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| Mirrors > Home > ILE Home > Th. List > exdistrv | GIF version | ||
| Description: Distribute a pair of existential quantifiers (over disjoint variables) over a conjunction. Combination of 19.41v 1949 and 19.42v 1953. For a version with fewer disjoint variable conditions but requiring more axioms, see eeanv 1983. (Contributed by BJ, 30-Sep-2022.) |
| Ref | Expression |
|---|---|
| exdistrv | ⊢ (∃𝑥∃𝑦(𝜑 ∧ 𝜓) ↔ (∃𝑥𝜑 ∧ ∃𝑦𝜓)) |
| Step | Hyp | Ref | Expression |
|---|---|---|---|
| 1 | exdistr 1956 | . 2 ⊢ (∃𝑥∃𝑦(𝜑 ∧ 𝜓) ↔ ∃𝑥(𝜑 ∧ ∃𝑦𝜓)) | |
| 2 | 19.41v 1949 | . 2 ⊢ (∃𝑥(𝜑 ∧ ∃𝑦𝜓) ↔ (∃𝑥𝜑 ∧ ∃𝑦𝜓)) | |
| 3 | 1, 2 | bitri 184 | 1 ⊢ (∃𝑥∃𝑦(𝜑 ∧ 𝜓) ↔ (∃𝑥𝜑 ∧ ∃𝑦𝜓)) |
| Colors of variables: wff set class |
| Syntax hints: ∧ wa 104 ↔ wb 105 ∃wex 1538 |
| This theorem was proved from axioms: ax-mp 5 ax-1 6 ax-2 7 ax-ia1 106 ax-ia2 107 ax-ia3 108 ax-5 1493 ax-gen 1495 ax-ie1 1539 ax-ie2 1540 ax-4 1556 ax-17 1572 ax-ial 1580 |
| This theorem depends on definitions: df-bi 117 |
| This theorem is referenced by: prodmodc 12097 txbasval 14949 |
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