Theorem sbelx 2241

Description: Elimination of substitution. Also see sbel2x 2469. (Contributed by NM, 5-Aug-1993.) Avoid ax-13 2367. (Revised by Wolf Lammen, 6-Aug-2023.) Avoid ax-10 2130. (Revised by Gino Giotto, 20-Aug-2023.)

Assertion

Ref	Expression
sbelx	⊢ (𝜑 ↔ ∃𝑥(𝑥 = 𝑦 ∧ [𝑥 / 𝑦]𝜑))

Distinct variable groups:   𝑥,𝑦   𝜑,𝑥

Allowed substitution hint:   𝜑(𝑦)

Proof of Theorem sbelx

Step	Hyp	Ref	Expression
1		sbequ12r 2240	. . 3 ⊢ (𝑥 = 𝑦 → ([𝑥 / 𝑦]𝜑 ↔ 𝜑))
2	1	equsexvw 2001	. 2 ⊢ (∃𝑥(𝑥 = 𝑦 ∧ [𝑥 / 𝑦]𝜑) ↔ 𝜑)
3	2	bicomi 223	1 ⊢ (𝜑 ↔ ∃𝑥(𝑥 = 𝑦 ∧ [𝑥 / 𝑦]𝜑))

Syntax hints:   ↔ wb 205   ∧ wa 395  ∃wex 1774  [wsb 2060

This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1790  ax-4 1804  ax-5 1906  ax-6 1964  ax-7 2004  ax-12 2167

This theorem depends on definitions:  df-bi 206  df-an 396  df-ex 1775  df-sb 2061

This theorem is referenced by:  pm13.196a  43845