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Theorem rsp2e 2678
Description: Restricted specialization. (Contributed by FL, 4-Jun-2012.)
Assertion
Ref Expression
rsp2e ⊢ ((x ∈ A ∧ y ∈ B ∧ φ) → ∃x ∈ A ∃y ∈ B φ)

Proof of Theorem rsp2e
StepHypRef Expression
1 simp1 955 . . 3 ⊢ ((x ∈ A ∧ y ∈ B ∧ φ) → x ∈ A)
2 rspe 2676 . . . 4 ⊢ ((y ∈ B ∧ φ) → ∃y ∈ B φ)
323adant1 973 . . 3 ⊢ ((x ∈ A ∧ y ∈ B ∧ φ) → ∃y ∈ B φ)
4 19.8a 1756 . . 3 ⊢ ((x ∈ A ∧ ∃y ∈ B φ) → ∃x(x ∈ A ∧ ∃y ∈ B φ))
51, 3, 4syl2anc 642 . 2 ⊢ ((x ∈ A ∧ y ∈ B ∧ φ) → ∃x(x ∈ A ∧ ∃y ∈ B φ))
6 df-rex 2621 . 2 ⊢ (∃x ∈ A ∃y ∈ B φ ↔ ∃x(x ∈ A ∧ ∃y ∈ B φ))
75, 6sylibr 203 1 ⊢ ((x ∈ A ∧ y ∈ B ∧ φ) → ∃x ∈ A ∃y ∈ B φ)
Colors of variables:    wff setvar class
This proof depends on syntax axioms:   → wi 4   ∧ wa 358   ∧ w3a 934  ∃wex 1541   ∈ wcel 1710  ∃wrex 2616
This proof depends on axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1546  ax-5 1557  ax-17 1616  ax-9 1654  ax-8 1675  ax-11 1746
This proof depends on definitions:  df-bi 177  df-an 360  df-3an 936  df-ex 1542  df-rex 2621
This theorem is used by: (None)
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