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Theorem truxorfal 1410
Description: A identity. (Contributed by David A. Wheeler, 2-Mar-2018.)
Assertion
Ref Expression
truxorfal ((⊤ ⊻ ⊥) ↔ ⊤)

Proof of Theorem truxorfal
StepHypRef Expression
1 df-xor 1366 . 2 ((⊤ ⊻ ⊥) ↔ ((⊤ ∨ ⊥) ∧ ¬ (⊤ ∧ ⊥)))
2 truorfal 1396 . . 3 ((⊤ ∨ ⊥) ↔ ⊤)
3 notfal 1404 . . . 4 (¬ ⊥ ↔ ⊤)
4 truan 1360 . . . 4 ((⊤ ∧ ⊥) ↔ ⊥)
53, 4xchnxbir 671 . . 3 (¬ (⊤ ∧ ⊥) ↔ ⊤)
62, 5anbi12i 456 . 2 (((⊤ ∨ ⊥) ∧ ¬ (⊤ ∧ ⊥)) ↔ (⊤ ∧ ⊤))
7 anidm 394 . 2 ((⊤ ∧ ⊤) ↔ ⊤)
81, 6, 73bitri 205 1 ((⊤ ⊻ ⊥) ↔ ⊤)
Colors of variables: wff set class
Syntax hints:  ¬ wn 3  wa 103  wb 104  wo 698  wtru 1344  wfal 1348  wxo 1365
This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-ia1 105  ax-ia2 106  ax-ia3 107  ax-in1 604  ax-in2 605  ax-io 699
This theorem depends on definitions:  df-bi 116  df-tru 1346  df-fal 1349  df-xor 1366
This theorem is referenced by: (None)
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