Theorem falxortru 1400

Description: A ⊻ identity. (Contributed by David A. Wheeler, 2-Mar-2018.)

Assertion

Ref	Expression
falxortru	⊢ ((⊥ ⊻ ⊤) ↔ ⊤)

Proof of Theorem falxortru

Step	Hyp	Ref	Expression
1		df-xor 1355	. 2 ⊢ ((⊥ ⊻ ⊤) ↔ ((⊥ ∨ ⊤) ∧ ¬ (⊥ ∧ ⊤)))
2		falortru 1386	. . 3 ⊢ ((⊥ ∨ ⊤) ↔ ⊤)
3		notfal 1393	. . . 4 ⊢ (¬ ⊥ ↔ ⊤)
4		falantru 1382	. . . 4 ⊢ ((⊥ ∧ ⊤) ↔ ⊥)
5	3, 4	xchnxbir 671	. . 3 ⊢ (¬ (⊥ ∧ ⊤) ↔ ⊤)
6	2, 5	anbi12i 456	. 2 ⊢ (((⊥ ∨ ⊤) ∧ ¬ (⊥ ∧ ⊤)) ↔ (⊤ ∧ ⊤))
7		anidm 394	. 2 ⊢ ((⊤ ∧ ⊤) ↔ ⊤)
8	1, 6, 7	3bitri 205	1 ⊢ ((⊥ ⊻ ⊤) ↔ ⊤)

Syntax hints:  ¬ wn 3   ∧ wa 103   ↔ wb 104   ∨ wo 698  ⊤wtru 1333  ⊥wfal 1337   ⊻ wxo 1354

This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-ia1 105  ax-ia2 106  ax-ia3 107  ax-in1 604  ax-in2 605  ax-io 699

This theorem depends on definitions:  df-bi 116  df-tru 1335  df-fal 1338  df-xor 1355

This theorem is referenced by: (None)