Metamath Proof Explorer |
< Previous
Next >
Nearby theorems |
||
Mirrors > Home > MPE Home > Th. List > nf5i | Structured version Visualization version GIF version |
Description: Deduce that 𝑥 is not free in 𝜑 from the definition. (Contributed by Mario Carneiro, 11-Aug-2016.) |
Ref | Expression |
---|---|
nf5i.1 | ⊢ (𝜑 → ∀𝑥𝜑) |
Ref | Expression |
---|---|
nf5i | ⊢ Ⅎ𝑥𝜑 |
Step | Hyp | Ref | Expression |
---|---|---|---|
1 | nf5-1 2149 | . 2 ⊢ (∀𝑥(𝜑 → ∀𝑥𝜑) → Ⅎ𝑥𝜑) | |
2 | nf5i.1 | . 2 ⊢ (𝜑 → ∀𝑥𝜑) | |
3 | 1, 2 | mpg 1798 | 1 ⊢ Ⅎ𝑥𝜑 |
Colors of variables: wff setvar class |
Syntax hints: → wi 4 ∀wal 1535 Ⅎwnf 1784 |
This theorem was proved from axioms: ax-mp 5 ax-1 6 ax-2 7 ax-3 8 ax-gen 1796 ax-4 1810 ax-10 2145 |
This theorem depends on definitions: df-bi 209 df-ex 1781 df-nf 1785 |
This theorem is referenced by: nfnaew 2153 nfe1 2154 sbh 2273 nf5di 2293 19.9h 2294 19.21h 2295 19.23h 2296 exlimih 2297 exlimdh 2298 equsalhw 2299 equsexhv 2300 hban 2308 hb3an 2309 nfal 2342 hbex 2344 hbsbw 2351 cbv3hv 2360 dvelimhw 2366 cbv3h 2424 equsalh 2442 equsexh 2443 nfae 2455 axc16i 2458 dvelimh 2472 nfs1 2527 hbsb 2567 sb7h 2569 nfsab1OLD 2811 nfsab 2814 nfsabg 2815 cleqh 2938 nfcii 2967 nfcri 2973 bnj596 32019 bnj1146 32065 bnj1379 32104 bnj1464 32118 bnj1468 32120 bnj605 32181 bnj607 32190 bnj916 32207 bnj964 32217 bnj981 32224 bnj983 32225 bnj1014 32235 bnj1123 32260 bnj1373 32304 bnj1417 32315 bnj1445 32318 bnj1463 32329 bnj1497 32334 bj-cbv3hv2 34119 bj-equsalhv 34130 bj-nfs1v 34137 bj-nfsab1 34140 wl-nfalv 34767 nfequid-o 36048 nfa1-o 36053 2sb5ndVD 41251 2sb5ndALT 41273 |
Copyright terms: Public domain | W3C validator |