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| Mirrors > Home > MPE Home > Th. List > equsexh | Structured version Visualization version GIF version | ||
| Description: An equivalence related to implicit substitution. Usage of this theorem is discouraged because it depends on ax-13 2404. See equsexhv 2327 for a version with a disjoint variable condition which does not require ax-13 2404. (Contributed by NM, 5-Aug-1993.) (New usage is discouraged.) |
| Ref | Expression |
|---|---|
| equsalh.1 | ⊢ (𝜓 → ∀𝑥𝜓) |
| equsalh.2 | ⊢ (𝑥 = 𝑦 → (𝜑 ↔ 𝜓)) |
| Ref | Expression |
|---|---|
| equsexh | ⊢ (∃𝑥(𝑥 = 𝑦 ∧ 𝜑) ↔ 𝜓) |
| Step | Hyp | Ref | Expression |
|---|---|---|---|
| 1 | equsalh.1 | . . 3 ⊢ (𝜓 → ∀𝑥𝜓) | |
| 2 | 1 | nf5i 2181 | . 2 ⊢ Ⅎ𝑥𝜓 |
| 3 | equsalh.2 | . 2 ⊢ (𝑥 = 𝑦 → (𝜑 ↔ 𝜓)) | |
| 4 | 2, 3 | equsex 2450 | 1 ⊢ (∃𝑥(𝑥 = 𝑦 ∧ 𝜑) ↔ 𝜓) |
| Colors of variables: wff setvar class |
| Syntax hints: → wi 4 ↔ wb 208 ∧ wa 399 ∀wal 1559 ∃wex 1800 |
| This theorem was proved from axioms: ax-mp 5 ax-1 6 ax-2 7 ax-3 8 ax-gen 1816 ax-4 1830 ax-5 1931 ax-6 1988 ax-7 2029 ax-10 2176 ax-12 2213 ax-13 2404 |
| This theorem depends on definitions: df-bi 209 df-an 400 df-ex 1801 df-nf 1805 |
| This theorem is referenced by: (None) |
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