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Theorem opabssxp 4838
Description: An abstraction relation is a subset of a related cross product. (Contributed by NM, 16-Jul-1995.)
Assertion
Ref Expression
opabssxp {x, y ((x A y B) φ)} (A × B)
Distinct variable groups:   x,y,A   x,B,y
Allowed substitution hints:   φ(x,y)

Proof of Theorem opabssxp
StepHypRef Expression
1 simpl 443 . . 3 (((x A y B) φ) → (x A y B))
21ssopab2i 4715 . 2 {x, y ((x A y B) φ)} {x, y (x A y B)}
3 df-xp 4785 . 2 (A × B) = {x, y (x A y B)}
42, 3sseqtr4i 3305 1 {x, y ((x A y B) φ)} (A × B)
Colors of variables: wff setvar class
Syntax hints:   wa 358   wcel 1710   wss 3258  {copab 4623   × cxp 4771
This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1546  ax-5 1557  ax-17 1616  ax-9 1654  ax-8 1675  ax-6 1729  ax-7 1734  ax-11 1746  ax-12 1925  ax-ext 2334
This theorem depends on definitions:  df-bi 177  df-or 359  df-an 360  df-nan 1288  df-tru 1319  df-ex 1542  df-nf 1545  df-sb 1649  df-clab 2340  df-cleq 2346  df-clel 2349  df-nfc 2479  df-v 2862  df-nin 3212  df-compl 3213  df-in 3214  df-ss 3260  df-opab 4624  df-xp 4785
This theorem is referenced by:  dmoprabss  5576
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