Proof of Theorem ka4ot
| Step | Hyp | Ref
| Expression |
| 1 | | le1 146 |
. 2
((a ≡ b)⊥ ∪ ((a ∪ c)
≡ (b ∪ c))) ≤ 1 |
| 2 | | wom2 434 |
. . . . . 6
a ≤ ((a ≡ b)⊥ ∪ ((a ∪ c)
≡ (b ∪ c))) |
| 3 | | wom2 434 |
. . . . . . 7
b ≤ ((b ≡ a)⊥ ∪ ((b ∪ c)
≡ (a ∪ c))) |
| 4 | | bicom 96 |
. . . . . . . . 9
(b ≡ a) = (a ≡
b) |
| 5 | 4 | ax-r4 37 |
. . . . . . . 8
(b ≡ a)⊥ = (a ≡ b)⊥ |
| 6 | | bicom 96 |
. . . . . . . 8
((b ∪ c) ≡ (a
∪ c)) = ((a ∪ c)
≡ (b ∪ c)) |
| 7 | 5, 6 | 2or 72 |
. . . . . . 7
((b ≡ a)⊥ ∪ ((b ∪ c)
≡ (a ∪ c))) = ((a
≡ b)⊥ ∪
((a ∪ c) ≡ (b
∪ c))) |
| 8 | 3, 7 | lbtr 139 |
. . . . . 6
b ≤ ((a ≡ b)⊥ ∪ ((a ∪ c)
≡ (b ∪ c))) |
| 9 | 2, 8 | le2or 168 |
. . . . 5
(a ∪ b) ≤ (((a
≡ b)⊥ ∪
((a ∪ c) ≡ (b
∪ c))) ∪ ((a ≡ b)⊥ ∪ ((a ∪ c)
≡ (b ∪ c)))) |
| 10 | | oridm 110 |
. . . . 5
(((a ≡ b)⊥ ∪ ((a ∪ c)
≡ (b ∪ c))) ∪ ((a
≡ b)⊥ ∪
((a ∪ c) ≡ (b
∪ c)))) = ((a ≡ b)⊥ ∪ ((a ∪ c)
≡ (b ∪ c))) |
| 11 | 9, 10 | lbtr 139 |
. . . 4
(a ∪ b) ≤ ((a
≡ b)⊥ ∪
((a ∪ c) ≡ (b
∪ c))) |
| 12 | 11 | leror 152 |
. . 3
((a ∪ b) ∪ ((a
∪ c) ≡ (b ∪ c)))
≤ (((a ≡ b)⊥ ∪ ((a ∪ c)
≡ (b ∪ c))) ∪ ((a
∪ c) ≡ (b ∪ c))) |
| 13 | | ka4lemo 228 |
. . 3
((a ∪ b) ∪ ((a
∪ c) ≡ (b ∪ c))) =
1 |
| 14 | | ax-a3 32 |
. . . 4
(((a ≡ b)⊥ ∪ ((a ∪ c)
≡ (b ∪ c))) ∪ ((a
∪ c) ≡ (b ∪ c))) =
((a ≡ b)⊥ ∪ (((a ∪ c)
≡ (b ∪ c)) ∪ ((a
∪ c) ≡ (b ∪ c)))) |
| 15 | | oridm 110 |
. . . . 5
(((a ∪ c) ≡ (b
∪ c)) ∪ ((a ∪ c)
≡ (b ∪ c))) = ((a ∪
c) ≡ (b ∪ c)) |
| 16 | 15 | lor 70 |
. . . 4
((a ≡ b)⊥ ∪ (((a ∪ c)
≡ (b ∪ c)) ∪ ((a
∪ c) ≡ (b ∪ c)))) =
((a ≡ b)⊥ ∪ ((a ∪ c)
≡ (b ∪ c))) |
| 17 | 14, 16 | ax-r2 36 |
. . 3
(((a ≡ b)⊥ ∪ ((a ∪ c)
≡ (b ∪ c))) ∪ ((a
∪ c) ≡ (b ∪ c))) =
((a ≡ b)⊥ ∪ ((a ∪ c)
≡ (b ∪ c))) |
| 18 | 12, 13, 17 | le3tr2 141 |
. 2
1 ≤ ((a ≡ b)⊥ ∪ ((a ∪ c)
≡ (b ∪ c))) |
| 19 | 1, 18 | lebi 145 |
1
((a ≡ b)⊥ ∪ ((a ∪ c)
≡ (b ∪ c))) = 1 |