Theorem necon3bbid 2460

Description: Deduction from equality to inequality. (Contributed by NM, 2-Jun-2007.)

Hypothesis

Ref	Expression
necon3bbid.1	⊢ (𝜑 → (𝜓 ↔ 𝐴 = 𝐵))

Assertion

Ref	Expression
necon3bbid	⊢ (𝜑 → (¬ 𝜓 ↔ 𝐴 ≠ 𝐵))

Proof of Theorem necon3bbid

Step	Hyp	Ref	Expression
1		necon3bbid.1	. . . 4 ⊢ (𝜑 → (𝜓 ↔ 𝐴 = 𝐵))
2	1	bicomd 141	. . 3 ⊢ (𝜑 → (𝐴 = 𝐵 ↔ 𝜓))
3	2	necon3abid 2459	. 2 ⊢ (𝜑 → (𝐴 ≠ 𝐵 ↔ ¬ 𝜓))
4	3	bicomd 141	1 ⊢ (𝜑 → (¬ 𝜓 ↔ 𝐴 ≠ 𝐵))

This proof depends on syntax axioms:  ¬ wn 3   → wi 4   ↔ wb 105   = wceq 1402   ≠ wne 2420

This proof depends on axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-ia1 106  ax-ia2 107  ax-ia3 108  ax-in1 623  ax-in2 624

This proof depends on definitions:  df-bi 117  df-ne 2421

This theorem is used by:  necon3bid  2461  eldifsn  3841  suppimacnvfn  6486  prmrp  12943  4sqlem17  13209  nzrunit  14579  lgsne0  16328  2sqlem7  16411