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Theorem sbequvvOLD 2334
Description: Obsolete version of sbequ 2089 as of 7-Jul-2023. Version of sbequ 2089 with disjoint variable conditions, not requiring ax-13 2389. (Contributed by Wolf Lammen, 19-Jan-2023.) (Proof modification is discouraged.) (New usage is discouraged.)
Assertion
Ref Expression
sbequvvOLD (𝑥 = 𝑦 → ([𝑥 / 𝑧]𝜑 ↔ [𝑦 / 𝑧]𝜑))
Distinct variable groups:   𝑥,𝑧   𝑦,𝑧
Allowed substitution hints:   𝜑(𝑥,𝑦,𝑧)

Proof of Theorem sbequvvOLD
StepHypRef Expression
1 sbequivvOLD 2333 . 2 (𝑥 = 𝑦 → ([𝑥 / 𝑧]𝜑 → [𝑦 / 𝑧]𝜑))
2 sbequivvOLD 2333 . . 3 (𝑦 = 𝑥 → ([𝑦 / 𝑧]𝜑 → [𝑥 / 𝑧]𝜑))
32equcoms 2026 . 2 (𝑥 = 𝑦 → ([𝑦 / 𝑧]𝜑 → [𝑥 / 𝑧]𝜑))
41, 3impbid 214 1 (𝑥 = 𝑦 → ([𝑥 / 𝑧]𝜑 ↔ [𝑦 / 𝑧]𝜑))
Colors of variables: wff setvar class
Syntax hints:  wi 4  wb 208  [wsb 2068
This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1795  ax-4 1809  ax-5 1910  ax-6 1969  ax-7 2014
This theorem depends on definitions:  df-bi 209  df-an 399  df-ex 1780  df-sb 2069
This theorem is referenced by: (None)
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