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| Mirrors > Home > ILE Home > Th. List > sbequ12a | GIF version | ||
| Description: An equality theorem for substitution. (Contributed by NM, 5-Aug-1993.) |
| Ref | Expression |
|---|---|
| sbequ12a | ⊢ (𝑥 = 𝑦 → ([𝑦 / 𝑥]𝜑 ↔ [𝑥 / 𝑦]𝜑)) |
| Step | Hyp | Ref | Expression |
|---|---|---|---|
| 1 | sbequ12 1795 | . 2 ⊢ (𝑥 = 𝑦 → (𝜑 ↔ [𝑦 / 𝑥]𝜑)) | |
| 2 | sbequ12 1795 | . . 3 ⊢ (𝑦 = 𝑥 → (𝜑 ↔ [𝑥 / 𝑦]𝜑)) | |
| 3 | 2 | equcoms 1732 | . 2 ⊢ (𝑥 = 𝑦 → (𝜑 ↔ [𝑥 / 𝑦]𝜑)) |
| 4 | 1, 3 | bitr3d 190 | 1 ⊢ (𝑥 = 𝑦 → ([𝑦 / 𝑥]𝜑 ↔ [𝑥 / 𝑦]𝜑)) |
| Colors of variables: wff set class |
| Syntax hints: → wi 4 ↔ wb 105 [wsb 1786 |
| This theorem was proved from axioms: ax-mp 5 ax-1 6 ax-2 7 ax-ia1 106 ax-ia2 107 ax-ia3 108 ax-gen 1473 ax-ie1 1517 ax-ie2 1518 ax-8 1528 ax-4 1534 ax-17 1550 ax-i9 1554 |
| This theorem depends on definitions: df-bi 117 df-sb 1787 |
| This theorem is referenced by: (None) |
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