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Theorem indif2 3498
 Description: Bring an intersection in and out of a class difference. (Contributed by Jeff Hankins, 15-Jul-2009.)
Assertion
Ref Expression
indif2 (A ∩ (B C)) = ((AB) C)

Proof of Theorem indif2
StepHypRef Expression
1 inass 3465 . 2 ((AB) ∩ (V C)) = (A ∩ (B ∩ (V C)))
2 invdif 3496 . 2 ((AB) ∩ (V C)) = ((AB) C)
3 invdif 3496 . . 3 (B ∩ (V C)) = (B C)
43ineq2i 3454 . 2 (A ∩ (B ∩ (V C))) = (A ∩ (B C))
51, 2, 43eqtr3ri 2382 1 (A ∩ (B C)) = ((AB) C)
 Colors of variables: wff setvar class Syntax hints:   = wceq 1642  Vcvv 2859   ∖ cdif 3206   ∩ cin 3208 This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1546  ax-5 1557  ax-17 1616  ax-9 1654  ax-8 1675  ax-6 1729  ax-7 1734  ax-11 1746  ax-12 1925  ax-ext 2334 This theorem depends on definitions:  df-bi 177  df-or 359  df-an 360  df-nan 1288  df-tru 1319  df-ex 1542  df-nf 1545  df-sb 1649  df-clab 2340  df-cleq 2346  df-clel 2349  df-nfc 2478  df-v 2861  df-nin 3211  df-compl 3212  df-in 3213  df-dif 3215 This theorem is referenced by:  indif1  3499  indifcom  3500
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