𝜃 ↔ 𝜏)))
8		df-xor 1507	. . 3 ⊢ ((if-(𝜑, 𝜓, 𝜃) ⊻ if-(𝜑, 𝜒, 𝜏)) ↔ ¬ (if-(𝜑, 𝜓, 𝜃) ↔ if-(𝜑, 𝜒, 𝜏)))
9	6, 7, 8	3bitr4i 303	. 2 ⊢ (if-(𝜑, ¬ (𝜓 ↔ 𝜒), ¬ (𝜃 ↔ 𝜏)) ↔ (if-(𝜑, 𝜓, 𝜃) ⊻ if-(𝜑, 𝜒, 𝜏)))
10	4, 9	bitri 274	1 ⊢ (if-(𝜑, (𝜓 ⊻ 𝜒), (𝜃 ⊻ 𝜏)) ↔ (if-(𝜑, 𝜓, 𝜃) ⊻ if-(𝜑, 𝜒, 𝜏)))

Syntax hints:  ¬ wn 3   ↔ wb 205  if-wif 1060   ⊻ wxo 1506

This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8

This theorem depends on definitions:  df-bi 206  df-an 397  df-or 845  df-ifp 1061  df-xor 1507

This theorem is referenced by: (None)