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Theorem List for Metamath Proof Explorer - 43001-43100   *Has distinct variable group(s)
TypeLabelDescription
Statement
 
Theoremfzsplitnr 43001 Split a finite interval of integers into two parts. (Contributed by metakunt, 28-May-2024.)
(𝜑 → 𝑀 ∈ ℤ)    &   (𝜑 → 𝑁 ∈ ℤ)    &   (𝜑 → 𝐾 ∈ ℤ)    &   (𝜑 → 𝑀 ≤ 𝐾)    &   (𝜑 → 𝐾 ≤ 𝑁)    ⇒   (𝜑 → (𝑀...𝑁) = ((𝑀...(𝐾 − 1)) ∪ (𝐾...𝑁)))
 
Theoremaddassnni 43002 Associative law for addition. (Contributed by metakunt, 25-Apr-2024.)
𝐴 ∈ ℕ    &   𝐵 ∈ ℕ    &   𝐶 ∈ ℕ    ⇒   ((𝐴 + 𝐵) + 𝐶) = (𝐴 + (𝐵 + 𝐶))
 
Theoremaddcomnni 43003 Commutative law for addition. (Contributed by metakunt, 25-Apr-2024.)
𝐴 ∈ ℕ    &   𝐵 ∈ ℕ    ⇒   (𝐴 + 𝐵) = (𝐵 + 𝐴)
 
Theoremmulassnni 43004 Associative law for multiplication. (Contributed by metakunt, 25-Apr-2024.)
𝐴 ∈ ℕ    &   𝐵 ∈ ℕ    &   𝐶 ∈ ℕ    ⇒   ((𝐴 · 𝐵) · 𝐶) = (𝐴 · (𝐵 · 𝐶))
 
Theoremmulcomnni 43005 Commutative law for multiplication. (Contributed by metakunt, 25-Apr-2024.)
𝐴 ∈ ℕ    &   𝐵 ∈ ℕ    ⇒   (𝐴 · 𝐵) = (𝐵 · 𝐴)
 
Theoremgcdcomnni 43006 Commutative law for gcd. (Contributed by metakunt, 25-Apr-2024.)
𝑀 ∈ ℕ    &   𝑁 ∈ ℕ    ⇒   (𝑀 gcd 𝑁) = (𝑁 gcd 𝑀)
 
Theoremgcdnegnni 43007 Negation invariance for gcd. (Contributed by metakunt, 25-Apr-2024.)
𝑀 ∈ ℕ    &   𝑁 ∈ ℕ    ⇒   (𝑀 gcd -𝑁) = (𝑀 gcd 𝑁)
 
Theoremneggcdnni 43008 Negation invariance for gcd. (Contributed by metakunt, 25-Apr-2024.)
𝑀 ∈ ℕ    &   𝑁 ∈ ℕ    ⇒   (-𝑀 gcd 𝑁) = (𝑀 gcd 𝑁)
 
Theorembccl2d 43009 Closure of the binomial coefficient, a deduction version. (Contributed by metakunt, 12-May-2024.)
(𝜑 → 𝑁 ∈ ℕ)    &   (𝜑 → 𝐾 ∈ ℕ0)    &   (𝜑 → 𝐾 ≤ 𝑁)    ⇒   (𝜑 → (𝑁C𝐾) ∈ ℕ)
 
Theoremrecbothd 43010 Take reciprocal on both sides. (Contributed by metakunt, 12-May-2024.)
(𝜑 → 𝐴 ∈ ℂ)    &   (𝜑 → 𝐴 ≠ 0)    &   (𝜑 → 𝐵 ∈ ℂ)    &   (𝜑 → 𝐵 ≠ 0)    &   (𝜑 → 𝐶 ∈ ℂ)    &   (𝜑 → 𝐶 ≠ 0)    &   (𝜑 → 𝐷 ∈ ℂ)    &   (𝜑 → 𝐷 ≠ 0)    ⇒   (𝜑 → ((𝐴 / 𝐵) = (𝐶 / 𝐷) ↔ (𝐵 / 𝐴) = (𝐷 / 𝐶)))
 
Theoremgcdmultiplei 43011 The GCD of a multiple of a positive integer is the positive integer itself. (Contributed by metakunt, 25-Apr-2024.)
𝑀 ∈ ℕ    &   𝑁 ∈ ℕ    ⇒   (𝑀 gcd (𝑀 · 𝑁)) = 𝑀
 
Theoremgcdaddmzz2nni 43012 Adding a multiple of one operand of the gcd operator to the other does not alter the result. (Contributed by metakunt, 25-Apr-2024.)
𝑀 ∈ ℕ    &   𝑁 ∈ ℕ    &   𝐾 ∈ ℤ    ⇒   (𝑀 gcd 𝑁) = (𝑀 gcd (𝑁 + (𝐾 · 𝑀)))
 
Theoremgcdaddmzz2nncomi 43013 Adding a multiple of one operand of the gcd operator to the other does not alter the result. (Contributed by metakunt, 25-Apr-2024.)
𝑀 ∈ ℕ    &   𝑁 ∈ ℕ    &   𝐾 ∈ ℤ    ⇒   (𝑀 gcd 𝑁) = (𝑀 gcd ((𝐾 · 𝑀) + 𝑁))
 
Theoremgcdnncli 43014 Closure of the gcd operator. (Contributed by metakunt, 25-Apr-2024.)
𝑀 ∈ ℕ    &   𝑁 ∈ ℕ    ⇒   (𝑀 gcd 𝑁) ∈ ℕ
 
Theoremmuldvds1d 43015 If a product divides an integer, so does one of its factors, a deduction version. (Contributed by metakunt, 12-May-2024.)
(𝜑 → 𝐾 ∈ ℤ)    &   (𝜑 → 𝑀 ∈ ℤ)    &   (𝜑 → 𝑁 ∈ ℤ)    &   (𝜑 → (𝐾 · 𝑀) ∥ 𝑁)    ⇒   (𝜑 → 𝐾 ∥ 𝑁)
 
Theoremmuldvds2d 43016 If a product divides an integer, so does one of its factors, a deduction version. (Contributed by metakunt, 12-May-2024.)
(𝜑 → 𝐾 ∈ ℤ)    &   (𝜑 → 𝑀 ∈ ℤ)    &   (𝜑 → 𝑁 ∈ ℤ)    &   (𝜑 → (𝐾 · 𝑀) ∥ 𝑁)    ⇒   (𝜑 → 𝑀 ∥ 𝑁)
 
Theoremnndivdvdsd 43017 A positive integer divides a natural number if and only if the quotient is a positive integer, a deduction version of nndivdvds 16411. (Contributed by metakunt, 12-May-2024.)
(𝜑 → 𝑀 ∈ ℕ)    &   (𝜑 → 𝑁 ∈ ℕ)    ⇒   (𝜑 → (𝑀 ∥ 𝑁 ↔ (𝑁 / 𝑀) ∈ ℕ))
 
Theoremnnproddivdvdsd 43018 A product of natural numbers divides a natural number if and only if a factor divides the quotient, a deduction version. (Contributed by metakunt, 12-May-2024.)
(𝜑 → 𝐾 ∈ ℕ)    &   (𝜑 → 𝑀 ∈ ℕ)    &   (𝜑 → 𝑁 ∈ ℕ)    ⇒   (𝜑 → ((𝐾 · 𝑀) ∥ 𝑁 ↔ 𝐾 ∥ (𝑁 / 𝑀)))
 
Theoremcoprmdvds2d 43019 If an integer is divisible by two coprime integers, then it is divisible by their product, a deduction version. (Contributed by metakunt, 12-May-2024.)
(𝜑 → 𝐾 ∈ ℤ)    &   (𝜑 → 𝑀 ∈ ℤ)    &   (𝜑 → 𝑁 ∈ ℤ)    &   (𝜑 → (𝐾 gcd 𝑀) = 1)    &   (𝜑 → 𝐾 ∥ 𝑁)    &   (𝜑 → 𝑀 ∥ 𝑁)    ⇒   (𝜑 → (𝐾 · 𝑀) ∥ 𝑁)
 
Theoremimadomfi 43020 An image of a function under a finite set is dominated by the set. (Contributed by SN, 10-May-2025.)
((𝐴 ∈ Fin ∧ Fun 𝐹) → (𝐹 “ 𝐴) ≼ 𝐴)
 
21.30.3  Some gcd and lcm results
 
Theorem12gcd5e1 43021 The gcd of 12 and 5 is 1. (Contributed by metakunt, 25-Apr-2024.)
(12 gcd 5) = 1
 
Theorem60gcd6e6 43022 The gcd of 60 and 6 is 6. (Contributed by metakunt, 25-Apr-2024.)
(60 gcd 6) = 6
 
Theorem60gcd7e1 43023 The gcd of 60 and 7 is 1. (Contributed by metakunt, 25-Apr-2024.)
(60 gcd 7) = 1
 
Theorem420gcd8e4 43024 The gcd of 420 and 8 is 4. (Contributed by metakunt, 25-Apr-2024.)
(420 gcd 8) = 4
 
Theoremlcmeprodgcdi 43025 Calculate the least common multiple of two natural numbers. (Contributed by metakunt, 25-Apr-2024.)
𝑀 ∈ ℕ    &   𝑁 ∈ ℕ    &   𝐺 ∈ ℕ    &   𝐻 ∈ ℕ    &   (𝑀 gcd 𝑁) = 𝐺    &   (𝐺 · 𝐻) = 𝐴    &   (𝑀 · 𝑁) = 𝐴    ⇒   (𝑀 lcm 𝑁) = 𝐻
 
Theorem12lcm5e60 43026 The lcm of 12 and 5 is 60. (Contributed by metakunt, 25-Apr-2024.)
(12 lcm 5) = 60
 
Theorem60lcm6e60 43027 The lcm of 60 and 6 is 60. (Contributed by metakunt, 25-Apr-2024.)
(60 lcm 6) = 60
 
Theorem60lcm7e420 43028 The lcm of 60 and 7 is 420. (Contributed by metakunt, 25-Apr-2024.)
(60 lcm 7) = 420
 
Theorem420lcm8e840 43029 The lcm of 420 and 8 is 840. (Contributed by metakunt, 25-Apr-2024.)
(420 lcm 8) = 840
 
Theoremlcmfunnnd 43030 Useful equation to calculate the least common multiple of 1 to n. (Contributed by metakunt, 29-Apr-2024.)
(𝜑 → 𝑁 ∈ ℕ)    ⇒   (𝜑 → (lcm‘(1...𝑁)) = ((lcm‘(1...(𝑁 − 1))) lcm 𝑁))
 
Theoremlcm1un 43031 Least common multiple of natural numbers up to 1 equals 1. (Contributed by metakunt, 25-Apr-2024.)
(lcm‘(1...1)) = 1
 
Theoremlcm2un 43032 Least common multiple of natural numbers up to 2 equals 2. (Contributed by metakunt, 25-Apr-2024.)
(lcm‘(1...2)) = 2
 
Theoremlcm3un 43033 Least common multiple of natural numbers up to 3 equals 6. (Contributed by metakunt, 25-Apr-2024.)
(lcm‘(1...3)) = 6
 
Theoremlcm4un 43034 Least common multiple of natural numbers up to 4 equals 12. (Contributed by metakunt, 25-Apr-2024.)
(lcm‘(1...4)) = 12
 
Theoremlcm5un 43035 Least common multiple of natural numbers up to 5 equals 60. (Contributed by metakunt, 25-Apr-2024.)
(lcm‘(1...5)) = 60
 
Theoremlcm6un 43036 Least common multiple of natural numbers up to 6 equals 60. (Contributed by metakunt, 25-Apr-2024.)
(lcm‘(1...6)) = 60
 
Theoremlcm7un 43037 Least common multiple of natural numbers up to 7 equals 420. (Contributed by metakunt, 25-Apr-2024.)
(lcm‘(1...7)) = 420
 
Theoremlcm8un 43038 Least common multiple of natural numbers up to 8 equals 840. (Contributed by metakunt, 25-Apr-2024.)
(lcm‘(1...8)) = 840
 
21.30.4  Least common multiple inequality theorem
 
Theorem3factsumint1 43039* Move constants out of integrals or sums and/or commute sum and integral. (Contributed by metakunt, 26-Apr-2024.)
𝐴 = (𝐿[,]𝑈)    &   (𝜑 → 𝐵 ∈ Fin)    &   (𝜑 → 𝐿 ∈ ℝ)    &   (𝜑 → 𝑈 ∈ ℝ)    &   ((𝜑 ∧ 𝑥 ∈ 𝐴) → 𝐹 ∈ ℂ)    &   (𝜑 → (𝑥 ∈ 𝐴 ↦ 𝐹) ∈ (𝐴–cn→ℂ))    &   ((𝜑 ∧ 𝑘 ∈ 𝐵) → 𝐺 ∈ ℂ)    &   ((𝜑 ∧ (𝑥 ∈ 𝐴 ∧ 𝑘 ∈ 𝐵)) → 𝐻 ∈ ℂ)    &   ((𝜑 ∧ 𝑘 ∈ 𝐵) → (𝑥 ∈ 𝐴 ↦ 𝐻) ∈ (𝐴–cn→ℂ))    ⇒   (𝜑 → ∫𝐴Σ𝑘 ∈ 𝐵 (𝐹 · (𝐺 · 𝐻)) d𝑥 = Σ𝑘 ∈ 𝐵 ∫𝐴(𝐹 · (𝐺 · 𝐻)) d𝑥)
 
Theorem3factsumint2 43040* Move constants out of integrals or sums and/or commute sum and integral. (Contributed by metakunt, 26-Apr-2024.)
((𝜑 ∧ 𝑥 ∈ 𝐴) → 𝐹 ∈ ℂ)    &   ((𝜑 ∧ 𝑘 ∈ 𝐵) → 𝐺 ∈ ℂ)    &   ((𝜑 ∧ (𝑥 ∈ 𝐴 ∧ 𝑘 ∈ 𝐵)) → 𝐻 ∈ ℂ)    ⇒   (𝜑 → Σ𝑘 ∈ 𝐵 ∫𝐴(𝐹 · (𝐺 · 𝐻)) d𝑥 = Σ𝑘 ∈ 𝐵 ∫𝐴(𝐺 · (𝐹 · 𝐻)) d𝑥)
 
Theorem3factsumint3 43041* Move constants out of integrals or sums and/or commute sum and integral. (Contributed by metakunt, 26-Apr-2024.)
𝐴 = (𝐿[,]𝑈)    &   (𝜑 → 𝐿 ∈ ℝ)    &   (𝜑 → 𝑈 ∈ ℝ)    &   ((𝜑 ∧ 𝑥 ∈ 𝐴) → 𝐹 ∈ ℂ)    &   (𝜑 → (𝑥 ∈ 𝐴 ↦ 𝐹) ∈ (𝐴–cn→ℂ))    &   ((𝜑 ∧ 𝑘 ∈ 𝐵) → 𝐺 ∈ ℂ)    &   ((𝜑 ∧ (𝑥 ∈ 𝐴 ∧ 𝑘 ∈ 𝐵)) → 𝐻 ∈ ℂ)    &   ((𝜑 ∧ 𝑘 ∈ 𝐵) → (𝑥 ∈ 𝐴 ↦ 𝐻) ∈ (𝐴–cn→ℂ))    ⇒   (𝜑 → Σ𝑘 ∈ 𝐵 ∫𝐴(𝐺 · (𝐹 · 𝐻)) d𝑥 = Σ𝑘 ∈ 𝐵 (𝐺 · ∫𝐴(𝐹 · 𝐻) d𝑥))
 
Theorem3factsumint4 43042* Move constants out of integrals or sums and/or commute sum and integral. (Contributed by metakunt, 26-Apr-2024.)
(𝜑 → 𝐵 ∈ Fin)    &   ((𝜑 ∧ 𝑥 ∈ 𝐴) → 𝐹 ∈ ℂ)    &   ((𝜑 ∧ 𝑘 ∈ 𝐵) → 𝐺 ∈ ℂ)    &   ((𝜑 ∧ (𝑥 ∈ 𝐴 ∧ 𝑘 ∈ 𝐵)) → 𝐻 ∈ ℂ)    ⇒   (𝜑 → ∫𝐴Σ𝑘 ∈ 𝐵 (𝐹 · (𝐺 · 𝐻)) d𝑥 = ∫𝐴(𝐹 · Σ𝑘 ∈ 𝐵 (𝐺 · 𝐻)) d𝑥)
 
Theorem3factsumint 43043* Helpful equation for lcm inequality proof. (Contributed by metakunt, 26-Apr-2024.)
𝐴 = (𝐿[,]𝑈)    &   (𝜑 → 𝐵 ∈ Fin)    &   (𝜑 → 𝐿 ∈ ℝ)    &   (𝜑 → 𝑈 ∈ ℝ)    &   (𝜑 → (𝑥 ∈ 𝐴 ↦ 𝐹) ∈ (𝐴–cn→ℂ))    &   ((𝜑 ∧ 𝑘 ∈ 𝐵) → 𝐺 ∈ ℂ)    &   ((𝜑 ∧ 𝑘 ∈ 𝐵) → (𝑥 ∈ 𝐴 ↦ 𝐻) ∈ (𝐴–cn→ℂ))    ⇒   (𝜑 → ∫𝐴(𝐹 · Σ𝑘 ∈ 𝐵 (𝐺 · 𝐻)) d𝑥 = Σ𝑘 ∈ 𝐵 (𝐺 · ∫𝐴(𝐹 · 𝐻) d𝑥))
 
Theoremresopunitintvd 43044 Restrict continuous function on open unit interval. (Contributed by metakunt, 12-May-2024.)
(𝜑 → (𝑥 ∈ ℂ ↦ 𝐴) ∈ (ℂ–cn→ℂ))    ⇒   (𝜑 → (𝑥 ∈ (0(,)1) ↦ 𝐴) ∈ ((0(,)1)–cn→ℂ))
 
Theoremresclunitintvd 43045 Restrict continuous function on closed unit interval. (Contributed by metakunt, 12-May-2024.)
(𝜑 → (𝑥 ∈ ℂ ↦ 𝐴) ∈ (ℂ–cn→ℂ))    ⇒   (𝜑 → (𝑥 ∈ (0[,]1) ↦ 𝐴) ∈ ((0[,]1)–cn→ℂ))
 
Theoremresdvopclptsd 43046* Restrict derivative on unit interval. (Contributed by metakunt, 12-May-2024.)
(𝜑 → (ℂ D (𝑥 ∈ ℂ ↦ 𝐴)) = (𝑥 ∈ ℂ ↦ 𝐵))    &   ((𝜑 ∧ 𝑥 ∈ ℂ) → 𝐴 ∈ ℂ)    &   ((𝜑 ∧ 𝑥 ∈ ℂ) → 𝐵 ∈ ℂ)    ⇒   (𝜑 → (ℝ D (𝑥 ∈ (0[,]1) ↦ 𝐴)) = (𝑥 ∈ (0(,)1) ↦ 𝐵))
 
Theoremlcmineqlem1 43047* Part of lcm inequality lemma, this part eventually shows that F times the least common multiple of 1 to n is an integer. (Contributed by metakunt, 29-Apr-2024.)
𝐹 = ∫(0[,]1)((𝑥↑(𝑀 − 1)) · ((1 − 𝑥)↑(𝑁 − 𝑀))) d𝑥    &   (𝜑 → 𝑁 ∈ ℕ)    &   (𝜑 → 𝑀 ∈ ℕ)    &   (𝜑 → 𝑀 ≤ 𝑁)    ⇒   (𝜑 → 𝐹 = ∫(0[,]1)((𝑥↑(𝑀 − 1)) · Σ𝑘 ∈ (0...(𝑁 − 𝑀))(((-1↑𝑘) · ((𝑁 − 𝑀)C𝑘)) · (𝑥↑𝑘))) d𝑥)
 
Theoremlcmineqlem2 43048* Part of lcm inequality lemma, this part eventually shows that F times the least common multiple of 1 to n is an integer. (Contributed by metakunt, 29-Apr-2024.)
𝐹 = ∫(0[,]1)((𝑥↑(𝑀 − 1)) · ((1 − 𝑥)↑(𝑁 − 𝑀))) d𝑥    &   (𝜑 → 𝑁 ∈ ℕ)    &   (𝜑 → 𝑀 ∈ ℕ)    &   (𝜑 → 𝑀 ≤ 𝑁)    ⇒   (𝜑 → 𝐹 = Σ𝑘 ∈ (0...(𝑁 − 𝑀))(((-1↑𝑘) · ((𝑁 − 𝑀)C𝑘)) · ∫(0[,]1)((𝑥↑(𝑀 − 1)) · (𝑥↑𝑘)) d𝑥))
 
Theoremlcmineqlem3 43049* Part of lcm inequality lemma, this part eventually shows that F times the least common multiple of 1 to n is an integer. (Contributed by metakunt, 30-Apr-2024.)
𝐹 = ∫(0[,]1)((𝑥↑(𝑀 − 1)) · ((1 − 𝑥)↑(𝑁 − 𝑀))) d𝑥    &   (𝜑 → 𝑁 ∈ ℕ)    &   (𝜑 → 𝑀 ∈ ℕ)    &   (𝜑 → 𝑀 ≤ 𝑁)    ⇒   (𝜑 → 𝐹 = Σ𝑘 ∈ (0...(𝑁 − 𝑀))(((-1↑𝑘) · ((𝑁 − 𝑀)C𝑘)) · (1 / (𝑀 + 𝑘))))
 
Theoremlcmineqlem4 43050 Part of lcm inequality lemma, this part eventually shows that F times the least common multiple of 1 to n is an integer. F is found in lcmineqlem6 43052. (Contributed by metakunt, 10-May-2024.)
(𝜑 → 𝑁 ∈ ℕ)    &   (𝜑 → 𝑀 ∈ ℕ)    &   (𝜑 → 𝑀 ≤ 𝑁)    &   (𝜑 → 𝐾 ∈ (0...(𝑁 − 𝑀)))    ⇒   (𝜑 → ((lcm‘(1...𝑁)) / (𝑀 + 𝐾)) ∈ ℤ)
 
Theoremlcmineqlem5 43051 Technical lemma for reciprocal multiplication in deduction form. (Contributed by metakunt, 10-May-2024.)
(𝜑 → 𝐴 ∈ ℂ)    &   (𝜑 → 𝐵 ∈ ℂ)    &   (𝜑 → 𝐶 ∈ ℂ)    &   (𝜑 → 𝐶 ≠ 0)    ⇒   (𝜑 → (𝐴 · (𝐵 · (1 / 𝐶))) = (𝐵 · (𝐴 / 𝐶)))
 
Theoremlcmineqlem6 43052* Part of lcm inequality lemma, this part eventually shows that F times the least common multiple of 1 to n is an integer. (Contributed by metakunt, 10-May-2024.)
𝐹 = ∫(0[,]1)((𝑥↑(𝑀 − 1)) · ((1 − 𝑥)↑(𝑁 − 𝑀))) d𝑥    &   (𝜑 → 𝑁 ∈ ℕ)    &   (𝜑 → 𝑀 ∈ ℕ)    &   (𝜑 → 𝑀 ≤ 𝑁)    ⇒   (𝜑 → ((lcm‘(1...𝑁)) · 𝐹) ∈ ℤ)
 
Theoremlcmineqlem7 43053 Derivative of 1-x for chain rule application. (Contributed by metakunt, 12-May-2024.)
(ℂ D (𝑥 ∈ ℂ ↦ (1 − 𝑥))) = (𝑥 ∈ ℂ ↦ -1)
 
Theoremlcmineqlem8 43054* Derivative of (1-x)^(N-M). (Contributed by metakunt, 12-May-2024.)
(𝜑 → 𝑀 ∈ ℕ)    &   (𝜑 → 𝑁 ∈ ℕ)    &   (𝜑 → 𝑀 < 𝑁)    ⇒   (𝜑 → (ℂ D (𝑥 ∈ ℂ ↦ ((1 − 𝑥)↑(𝑁 − 𝑀)))) = (𝑥 ∈ ℂ ↦ (-(𝑁 − 𝑀) · ((1 − 𝑥)↑((𝑁 − 𝑀) − 1)))))
 
Theoremlcmineqlem9 43055* (1-x)^(N-M) is continuous. (Contributed by metakunt, 12-May-2024.)
(𝜑 → 𝑀 ∈ ℕ)    &   (𝜑 → 𝑁 ∈ ℕ)    &   (𝜑 → 𝑀 ≤ 𝑁)    ⇒   (𝜑 → (𝑥 ∈ ℂ ↦ ((1 − 𝑥)↑(𝑁 − 𝑀))) ∈ (ℂ–cn→ℂ))
 
Theoremlcmineqlem10 43056* Induction step of lcmineqlem13 43059 (deduction form). (Contributed by metakunt, 12-May-2024.)
(𝜑 → 𝑀 ∈ ℕ)    &   (𝜑 → 𝑁 ∈ ℕ)    &   (𝜑 → 𝑀 < 𝑁)    ⇒   (𝜑 → ∫(0[,]1)((𝑥↑((𝑀 + 1) − 1)) · ((1 − 𝑥)↑(𝑁 − (𝑀 + 1)))) d𝑥 = ((𝑀 / (𝑁 − 𝑀)) · ∫(0[,]1)((𝑥↑(𝑀 − 1)) · ((1 − 𝑥)↑(𝑁 − 𝑀))) d𝑥))
 
Theoremlcmineqlem11 43057 Induction step, continuation for binomial coefficients. (Contributed by metakunt, 12-May-2024.)
(𝜑 → 𝑀 ∈ ℕ)    &   (𝜑 → 𝑁 ∈ ℕ)    &   (𝜑 → 𝑀 < 𝑁)    ⇒   (𝜑 → (1 / ((𝑀 + 1) · (𝑁C(𝑀 + 1)))) = ((𝑀 / (𝑁 − 𝑀)) · (1 / (𝑀 · (𝑁C𝑀)))))
 
Theoremlcmineqlem12 43058* Base case for induction. (Contributed by metakunt, 12-May-2024.)
(𝜑 → 𝑁 ∈ ℕ)    ⇒   (𝜑 → ∫(0[,]1)((𝑡↑(1 − 1)) · ((1 − 𝑡)↑(𝑁 − 1))) d𝑡 = (1 / (1 · (𝑁C1))))
 
Theoremlcmineqlem13 43059* Induction proof for lcm integral. (Contributed by metakunt, 12-May-2024.)
𝐹 = ∫(0[,]1)((𝑥↑(𝑀 − 1)) · ((1 − 𝑥)↑(𝑁 − 𝑀))) d𝑥    &   (𝜑 → 𝑀 ∈ ℕ)    &   (𝜑 → 𝑁 ∈ ℕ)    &   (𝜑 → 𝑀 ≤ 𝑁)    ⇒   (𝜑 → 𝐹 = (1 / (𝑀 · (𝑁C𝑀))))
 
Theoremlcmineqlem14 43060 Technical lemma for inequality estimate. (Contributed by metakunt, 12-May-2024.)
(𝜑 → 𝐴 ∈ ℕ)    &   (𝜑 → 𝐵 ∈ ℕ)    &   (𝜑 → 𝐶 ∈ ℕ)    &   (𝜑 → 𝐷 ∈ ℕ)    &   (𝜑 → 𝐸 ∈ ℕ)    &   (𝜑 → (𝐴 · 𝐶) ∥ 𝐷)    &   (𝜑 → (𝐵 · 𝐶) ∥ 𝐸)    &   (𝜑 → 𝐷 ∥ 𝐸)    &   (𝜑 → (𝐴 gcd 𝐵) = 1)    ⇒   (𝜑 → ((𝐴 · 𝐵) · 𝐶) ∥ 𝐸)
 
Theoremlcmineqlem15 43061* F times the least common multiple of 1 to n is a natural number. (Contributed by metakunt, 10-May-2024.)
𝐹 = ∫(0[,]1)((𝑥↑(𝑀 − 1)) · ((1 − 𝑥)↑(𝑁 − 𝑀))) d𝑥    &   (𝜑 → 𝑁 ∈ ℕ)    &   (𝜑 → 𝑀 ∈ ℕ)    &   (𝜑 → 𝑀 ≤ 𝑁)    ⇒   (𝜑 → ((lcm‘(1...𝑁)) · 𝐹) ∈ ℕ)
 
Theoremlcmineqlem16 43062 Technical divisibility lemma. (Contributed by metakunt, 12-May-2024.)
(𝜑 → 𝑀 ∈ ℕ)    &   (𝜑 → 𝑁 ∈ ℕ)    &   (𝜑 → 𝑀 ≤ 𝑁)    ⇒   (𝜑 → (𝑀 · (𝑁C𝑀)) ∥ (lcm‘(1...𝑁)))
 
Theoremlcmineqlem17 43063 Inequality of 2^{2n}. (Contributed by metakunt, 29-Apr-2024.)
(𝜑 → 𝑁 ∈ ℕ0)    ⇒   (𝜑 → (2↑(2 · 𝑁)) ≤ (((2 · 𝑁) + 1) · ((2 · 𝑁)C𝑁)))
 
Theoremlcmineqlem18 43064 Technical lemma to shift factors in binomial coefficient. (Contributed by metakunt, 12-May-2024.)
(𝜑 → 𝑁 ∈ ℕ)    ⇒   (𝜑 → ((𝑁 + 1) · (((2 · 𝑁) + 1)C(𝑁 + 1))) = (((2 · 𝑁) + 1) · ((2 · 𝑁)C𝑁)))
 
Theoremlcmineqlem19 43065 Dividing implies inequality for lcm inequality lemma. (Contributed by metakunt, 12-May-2024.)
(𝜑 → 𝑁 ∈ ℕ)    ⇒   (𝜑 → ((𝑁 · ((2 · 𝑁) + 1)) · ((2 · 𝑁)C𝑁)) ∥ (lcm‘(1...((2 · 𝑁) + 1))))
 
Theoremlcmineqlem20 43066 Inequality for lcm lemma. (Contributed by metakunt, 12-May-2024.)
(𝜑 → 𝑁 ∈ ℕ)    ⇒   (𝜑 → (𝑁 · (2↑(2 · 𝑁))) ≤ (lcm‘(1...((2 · 𝑁) + 1))))
 
Theoremlcmineqlem21 43067 The lcm inequality lemma without base cases 7 and 8. (Contributed by metakunt, 12-May-2024.)
(𝜑 → 𝑁 ∈ ℕ)    &   (𝜑 → 4 ≤ 𝑁)    ⇒   (𝜑 → (2↑((2 · 𝑁) + 2)) ≤ (lcm‘(1...((2 · 𝑁) + 1))))
 
Theoremlcmineqlem22 43068 The lcm inequality lemma without base cases 7 and 8. (Contributed by metakunt, 12-May-2024.)
(𝜑 → 𝑁 ∈ ℕ)    &   (𝜑 → 4 ≤ 𝑁)    ⇒   (𝜑 → ((2↑((2 · 𝑁) + 1)) ≤ (lcm‘(1...((2 · 𝑁) + 1))) ∧ (2↑((2 · 𝑁) + 2)) ≤ (lcm‘(1...((2 · 𝑁) + 2)))))
 
Theoremlcmineqlem23 43069 Penultimate step to the lcm inequality lemma. (Contributed by metakunt, 12-May-2024.)
(𝜑 → 𝑁 ∈ ℕ)    &   (𝜑 → 9 ≤ 𝑁)    ⇒   (𝜑 → (2↑𝑁) ≤ (lcm‘(1...𝑁)))
 
Theoremlcmineqlem 43070 The least common multiple inequality lemma, a central result for future use. Theorem 3.1 from https://www3.nd.edu/%7eandyp/notes/AKS.pdf (Contributed by metakunt, 16-May-2024.)
(𝜑 → 𝑁 ∈ ℕ)    &   (𝜑 → 7 ≤ 𝑁)    ⇒   (𝜑 → (2↑𝑁) ≤ (lcm‘(1...𝑁)))
 
21.30.5  Logarithm inequalities
 
Theorem3exp7 43071 3 to the power of 7 equals 2187. (Contributed by metakunt, 21-Aug-2024.)
(3↑7) = 2187
 
Theorem3lexlogpow5ineq1 43072 First inequality in inequality chain, proposed by Mario Carneiro (Contributed by metakunt, 22-May-2024.)
9 < ((11 / 7)↑5)
 
Theorem3lexlogpow5ineq2 43073 Second inequality in inequality chain, proposed by Mario Carneiro. (Contributed by metakunt, 22-May-2024.)
(𝜑 → 𝑋 ∈ ℝ)    &   (𝜑 → 3 ≤ 𝑋)    ⇒   (𝜑 → ((11 / 7)↑5) ≤ ((2 logb 𝑋)↑5))
 
Theorem3lexlogpow5ineq4 43074 Sharper logarithm inequality chain. (Contributed by metakunt, 21-Aug-2024.)
(𝜑 → 𝑋 ∈ ℝ)    &   (𝜑 → 3 ≤ 𝑋)    ⇒   (𝜑 → 9 < ((2 logb 𝑋)↑5))
 
Theorem3lexlogpow5ineq3 43075 Combined inequality chain for a specific power of the binary logarithm, proposed by Mario Carneiro. (Contributed by metakunt, 22-May-2024.)
(𝜑 → 𝑋 ∈ ℝ)    &   (𝜑 → 3 ≤ 𝑋)    ⇒   (𝜑 → 7 < ((2 logb 𝑋)↑5))
 
Theorem3lexlogpow2ineq1 43076 Result for bound in AKS inequality lemma. (Contributed by metakunt, 21-Aug-2024.)
((3 / 2) < (2 logb 3) ∧ (2 logb 3) < (5 / 3))
 
Theorem3lexlogpow2ineq2 43077 Result for bound in AKS inequality lemma. (Contributed by metakunt, 21-Aug-2024.)
(2 < ((2 logb 3)↑2) ∧ ((2 logb 3)↑2) < 3)
 
Theorem3lexlogpow5ineq5 43078 Result for bound in AKS inequality lemma. (Contributed by metakunt, 21-Aug-2024.)
((2 logb 3)↑5) ≤ 15
 
21.30.6  Miscellaneous results for AKS formalisation
 
Theoremintlewftc 43079* Inequality inference by invoking fundamental theorem of calculus. (Contributed by metakunt, 22-Jul-2024.)
(𝜑 → 𝐴 ∈ ℝ)    &   (𝜑 → 𝐵 ∈ ℝ)    &   (𝜑 → 𝐴 ≤ 𝐵)    &   (𝜑 → 𝐹 ∈ ((𝐴[,]𝐵)–cn→ℝ))    &   (𝜑 → 𝐺 ∈ ((𝐴[,]𝐵)–cn→ℝ))    &   (𝜑 → 𝐷 = (ℝ D 𝐹))    &   (𝜑 → 𝐸 = (ℝ D 𝐺))    &   (𝜑 → 𝐷 ∈ ((𝐴(,)𝐵)–cn→ℝ))    &   (𝜑 → 𝐸 ∈ ((𝐴(,)𝐵)–cn→ℝ))    &   (𝜑 → 𝐷 ∈ 𝐿1)    &   (𝜑 → 𝐸 ∈ 𝐿1)    &   (𝜑 → 𝐷 = (𝑥 ∈ (𝐴(,)𝐵) ↦ 𝑃))    &   (𝜑 → 𝐸 = (𝑥 ∈ (𝐴(,)𝐵) ↦ 𝑄))    &   ((𝜑 ∧ 𝑥 ∈ (𝐴(,)𝐵)) → 𝑃 ≤ 𝑄)    &   (𝜑 → (𝐹‘𝐴) ≤ (𝐺‘𝐴))    ⇒   (𝜑 → (𝐹‘𝐵) ≤ (𝐺‘𝐵))
 
Theoremaks4d1lem1 43080 Technical lemma to reduce proof size. (Contributed by metakunt, 14-Nov-2024.)
(𝜑 → 𝑁 ∈ (ℤ≥‘3))    &   𝐵 = (⌈‘((2 logb 𝑁)↑5))    ⇒   (𝜑 → (𝐵 ∈ ℕ ∧ 9 < 𝐵))
 
Theoremaks4d1p1p1 43081* Exponential law for finite products, special case. (Contributed by metakunt, 22-Jul-2024.)
(𝜑 → 𝐴 ∈ ℝ+)    &   (𝜑 → 𝑁 ∈ ℕ)    ⇒   (𝜑 → ∏𝑘 ∈ (1...𝑁)(𝐴↑𝑐𝑘) = (𝐴↑𝑐Σ𝑘 ∈ (1...𝑁)𝑘))
 
Theoremdvrelog2 43082* The derivative of the logarithm, ftc2 26344 version. (Contributed by metakunt, 11-Aug-2024.)
(𝜑 → 𝐴 ∈ ℝ)    &   (𝜑 → 𝐵 ∈ ℝ)    &   (𝜑 → 0 < 𝐴)    &   (𝜑 → 𝐴 ≤ 𝐵)    &   𝐹 = (𝑥 ∈ (𝐴[,]𝐵) ↦ (log‘𝑥))    &   𝐺 = (𝑥 ∈ (𝐴(,)𝐵) ↦ (1 / 𝑥))    ⇒   (𝜑 → (ℝ D 𝐹) = 𝐺)
 
Theoremdvrelog3 43083* The derivative of the logarithm on an open interval. (Contributed by metakunt, 11-Aug-2024.)
(𝜑 → 𝐴 ∈ ℝ*)    &   (𝜑 → 𝐵 ∈ ℝ*)    &   (𝜑 → 0 ≤ 𝐴)    &   (𝜑 → 𝐴 ≤ 𝐵)    &   𝐹 = (𝑥 ∈ (𝐴(,)𝐵) ↦ (log‘𝑥))    &   𝐺 = (𝑥 ∈ (𝐴(,)𝐵) ↦ (1 / 𝑥))    ⇒   (𝜑 → (ℝ D 𝐹) = 𝐺)
 
Theoremdvrelog2b 43084* Derivative of the binary logarithm. (Contributed by metakunt, 11-Aug-2024.)
(𝜑 → 𝐴 ∈ ℝ*)    &   (𝜑 → 𝐵 ∈ ℝ*)    &   (𝜑 → 0 ≤ 𝐴)    &   (𝜑 → 𝐴 ≤ 𝐵)    &   𝐹 = (𝑥 ∈ (𝐴(,)𝐵) ↦ (2 logb 𝑥))    &   𝐺 = (𝑥 ∈ (𝐴(,)𝐵) ↦ (1 / (𝑥 · (log‘2))))    ⇒   (𝜑 → (ℝ D 𝐹) = 𝐺)
 
Theorem0nonelalab 43085 Technical lemma for open interval. (Contributed by metakunt, 12-Aug-2024.)
(𝜑 → 𝐴 ∈ ℝ)    &   (𝜑 → 𝐵 ∈ ℝ)    &   (𝜑 → 0 < 𝐴)    &   (𝜑 → 𝐴 ≤ 𝐵)    &   (𝜑 → 𝐶 ∈ (𝐴(,)𝐵))    ⇒   (𝜑 → 0 ≠ 𝐶)
 
Theoremdvrelogpow2b 43086* Derivative of the power of the binary logarithm. (Contributed by metakunt, 12-Aug-2024.)
(𝜑 → 𝐴 ∈ ℝ)    &   (𝜑 → 𝐵 ∈ ℝ)    &   (𝜑 → 0 < 𝐴)    &   (𝜑 → 𝐴 ≤ 𝐵)    &   𝐹 = (𝑥 ∈ (𝐴(,)𝐵) ↦ ((2 logb 𝑥)↑𝑁))    &   𝐺 = (𝑥 ∈ (𝐴(,)𝐵) ↦ (𝐶 · (((log‘𝑥)↑(𝑁 − 1)) / 𝑥)))    &   𝐶 = (𝑁 / ((log‘2)↑𝑁))    &   (𝜑 → 𝑁 ∈ ℕ)    ⇒   (𝜑 → (ℝ D 𝐹) = 𝐺)
 
Theoremaks4d1p1p3 43087 Bound of a ceiling of the binary logarithm to the fifth power. (Contributed by metakunt, 19-Aug-2024.)
(𝜑 → 𝑁 ∈ ℕ)    &   𝐵 = (⌈‘((2 logb 𝑁)↑5))    &   (𝜑 → 3 ≤ 𝑁)    ⇒   (𝜑 → (𝑁↑𝑐(⌊‘(2 logb 𝐵))) < (𝑁↑𝑐(2 logb (((2 logb 𝑁)↑5) + 1))))
 
Theoremaks4d1p1p2 43088* Rewrite 𝐴 in more suitable form. (Contributed by metakunt, 19-Aug-2024.)
(𝜑 → 𝑁 ∈ ℕ)    &   𝐴 = ((𝑁↑(⌊‘(2 logb 𝐵))) · ∏𝑘 ∈ (1...(⌊‘((2 logb 𝑁)↑2)))((𝑁↑𝑘) − 1))    &   𝐵 = (⌈‘((2 logb 𝑁)↑5))    &   (𝜑 → 3 ≤ 𝑁)    ⇒   (𝜑 → 𝐴 < (𝑁↑𝑐(((2 logb (((2 logb 𝑁)↑5) + 1)) + (((2 logb 𝑁)↑2) / 2)) + (((2 logb 𝑁)↑4) / 2))))
 
Theoremaks4d1p1p4 43089* Technical step for inequality. The hard work is in to prove the final hypothesis. (Contributed by metakunt, 19-Aug-2024.)
(𝜑 → 𝑁 ∈ ℕ)    &   𝐴 = ((𝑁↑(⌊‘(2 logb 𝐵))) · ∏𝑘 ∈ (1...(⌊‘((2 logb 𝑁)↑2)))((𝑁↑𝑘) − 1))    &   𝐵 = (⌈‘((2 logb 𝑁)↑5))    &   (𝜑 → 3 ≤ 𝑁)    &   𝐶 = (2 logb (((2 logb 𝑁)↑5) + 1))    &   𝐷 = ((2 logb 𝑁)↑2)    &   𝐸 = ((2 logb 𝑁)↑4)    &   (𝜑 → ((2 · 𝐶) + 𝐷) ≤ 𝐸)    ⇒   (𝜑 → 𝐴 < (2↑𝐵))
 
Theoremdvle2 43090* Collapsed dvle 26307. (Contributed by metakunt, 19-Aug-2024.)
(𝜑 → 𝐴 ∈ ℝ)    &   (𝜑 → 𝐵 ∈ ℝ)    &   (𝜑 → (𝑥 ∈ (𝐴[,]𝐵) ↦ 𝐸) ∈ ((𝐴[,]𝐵)–cn→ℝ))    &   (𝜑 → (𝑥 ∈ (𝐴[,]𝐵) ↦ 𝐺) ∈ ((𝐴[,]𝐵)–cn→ℝ))    &   (𝜑 → (ℝ D (𝑥 ∈ (𝐴(,)𝐵) ↦ 𝐸)) = (𝑥 ∈ (𝐴(,)𝐵) ↦ 𝐹))    &   (𝜑 → (ℝ D (𝑥 ∈ (𝐴(,)𝐵) ↦ 𝐺)) = (𝑥 ∈ (𝐴(,)𝐵) ↦ 𝐻))    &   ((𝜑 ∧ 𝑥 ∈ (𝐴(,)𝐵)) → 𝐹 ≤ 𝐻)    &   (𝑥 = 𝐴 → 𝐸 = 𝑃)    &   (𝑥 = 𝐴 → 𝐺 = 𝑄)    &   (𝑥 = 𝐵 → 𝐸 = 𝑅)    &   (𝑥 = 𝐵 → 𝐺 = 𝑆)    &   (𝜑 → 𝑃 ≤ 𝑄)    &   (𝜑 → 𝐴 ≤ 𝐵)    ⇒   (𝜑 → 𝑅 ≤ 𝑆)
 
Theoremaks4d1p1p6 43091* Inequality lift to differentiable functions for a term in AKS inequality lemma. (Contributed by metakunt, 19-Aug-2024.)
(𝜑 → 𝐴 ∈ ℝ)    &   (𝜑 → 𝐵 ∈ ℝ)    &   (𝜑 → 3 ≤ 𝐴)    &   (𝜑 → 𝐴 ≤ 𝐵)    ⇒   (𝜑 → (ℝ D (𝑥 ∈ (𝐴(,)𝐵) ↦ ((2 · (2 logb (((2 logb 𝑥)↑5) + 1))) + ((2 logb 𝑥)↑2)))) = (𝑥 ∈ (𝐴(,)𝐵) ↦ ((2 · ((1 / ((((2 logb 𝑥)↑5) + 1) · (log‘2))) · (((5 · ((2 logb 𝑥)↑4)) · (1 / (𝑥 · (log‘2)))) + 0))) + ((2 / ((log‘2)↑2)) · (((log‘𝑥)↑(2 − 1)) / 𝑥)))))
 
Theoremaks4d1p1p7 43092 Bound of intermediary of inequality step. (Contributed by metakunt, 19-Aug-2024.)
(𝜑 → 𝐴 ∈ ℝ)    &   (𝜑 → 4 ≤ 𝐴)    ⇒   (𝜑 → ((2 · ((1 / ((((2 logb 𝐴)↑5) + 1) · (log‘2))) · (((5 · ((2 logb 𝐴)↑4)) · (1 / (𝐴 · (log‘2)))) + 0))) + ((2 / ((log‘2)↑2)) · (((log‘𝐴)↑(2 − 1)) / 𝐴))) ≤ ((4 / ((log‘2)↑4)) · (((log‘𝐴)↑3) / 𝐴)))
 
Theoremaks4d1p1p5 43093* Show inequality for existence of a non-divisor. (Contributed by metakunt, 19-Aug-2024.)
(𝜑 → 𝑁 ∈ ℕ)    &   𝐴 = ((𝑁↑(⌊‘(2 logb 𝐵))) · ∏𝑘 ∈ (1...(⌊‘((2 logb 𝑁)↑2)))((𝑁↑𝑘) − 1))    &   𝐵 = (⌈‘((2 logb 𝑁)↑5))    &   (𝜑 → 4 ≤ 𝑁)    &   𝐶 = (2 logb (((2 logb 𝑁)↑5) + 1))    &   𝐷 = ((2 logb 𝑁)↑2)    &   𝐸 = ((2 logb 𝑁)↑4)    ⇒   (𝜑 → 𝐴 < (2↑𝐵))
 
Theoremaks4d1p1 43094* Show inequality for existence of a non-divisor. (Contributed by metakunt, 21-Aug-2024.)
(𝜑 → 𝑁 ∈ (ℤ≥‘3))    &   𝐴 = ((𝑁↑(⌊‘(2 logb 𝐵))) · ∏𝑘 ∈ (1...(⌊‘((2 logb 𝑁)↑2)))((𝑁↑𝑘) − 1))    &   𝐵 = (⌈‘((2 logb 𝑁)↑5))    ⇒   (𝜑 → 𝐴 < (2↑𝐵))
 
Theoremaks4d1p2 43095 Technical lemma for existence of non-divisor. (Contributed by metakunt, 27-Oct-2024.)
(𝜑 → 𝑁 ∈ (ℤ≥‘3))    &   𝐴 = ((𝑁↑(⌊‘(2 logb 𝐵))) · ∏𝑘 ∈ (1...(⌊‘((2 logb 𝑁)↑2)))((𝑁↑𝑘) − 1))    &   𝐵 = (⌈‘((2 logb 𝑁)↑5))    ⇒   (𝜑 → (2↑𝐵) ≤ (lcm‘(1...𝐵)))
 
Theoremaks4d1p3 43096* There exists a small enough number such that it does not divide 𝐴. (Contributed by metakunt, 27-Oct-2024.)
(𝜑 → 𝑁 ∈ (ℤ≥‘3))    &   𝐴 = ((𝑁↑(⌊‘(2 logb 𝐵))) · ∏𝑘 ∈ (1...(⌊‘((2 logb 𝑁)↑2)))((𝑁↑𝑘) − 1))    &   𝐵 = (⌈‘((2 logb 𝑁)↑5))    ⇒   (𝜑 → ∃𝑟 ∈ (1...𝐵) ¬ 𝑟 ∥ 𝐴)
 
Theoremaks4d1p4 43097* There exists a small enough number such that it does not divide 𝐴. (Contributed by metakunt, 28-Oct-2024.)
(𝜑 → 𝑁 ∈ (ℤ≥‘3))    &   𝐴 = ((𝑁↑(⌊‘(2 logb 𝐵))) · ∏𝑘 ∈ (1...(⌊‘((2 logb 𝑁)↑2)))((𝑁↑𝑘) − 1))    &   𝐵 = (⌈‘((2 logb 𝑁)↑5))    &   𝑅 = inf({𝑟 ∈ (1...𝐵) ∣ ¬ 𝑟 ∥ 𝐴}, ℝ, < )    ⇒   (𝜑 → (𝑅 ∈ (1...𝐵) ∧ ¬ 𝑅 ∥ 𝐴))
 
Theoremaks4d1p5 43098* Show that 𝑁 and 𝑅 are coprime for AKS existence theorem. Precondition will be eliminated in further theorem. (Contributed by metakunt, 30-Oct-2024.)
(𝜑 → 𝑁 ∈ (ℤ≥‘3))    &   𝐴 = ((𝑁↑(⌊‘(2 logb 𝐵))) · ∏𝑘 ∈ (1...(⌊‘((2 logb 𝑁)↑2)))((𝑁↑𝑘) − 1))    &   𝐵 = (⌈‘((2 logb 𝑁)↑5))    &   𝑅 = inf({𝑟 ∈ (1...𝐵) ∣ ¬ 𝑟 ∥ 𝐴}, ℝ, < )    &   (((𝜑 ∧ 1 < (𝑁 gcd 𝑅)) ∧ (𝑅 / (𝑁 gcd 𝑅)) ∥ 𝐴) → ¬ (𝑅 / (𝑁 gcd 𝑅)) ∥ 𝐴)    ⇒   (𝜑 → (𝑁 gcd 𝑅) = 1)
 
Theoremaks4d1p6 43099* The maximal prime power exponent is smaller than the binary logarithm floor of 𝐵. (Contributed by metakunt, 30-Oct-2024.)
(𝜑 → 𝑁 ∈ (ℤ≥‘3))    &   𝐴 = ((𝑁↑(⌊‘(2 logb 𝐵))) · ∏𝑘 ∈ (1...(⌊‘((2 logb 𝑁)↑2)))((𝑁↑𝑘) − 1))    &   𝐵 = (⌈‘((2 logb 𝑁)↑5))    &   𝑅 = inf({𝑟 ∈ (1...𝐵) ∣ ¬ 𝑟 ∥ 𝐴}, ℝ, < )    &   (𝜑 → 𝑃 ∈ ℙ)    &   (𝜑 → 𝑃 ∥ 𝑅)    &   𝐾 = (𝑃 pCnt 𝑅)    ⇒   (𝜑 → 𝐾 ≤ (⌊‘(2 logb 𝐵)))
 
Theoremaks4d1p7d1 43100* Technical step in AKS lemma 4.1. (Contributed by metakunt, 31-Oct-2024.)
(𝜑 → 𝑁 ∈ (ℤ≥‘3))    &   𝐴 = ((𝑁↑(⌊‘(2 logb 𝐵))) · ∏𝑘 ∈ (1...(⌊‘((2 logb 𝑁)↑2)))((𝑁↑𝑘) − 1))    &   𝐵 = (⌈‘((2 logb 𝑁)↑5))    &   𝑅 = inf({𝑟 ∈ (1...𝐵) ∣ ¬ 𝑟 ∥ 𝐴}, ℝ, < )    &   (𝜑 → ∀𝑝 ∈ ℙ (𝑝 ∥ 𝑅 → 𝑝 ∥ 𝑁))    ⇒   (𝜑 → 𝑅 ∥ (𝑁↑(⌊‘(2 logb 𝐵))))
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