Theorem parteq2 36995

Description: Equality theorem for partition. (Contributed by Peter Mazsa, 25-Jul-2024.)

Assertion

Ref	Expression
parteq2	⊢ (𝐴 = 𝐵 → (𝑅 Part 𝐴 ↔ 𝑅 Part 𝐵))

Proof of Theorem parteq2

Step	Hyp	Ref	Expression
1		eqeq2 2748	. . 3 ⊢ (𝐴 = 𝐵 → ((dom 𝑅 / 𝑅) = 𝐴 ↔ (dom 𝑅 / 𝑅) = 𝐵))
2	1	anbi2d 630	. 2 ⊢ (𝐴 = 𝐵 → (( Disj 𝑅 ∧ (dom 𝑅 / 𝑅) = 𝐴) ↔ ( Disj 𝑅 ∧ (dom 𝑅 / 𝑅) = 𝐵)))
3		dfpart2 36989	. 2 ⊢ (𝑅 Part 𝐴 ↔ ( Disj 𝑅 ∧ (dom 𝑅 / 𝑅) = 𝐴))
4		dfpart2 36989	. 2 ⊢ (𝑅 Part 𝐵 ↔ ( Disj 𝑅 ∧ (dom 𝑅 / 𝑅) = 𝐵))
5	2, 3, 4	3bitr4g 314	1 ⊢ (𝐴 = 𝐵 → (𝑅 Part 𝐴 ↔ 𝑅 Part 𝐵))

Syntax hints:   → wi 4   ↔ wb 205   ∧ wa 397   = wceq 1539  dom cdm 5600   / cqs 8528   Disj wdisjALTV 36421   Part wpart 36426

This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1795  ax-4 1809  ax-5 1911  ax-6 1969  ax-7 2009  ax-9 2114  ax-ext 2707

This theorem depends on definitions:  df-bi 206  df-an 398  df-ex 1780  df-cleq 2728  df-dmqs 36859  df-part 36986

This theorem is referenced by:  parteq12  36996